Update an occupancy claim after repeated nondetection
An occupied site may produce a nondetection because organisms are cryptic, inactive or outside the sampled portion. Occupancy concerns whether a site is used or contains the species under a defined period and scale; detection concerns the observation process conditional on that state. Treating every zero as absence confounds these two quantities.
Learning outcome: Compare one and four visits at p=0.2 and p=0.8. Separate conditional detection from marginal all-zero probability, and describe one real condition violating independent visits.
Starting recap
Separate target population, sampling frame, inclusion probability, detection and ecological state. Identify the quantity and assumptions before interpreting a corrected estimate.
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Try
At p=0.4 and three visits, an occupied site is missed with probability 0.6³=0.216. Marginal all-zero probability is 0.4+0.6×0.216=0.5296. Conditional occupancy is 0.1296/0.5296≈0.2447, not zero.
Open the experimentPredict
Do three nondetections prove absence when detection is imperfect?
Experiment
Compare one and four visits at p=0.2 and p=0.8. Separate conditional detection from marginal all-zero probability, and describe one real condition violating independent visits.
Interpret repeated nondetection under explicit assumptions
Worked teaching model · synthetic values · Assigned prior occupancy 0.6; constant independent conditional detection p, no false positives, site occupancy closed across visits. P(occupied|allzero)=0.6(1−p)^k/[0.4+0.6(1−p)^k]. This is a stipulated probability exercise, not an occupancy model fitted to data.
Reset keeps your prediction, captures and practice history.
| Quantity | Value | Unit |
|---|---|---|
| Detection at least once if occupied | 0.784 | probability |
| All-zero probability if occupied | 0.216 | probability |
| Marginal all-zero probability | 0.5296 | probability |
| Occupancy probability after all zero | 0.244713 | probability |
Nondetection updates an occupancy claim but does not automatically prove absence.
Repeated visits require closure and a defensible conditional detection model. Heterogeneity, correlated visits and false positives need richer designs; this example does not estimate either p or occupancy from observations.
Predict, change one control, and save contrasting captures. Reconstruct the balance with units; then explain a process the ledger deliberately leaves out. Display precision is not measurement precision.
Nondetection updates an occupancy claim but does not automatically prove absence.
Repeated visits require closure and a defensible conditional detection model. Heterogeneity, correlated visits and false positives need richer designs; this example does not estimate either p or occupancy from observations.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
With prior occupancy 0.5, p=0.5 and two visits, compute probability of at least one detection if occupied and occupancy after all zeros.
Continue
Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
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