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SCIENCE · INVESTIGATE AND EXPLAIN

Close a dielectric-change energy ledger under two constraints

A dielectric can polarize without conducting free charge across the gap. In an ideal linear material filling fixed parallel plates, capacitance increases from C0 to κC0. Before applying an energy formula, decide whether free plate charge or source voltage is held fixed. Both cannot generally remain fixed while capacitance changes.

Learning outcome: Compare isolated and connected constraints for κ=1,3,5. Retain source work and mechanical work separately instead of calling a stored-energy decrease unexplained loss. Explain why κ=1 is an exact no-change boundary.

Starting recap

Use charge continuity, energy per charge, consistent SI units and an explicit circuit topology. Exponential responses are supplied algebraic models; initial state, source constraint and measurement loading must be declared.

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Try

Initially C0=2 µF and V0=6 V give Q0=12 µC and U0=36 µJ. For κ=3 isolated, voltage becomes 2 V and U=12 µJ, with external mechanical work −24 µJ. Connected, Q=36 µC and U=108 µJ; source work is 144 µJ and mechanical work −72 µJ.

Open the experiment

Predict

At fixed source voltage while capacitance increases, source work:

Experiment

Compare isolated and connected constraints for κ=1,3,5. Retain source work and mechanical work separately instead of calling a stored-energy decrease unexplained loss. Explain why κ=1 is an exact no-change boundary.

Track source and mechanical work when capacitance changes

Worked teaching model · synthetic values · Initial vacuum capacitance 2 µF at 6 V. Final dielectric fills the ideal gap, giving C=kappa C0. Lossless quasistatic change, fixed geometry, no dissipative effects. Isolated means fixed free plate charge; connected means maintained 6 V. Virtual only.

Reset keeps your prediction, captures and practice history.

Stored energy under the selected constraint

stored energy (J)relative permittivity050.0000360

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: fixed free charge (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Stored energy under the selected constraint

fixed free charge

relative permittivitystored energy (J)
10.000036
1.10.0000327273
1.20.00003
1.30.0000276923
1.40.0000257143
1.50.000024
1.60.0000225
1.70.0000211765
1.80.00002
1.90.0000189474
20.000018
2.10.0000171429
2.20.0000163636
2.30.0000156522
2.40.000015
2.50.0000144
2.60.0000138462
2.70.0000133333
2.80.0000128571
2.90.0000124138
30.000012
3.10.0000116129
3.20.00001125
3.30.0000109091
3.40.0000105882
3.50.0000102857
3.60.00001
3.70.00000972973
3.80.00000947368
3.90.00000923077
40.000009
4.10.00000878049
4.20.00000857143
4.30.00000837209
4.40.00000818182
4.50.000008
4.60.00000782609
4.70.00000765957
4.80.0000075
4.90.00000734694
50.0000072

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Initial stored energy0.000036J
Final capacitance0.000006F
Final voltage2V
Final free plate charge0.000012C
Final stored energy0.000012J
Stored-energy change-0.000024J
Ideal source work0J
External mechanical work on capacitor system-0.000024J
Energy residual0J

At fixed charge, increased capacitance reduces voltage and stored energy.

Use Q=CV and U=Q²/(2C)=CV²/2, but hold the correct quantity fixed. In the quasistatic lossless convention Delta U=Wsource+Wexternal-mechanical. Negative external mechanical work means the electric system can deliver mechanical energy to the agent. It is not a lost-energy discrepancy. Actual friction, leakage and fast motion are excluded, so no handling protocol follows.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

At fixed charge, increased capacitance reduces voltage and stored energy.

Use Q=CV and U=Q²/(2C)=CV²/2, but hold the correct quantity fixed. In the quasistatic lossless convention Delta U=Wsource+Wexternal-mechanical. Negative external mechanical work means the electric system can deliver mechanical energy to the agent. It is not a lost-energy discrepancy. Actual friction, leakage and fast motion are excluded, so no handling protocol follows.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Define topology, recipient and initial conditions

A dielectric can polarize without conducting free charge across the gap. In an ideal linear material filling fixed parallel plates, capacitance increases from C0 to κC0. Before applying an energy formula, decide whether free plate charge or source voltage is held fixed. Both cannot generally remain fixed while capacitance changes.

Derive the quantitative response

For an isolated charged capacitor, Q stays at C0V0, voltage becomes V0/κ and stored energy becomes U0/κ. For a capacitor connected to a maintained V0 source, voltage stays fixed, charge becomes κQ0 and energy becomes κU0. The connected source does work V0(Qfinal−Qinitial)=2U0(κ−1), which exceeds the stored-energy increase U0(κ−1). That is not a conservation failure.

Check evidence and the limits of the model

Under the explicitly lossless quasistatic convention, ΔU=Wsource+Wexternal-mechanical. In either case the external agent can extract mechanical energy as the dielectric is drawn in, so its work on the capacitor system is negative. Actual friction, finite insertion speed, leakage and material loss would require additional terms. The calculations are a virtual thermodynamic-style system account, not instructions for inserting material into an energized or charged device.

Worked original case

Initially C0=2 µF and V0=6 V give Q0=12 µC and U0=36 µJ. For κ=3 isolated, voltage becomes 2 V and U=12 µJ, with external mechanical work −24 µJ. Connected, Q=36 µC and U=108 µJ; source work is 144 µJ and mechanical work −72 µJ.

Investigation

Compare isolated and connected constraints for κ=1,3,5. Retain source work and mechanical work separately instead of calling a stored-energy decrease unexplained loss. Explain why κ=1 is an exact no-change boundary.

Changed-case practice

Try the changed case before feedback

An isolated capacitor starts with 48 µJ stored energy. Its capacitance triples without charge exchange. Find final stored energy in µJ.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and evidence boundary

Original numerical cases and prose checked 30 October 2026 against the relevant primary explanation. All records are synthetic and all diagrams mathematical. No practical wiring, battery testing, capacitor handling, mains measurement or equipment safety rating is requested. Public feedback does not verify independent mastery; retain first predictions, contrasting recipes and criterion-based critique in the separate course evidence workspace.

The molecular polarization distinction is also checked against University Physics, dielectric model. The quasistatic source/mechanical ledger here is an original algebraic energy-balance derivation, not a copied apparatus exercise.

Apply

At fixed source voltage while capacitance increases, source work:

Public practice checks a specific claim. It does not establish independent mastery.

Which independent observation could reject this model rather than merely refit its parameters?

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