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SCIENCE · INVESTIGATE AND EXPLAIN

Distinguish grazing refraction from total internal reflection

Refraction changes direction when a wave crosses a stationary boundary between different propagation speeds. For light, index n is the vacuum speed divided by the medium phase speed. Snell law is n1 sinθ1=n2 sinθ2, with both angles measured from the normal. The boundary preserves frequency; changing speed therefore changes wavelength rather than requiring the source to change its oscillation rate.

Learning outcome: Compare a=.75,1,1.25 for each allowed second index. Record the branch before calculating a transmitted angle. Explain why a field-amplitude or power claim cannot be inferred solely from a geometric direction drawing.

Starting recap

Use normal-based angles, signed conjugate distances and explicit optical-path/reflection phases. Separate geometric direction, amplitude and energy; preserve focal and critical boundaries.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

For n1=1.5,n2=1, the critical sine is 2/3 and critical angle is about 41.8103°. At a=.75, the transmitted angle is arcsin(.75)≈48.5904° while incidence is arcsin(.5)=30°. At a=1 the transmitted angle is exactly 90°; at a=1.25 no propagating transmitted angle is listed.

Open the experiment

Predict

Exactly at the critical angle, the geometric transmitted direction is:

Experiment

Compare a=.75,1,1.25 for each allowed second index. Record the branch before calculating a transmitted angle. Explain why a field-amplitude or power claim cannot be inferred solely from a geometric direction drawing.

Keep grazing transmission separate from total reflection

Worked teaching model · synthetic values · Light crosses from index1.5 toward the second medium. sin(theta_i)=a*n2/1.5, so a is the candidate transmitted sine. Exactly a=1 gives grazing refraction; a>1 has no propagating transmitted ray in geometric optics. No Fresnel power or evanescent-field amplitude calculation.

Reset keeps your prediction, captures and practice history.

Geometric directions at the index boundary

y (common length unit)x (common length unit)-110.7453560

Spatial axes use the same pixels per physical unit, preserving geometry. 1: incident ray toward interface (solid).2: reflected ray (dashed).3: interface (dotted).4: grazing transmitted geometric direction (dotted). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Geometric directions at the index boundary

incident ray toward interface

x (common length unit)y (common length unit)
-0.6666670.745356
00

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

reflected ray

x (common length unit)y (common length unit)
00
0.6666670.745356

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

interface

x (common length unit)y (common length unit)
-10
10

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

grazing transmitted geometric direction

x (common length unit)y (common length unit)
00
10

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Incident angle from normal41.8103degrees
Critical incident angle41.8103degrees
Candidate transmitted sine1ratio
Propagating transmitted ray exists1flag
Grazing boundary1flag
Total internal reflection branch0flag
Transmitted angle from normal90degrees

Exactly at the critical angle the refracted direction is tangent, not a downward-propagating bulk ray.

n1 sin(theta_i)=n2 sin(theta_t), with all angles from the normal. The chosen control a is sin(theta_t) if a propagating geometric ray exists. At a=1 the refracted angle is90 degrees; above it no real angle is reported. This plot does not assign Fresnel power fractions or an evanescent-field amplitude. For a parallel slab with equal exterior media the final direction returns to the initial direction but a lateral displacement can remain.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

Exactly at the critical angle the refracted direction is tangent, not a downward-propagating bulk ray.

n1 sin(theta_i)=n2 sin(theta_t), with all angles from the normal. The chosen control a is sin(theta_t) if a propagating geometric ray exists. At a=1 the refracted angle is90 degrees; above it no real angle is reported. This plot does not assign Fresnel power fractions or an evanescent-field amplitude. For a parallel slab with equal exterior media the final direction returns to the initial direction but a lateral displacement can remain.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Define the optical model

Refraction changes direction when a wave crosses a stationary boundary between different propagation speeds. For light, index n is the vacuum speed divided by the medium phase speed. Snell law is n1 sinθ1=n2 sinθ2, with both angles measured from the normal. The boundary preserves frequency; changing speed therefore changes wavelength rather than requiring the source to change its oscillation rate.

Build the signed account

Here n1=1.5 and the interactive second index is 1 or 1.1. The control a sets sinθ1=a n2/n1, so the candidate transmitted sine is exactly a. At a below one there is a real transmitted angle. At a=1 the direction is tangent to the boundary: this is the critical angle. Above one there is no propagating transmitted geometric ray. The model does not invent arcsin of a value above one or assign a finite transmitted direction to that branch.

Test the limits and evidence

Total internal reflection requires incidence from higher to lower index and an angle above critical. Exactly critical is a boundary case, not an ordinary downward-transmitted ray. Fresnel reflected/transmitted powers and evanescent fields require additional wave analysis and are not computed by these arrows. In a parallel-sided slab with identical exterior media, two refractions restore the external direction but can leave lateral displacement. This virtual classification is not an optical-fiber construction or exposure procedure.

Worked original case

For n1=1.5,n2=1, the critical sine is 2/3 and critical angle is about 41.8103°. At a=.75, the transmitted angle is arcsin(.75)≈48.5904° while incidence is arcsin(.5)=30°. At a=1 the transmitted angle is exactly 90°; at a=1.25 no propagating transmitted angle is listed.

Predict and investigate

Compare a=.75,1,1.25 for each allowed second index. Record the branch before calculating a transmitted angle. Explain why a field-amplitude or power claim cannot be inferred solely from a geometric direction drawing.

Changed-case practice

Try the changed case before feedback

Light goes from n=1.5 toward n=1.2. Find the sine of its critical incident angle.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original text and numerical cases checked 30 October 2026 against the primary explanation. All optical activity is virtual: no laser, sunlight viewing, eye exposure, physical lens alignment or device construction is requested. Public feedback is not independent mastery; retain first calculations, critique and changed-case evidence in the separate course workspace.

Apply

Exactly at the critical angle, the geometric transmitted direction is:

Public practice checks a specific claim. It does not establish independent mastery.

Which independent observation would reject the approximation, sign convention or calibration premise rather than merely refit it?

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

Skipping retains experiments and awards no mastery.

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