Distinguish a field null from a zero potential
For two positive point charges on a line, fields point away from each source. Between them the contributions oppose; outside them they point in the same direction. Therefore the finite cancellation point lies between the sources, not beyond an endpoint. Source positions themselves are singular and cannot be substituted as candidate nulls.
Learning outcome: Hold separation at 2 m and compare right charges 1,5,9 nC. Predict the direction of null motion before checking. Draw the separate equal-and-opposite midpoint case and use vector arrows and scalar signs to explain its contrasting cancellations.
Starting recap
Use signed charge, common coordinate axes, SI units, vector components and algebraic ratios. Separate a source field from probe force and a fitted parameter from independently tested evidence.
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Try
For a=9 and d=2 m, the field null is x=2/(1+3)=.5 m. Its distances from the sources are .5 and 1.5 m. The source-field magnitudes match because 1/.5²=9/1.5²=4; the potential contributions are both positive.
Open the experimentPredict
At the null between two positive sources, potential relative to infinity is:
Experiment
Hold separation at 2 m and compare right charges 1,5,9 nC. Predict the direction of null motion before checking. Draw the separate equal-and-opposite midpoint case and use vector arrows and scalar signs to explain its contrasting cancellations.
Find a field null without confusing potential cancellation
Worked teaching model · synthetic values · Left source +1 nC at x=0 and right positive source at x=d. One field null lies strictly between them. Compare the midpoint potential of a separately stipulated equal-and-opposite pair; source locations themselves are excluded.
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Same-sign potential along interior segment
Unlike graph quantities rescale independently; read units and values, not screen angles. 1: sum of source potentials (solid). Joined curves show the supplied model, not additional observations.
Equivalent numerical coordinates for Same-sign potential along interior segment
sum of source potentials
| x (m) | potential (V) |
|---|---|
| 0.2 | 69.9032 |
| 0.24 | 62.981 |
| 0.28 | 58.225 |
| 0.32 | 54.8348 |
| 0.36 | 52.3665 |
| 0.4 | 50.555 |
| 0.44 | 49.2325 |
| 0.48 | 48.2884 |
| 0.52 | 47.6471 |
| 0.56 | 47.256 |
| 0.6 | 47.0777 |
| 0.64 | 47.0855 |
| 0.68 | 47.2607 |
| 0.72 | 47.5903 |
| 0.76 | 48.0659 |
| 0.8 | 48.6826 |
| 0.84 | 49.4389 |
| 0.88 | 50.3361 |
| 0.92 | 51.3781 |
| 0.96 | 52.5714 |
| 1 | 53.9253 |
| 1.04 | 55.452 |
| 1.08 | 57.1672 |
| 1.12 | 59.0902 |
| 1.16 | 61.2452 |
| 1.2 | 63.6618 |
| 1.24 | 66.3767 |
| 1.28 | 69.4351 |
| 1.32 | 72.8937 |
| 1.36 | 76.8237 |
| 1.4 | 81.3159 |
| 1.44 | 86.4874 |
| 1.48 | 92.4914 |
| 1.52 | 99.5332 |
| 1.56 | 107.893 |
| 1.6 | 117.962 |
| 1.64 | 130.307 |
| 1.68 | 145.78 |
| 1.72 | 165.717 |
| 1.76 | 192.347 |
| 1.8 | 229.682 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
| Quantity | Value | Unit |
|---|---|---|
| Field-null coordinate | 0.618034 | m |
| Distance from right source | 1.38197 | m |
| Potential at field null | 47.0594 | V |
| Net field at declared null | 0 | N/C |
| Equal-opposite comparison midpoint potential | 0 | V |
| Equal-opposite comparison midpoint field | 17.9751 | N/C |
Zero electric field need not mean zero potential, and zero potential need not mean zero field.
Between positive sources fields oppose: 1/x²=a/(d−x)² gives x=d/(1+sqrt(a)). Both potentials are positive relative to infinity, so their sum cannot vanish. A separate +1/−1 nC pair has zero midpoint potential but reinforcing rightward fields. Cancellation claims must identify vector versus scalar quantity and the source configuration.
Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.
Zero electric field need not mean zero potential, and zero potential need not mean zero field.
Between positive sources fields oppose: 1/x²=a/(d−x)² gives x=d/(1+sqrt(a)). Both potentials are positive relative to infinity, so their sum cannot vanish. A separate +1/−1 nC pair has zero midpoint potential but reinforcing rightward fields. Cancellation claims must identify vector versus scalar quantity and the source configuration.
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