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SCIENCE · INVESTIGATE AND EXPLAIN

Keep source and observer velocities in the medium frame

Sound fronts move through a medium. In this model still air carries waves toward +x at 340 m/s, the source is left of the observer and the source frequency is 500 Hz. Positive source velocity moves toward the observer; positive observer velocity moves away along the same direction. Keeping these signs explicit is more reliable than choosing a formula sign from an unlabeled word such as approaching.

Learning outcome: Compare (vs,vo)=(20,0),(0,−20),(20,20) and (−20,0) m/s. Predict whether each shift is upward, absent or downward. Retain wavelength and front-crossing speed separately before forming the observed frequency.

Starting recap

Separate local oscillation from propagation, amplitude from its square, and a calibration fit from a fresh prediction. Use declared phase, medium frame and boundary conditions.

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Try

For vs=20 m/s and vo=0, wavelength is (340−20)/500=.64 m and observed frequency is 531.25 Hz. If instead the source is stationary and the observer moves at −20 m/s, frequency is 500(360/340)≈529.412 Hz despite the same 20 m/s closing speed.

Open the experiment

Predict

Which pair gives no Doppler shift under the stated collinear still-air model?

Experiment

Compare (vs,vo)=(20,0),(0,−20),(20,20) and (−20,0) m/s. Predict whether each shift is upward, absent or downward. Retain wavelength and front-crossing speed separately before forming the observed frequency.

Keep both velocities in the medium frame

Worked teaching model · synthetic values · Source is left of observer; waves travel +x through still uniform air at 340 m/s. Source emits 500 Hz in this classical medium model. Positive observer velocity moves away along propagation. Snapshot before crossing; all speeds subsonic. Not a light or relativistic Doppler law.

Reset keeps your prediction, captures and practice history.

Received frequency versus observer medium-frame velocity

received frequency (Hz)observer velocity +x (m/s)-4040593.750

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: fixed source velocity (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Received frequency versus observer medium-frame velocity

fixed source velocity

observer velocity +x (m/s)received frequency (Hz)
-40593.75
-39592.188
-38590.625
-37589.063
-36587.5
-35585.938
-34584.375
-33582.813
-32581.25
-31579.688
-30578.125
-29576.563
-28575
-27573.438
-26571.875
-25570.313
-24568.75
-23567.188
-22565.625
-21564.063
-20562.5
-19560.938
-18559.375
-17557.813
-16556.25
-15554.688
-14553.125
-13551.563
-12550
-11548.438
-10546.875
-9545.313
-8543.75
-7542.188
-6540.625
-5539.063
-4537.5
-3535.938
-2534.375
-1532.813
0531.25
1529.688
2528.125
3526.563
4525
5523.438
6521.875
7520.313
8518.75
9517.188
10515.625
11514.063
12512.5
13510.938
14509.375
15507.813
16506.25
17504.688
18503.125
19501.563
20500
21498.438
22496.875
23495.313
24493.75
25492.188
26490.625
27489.063
28487.5
29485.938
30484.375
31482.813
32481.25
33479.688
34478.125
35476.563
36475
37473.438
38471.875
39470.313
40468.75

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Ahead-of-source wavelength0.64m
Received frequency531.25Hz
Observed-minus-source frequency31.25Hz
Wave speed relative to observer340m/s
Source-observer relative velocity20m/s

Source motion changes the wavelength; observer motion changes the rate of crossing those fronts.

Successive fronts are emitted one source period apart while the source advances vs/fs, so lambda=(c−vs)/fs ahead of it. The observer crosses fronts at relative speed c−vo, giving fobs=fs(c−vo)/(c−vs). Equal source and observer velocities cancel the shift in this collinear arrangement. Equal relative velocities alone do not generally give equal shifts when their separate medium-frame velocities differ. A moving medium requires transforming both velocities consistently; this formula is not the relativistic light result.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

Source motion changes the wavelength; observer motion changes the rate of crossing those fronts.

Successive fronts are emitted one source period apart while the source advances vs/fs, so lambda=(c−vs)/fs ahead of it. The observer crosses fronts at relative speed c−vo, giving fobs=fs(c−vo)/(c−vs). Equal source and observer velocities cancel the shift in this collinear arrangement. Equal relative velocities alone do not generally give equal shifts when their separate medium-frame velocities differ. A moving medium requires transforming both velocities consistently; this formula is not the relativistic light result.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Define the observable

Sound fronts move through a medium. In this model still air carries waves toward +x at 340 m/s, the source is left of the observer and the source frequency is 500 Hz. Positive source velocity moves toward the observer; positive observer velocity moves away along the same direction. Keeping these signs explicit is more reliable than choosing a formula sign from an unlabeled word such as approaching.

Build the bounded model

During one source period the source advances vs/fs, so successive forward fronts are separated by λ=(c−vs)/fs. The observer crosses them at speed c−vo relative to the fronts. Thus fobs=fs(c−vo)/(c−vs). Source motion changes front spacing, whereas observer motion changes the rate of crossing that spacing. These are distinct medium-frame effects even when the source-observer relative speed happens to match another scenario.

Interpret the evidence

When source and observer have the same velocity, their collinear frequency ratio is one. But the same relative velocity with different individual medium-frame velocities generally produces different ratios. A moving air mass requires transforming both velocities consistently; the propagation speed here is measured relative to the medium. The bounded speeds stay far below c, and no sonic shock, crossing event or relativistic light effect is modeled. This is a silent calculation, not a moving-vehicle experiment.

Worked original case

For vs=20 m/s and vo=0, wavelength is (340−20)/500=.64 m and observed frequency is 531.25 Hz. If instead the source is stationary and the observer moves at −20 m/s, frequency is 500(360/340)≈529.412 Hz despite the same 20 m/s closing speed.

Predict and investigate

Compare (vs,vo)=(20,0),(0,−20),(20,20) and (−20,0) m/s. Predict whether each shift is upward, absent or downward. Retain wavelength and front-crossing speed separately before forming the observed frequency.

Changed-case practice

Try the changed case before feedback

For vs=0 and vo=+34 m/s in air with c=340 m/s and source frequency 500 Hz, find the observed frequency in Hz.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original prose and cases checked 30 October 2026 against the primary source. These are silent, synthetic wave models: no sound playback, exposure prescription, hearing test or physical apparatus is requested. A correct public number is not independent mastery; retain first explanations and a changed-case review in the course evidence workspace.

Apply

Which pair gives no Doppler shift under the stated collinear still-air model?

Public practice checks a specific claim. It does not establish independent mastery.

Which fresh observation separates a failed physical model from a fitted calibration parameter?

Continue

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