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SCIENCE · INVESTIGATE AND EXPLAIN

Resolve curvature without inventing a neutral gyroperiod

A charged particle moving perpendicular to a uniform stationary magnetic field can change direction without changing speed. For mass m, charge q and field B along +z, define signed rate w=qB/m. Starting at the origin with velocity +1 m/s along x, the supplied path is x=sin(wt)/w and y=[cos(wt)−1]/w for nonzero w. Its initial curvature is toward −y for positive charge and toward +y for negative charge.

Learning outcome: Compare positive, negative and zero charge at the same field. Retain radius/period only when defined, plus exact one-second coordinates. Then double B and predict both radius and period changes before checking.

Starting recap

Use a right-handed coordinate system, oriented surface normal, signed charge/current and declared energy boundary. Separate an entry force from a trajectory, emf from current, and rms from signed average.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

At B=4 mT, q=1 µC and m=2×10⁻⁹ kg, w=2 rad/s, radius .5 m and period π s. After one second, x=sin2/2≈.454649 m and y=(cos2−1)/2≈−.708073 m. Reversing charge reverses y while preserving x and speed.

Open the experiment

Predict

At exactly zero charge in this model, the path is:

Experiment

Compare positive, negative and zero charge at the same field. Retain radius/period only when defined, plus exact one-second coordinates. Then double B and predict both radius and period changes before checking.

Resolve magnetic curvature and the zero-charge branch

Worked teaching model · synthetic values · Fictional mass 2e−9 kg enters at origin with vx 1 m/s, vy 0. Uniform stationary field fills the mathematical plane; no electric field, collisions or gravity. Nonrelativistic path shown only over 1 s; charge zero follows a straight line, not an infinite displayed radius.

Reset keeps your prediction, captures and practice history.

Signed path over one second on common spatial scales

y (m)x (m)00.4999960-0.708073

Spatial axes use the same pixels per physical unit, preserving geometry. 1: charged orbit segment (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Signed path over one second on common spatial scales

charged orbit segment

x (m)y (m)
00
0.0124987-0.000156242
0.0249896-0.00062487
0.0374649-0.00140559
0.0499167-0.00249792
0.0623374-0.00390117
0.0747191-0.00561446
0.0870541-0.00763673
0.0993347-0.00996671
0.111553-0.0126029
0.123702-0.0155438
0.135773-0.0187874
0.14776-0.0223318
0.159654-0.0261746
0.171449-0.0303136
0.183136-0.0347462
0.194709-0.0394695
0.20616-0.0444806
0.217483-0.0497764
0.228669-0.0553536
0.239713-0.0612087
0.250607-0.067338
0.261344-0.0737377
0.271917-0.0804038
0.282321-0.0873322
0.292549-0.0945184
0.302593-0.101958
0.312449-0.109647
0.322109-0.117579
0.331568-0.12575
0.340819-0.134156
0.349858-0.142789
0.358678-0.151647
0.367274-0.160722
0.37564-0.170008
0.383772-0.179502
0.391663-0.189195
0.39931-0.199083
0.406708-0.209158
0.413851-0.219416
0.420735-0.229849
0.427357-0.240451
0.433712-0.251214
0.439795-0.262134
0.445604-0.273202
0.451134-0.284412
0.456382-0.295756
0.461345-0.307228
0.46602-0.318821
0.470403-0.330527
0.474492-0.342339
0.478285-0.354249
0.481779-0.366251
0.484972-0.378336
0.487862-0.390497
0.490447-0.402726
0.492725-0.415016
0.494695-0.42736
0.496356-0.439749
0.497708-0.452175
0.498747-0.464631
0.499476-0.47711
0.499892-0.489603
0.499996-0.502102
0.499787-0.5146
0.499266-0.527089
0.498433-0.53956
0.497288-0.552008
0.495832-0.564422
0.494067-0.576797
0.491993-0.589123
0.489611-0.601394
0.486924-0.613601
0.483932-0.625737
0.480638-0.637795
0.477043-0.649767
0.47315-0.661645
0.468961-0.673422
0.46448-0.68509
0.459708-0.696643
0.454649-0.708073

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Signed curvature angular rate parameter2rad/s
Particle speed1m/s
Kinetic energy1e-9J
Straight neutral branch0flag
Orbit radius0.5m
Gyroperiod3.14159s
x after one second0.454649m
y after one second-0.708073m
Magnetic work over displayed path0J

The sign of charge reverses curvature without changing speed or kinetic energy.

With B along +z, positive q curves initially toward −y. Let w=qB/m; x=sin(wt)/w and y=[cos(wt)−1]/w satisfy the initial velocity and Lorentz force. Radius is mv/(|q|B), period 2pi m/(|q|B). Speed independence of this period is restricted to the uniform nonrelativistic model; magnetic force is perpendicular to velocity and does no work.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

The sign of charge reverses curvature without changing speed or kinetic energy.

With B along +z, positive q curves initially toward −y. Let w=qB/m; x=sin(wt)/w and y=[cos(wt)−1]/w satisfy the initial velocity and Lorentz force. Radius is mv/(|q|B), period 2pi m/(|q|B). Speed independence of this period is restricted to the uniform nonrelativistic model; magnetic force is perpendicular to velocity and does no work.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Define vectors, source and system boundary

A charged particle moving perpendicular to a uniform stationary magnetic field can change direction without changing speed. For mass m, charge q and field B along +z, define signed rate w=qB/m. Starting at the origin with velocity +1 m/s along x, the supplied path is x=sin(wt)/w and y=[cos(wt)−1]/w for nonzero w. Its initial curvature is toward −y for positive charge and toward +y for negative charge.

Derive the quantitative comparison

The radius is mv/(|q|B) and period is 2πm/(|q|B). Charge sign sets sense of circulation, not a negative physical radius. With fixed mass and charge the nonrelativistic period does not depend on speed, whereas radius does. These conclusions require the stated uniform field, negligible electric force and low speed; they are not a general claim about every particle instrument or high-energy orbit.

Separate physical evidence from a model extension

The exact neutral case is a different displayed branch: x=t,y=0. Reporting a numerical infinity for radius or period would obscure the fact that there is no circular orbit at all. The graphic uses equal spatial scales and a fixed one-second interval for every recipe. Magnetic work is zero because force is perpendicular to instantaneous velocity, and kinetic energy stays m/2 for this unit-speed packet. The source field is a mathematical plane model, not observed apparatus.

Worked original case

At B=4 mT, q=1 µC and m=2×10⁻⁹ kg, w=2 rad/s, radius .5 m and period π s. After one second, x=sin2/2≈.454649 m and y=(cos2−1)/2≈−.708073 m. Reversing charge reverses y while preserving x and speed.

Investigation

Compare positive, negative and zero charge at the same field. Retain radius/period only when defined, plus exact one-second coordinates. Then double B and predict both radius and period changes before checking.

Changed-case practice

Try the changed case before feedback

For B=2 mT, q=2 µC and the stated mass/speed, find the orbit radius in metres.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and evidence boundary

Original prose and numerical cases checked 30 October 2026 against the relevant primary explanation. All records and diagrams are virtual. No real coil, powered wire, high-field exposure, motor, transformer, mains connection or inductor switching is requested. Retain first predictions, contrasting recipes and independent criterion review; public agreement is not practical certification or demonstrated mastery.

Apply

At exactly zero charge in this model, the path is:

Public practice checks a specific claim. It does not establish independent mastery.

Which independent observation could reject this model rather than merely refit its parameters?

Continue

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