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SCIENCE · INVESTIGATE AND EXPLAIN

Verify a traveling wave through derivatives and energy flux

The ideal small-slope string equation is ytt = (T/μ) yxx, where T is tension and μ is mass per unit length. It follows by balancing the small difference of transverse tension components on a short string segment. The approximation keeps tension constant and neglects terms beyond the small transverse slope.

Learning outcome: Check the wave equation by two derivatives, compare phase and material velocities and derive the amplitude-squared mean-power scaling.

Starting recap

Derive equations with their initial or boundary conditions, integrate distributed profiles, and check model domains independently of numerical outputs.

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Try

At k = 2 rad/m and A = 0.01 m, ω = 40 rad/s and maximum material speed remains 0.4 m/s. Mean power is again 0.16 W because ω²A² is unchanged, although wavelength is halved.

Open the experiment

Predict

For k = 1 and A = 0.02 in this model, maximum transverse particle speed is:

Experiment

Check the wave equation by two derivatives, compare phase and material velocities and derive the amplitude-squared mean-power scaling.

Verify a traveling solution and its energy flux

Worked teaching model · synthetic values · Ideal taut string tension40 N, mass density.1 kg/m, small transverse slope at most.06. y=A cos(kx−omega t), omega=20k, no dispersion or damping. Average power belongs to this traveling solution, not arbitrary superpositions.

Reset keeps your prediction, captures and practice history.

Small-slope traveling snapshot at t0

transverse displacement (m)position (m)012.566370.02-0.02

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: A cos(kx) (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Small-slope traveling snapshot at t0

A cos(kx)

position (m)transverse displacement (m)
00.02
0.15707960.01975377
0.31415930.01902113
0.47123890.01782013
0.62831850.01618034
0.78539820.01414214
0.94247780.01175571
1.0995570.00907981
1.2566370.00618034
1.4137170.003128689
1.5707961.22465e-18
1.727876-0.003128689
1.884956-0.00618034
2.042035-0.00907981
2.199115-0.01175571
2.356194-0.01414214
2.513274-0.01618034
2.670354-0.01782013
2.827433-0.01902113
2.984513-0.01975377
3.141593-0.02
3.298672-0.01975377
3.455752-0.01902113
3.612832-0.01782013
3.769911-0.01618034
3.926991-0.01414214
4.08407-0.01175571
4.24115-0.00907981
4.39823-0.00618034
4.555309-0.003128689
4.712389-3.67394e-18
4.8694690.003128689
5.0265480.00618034
5.1836280.00907981
5.3407080.01175571
5.4977870.01414214
5.6548670.01618034
5.8119460.01782013
5.9690260.01902113
6.1261060.01975377
6.2831850.02
6.4402650.01975377
6.5973450.01902113
6.7544240.01782013
6.9115040.01618034
7.0685830.01414214
7.2256630.01175571
7.3827430.00907981
7.5398220.00618034
7.6969020.003128689
7.8539826.12323e-18
8.011061-0.003128689
8.168141-0.00618034
8.325221-0.00907981
8.4823-0.01175571
8.63938-0.01414214
8.796459-0.01618034
8.953539-0.01782013
9.110619-0.01902113
9.267698-0.01975377
9.424778-0.02
9.581858-0.01975377
9.738937-0.01902113
9.896017-0.01782013
10.0531-0.01618034
10.21018-0.01414214
10.36726-0.01175571
10.52434-0.00907981
10.68142-0.00618034
10.83849-0.003128689
10.99557-8.57253e-18
11.152650.003128689
11.309730.00618034
11.466810.00907981
11.623890.01175571
11.780970.01414214
11.938050.01618034
12.095130.01782013
12.252210.01902113
12.409290.01975377
12.566370.02

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Phase speed20m/s
Angular frequency20rad/s
Wavelength6.283185m
Maximum transverse particle speed0.4m/s
Maximum slope magnitude0.02ratio
Average traveling-wave power0.16W
Wave-equation coefficient tension over density400m²/s²

The wave equation constrains spatial and temporal derivatives without making material speed equal phase speed.

For y=A cos(kx−omega t), ytt=−omega²y and yxx=−k²y. The string equation ytt=(T/mu)yxx requires omega²=(T/mu)k². Here sqrt(T/mu)=20, while maximum transverse particle speed is omega A. Mean traveling power is mu omega² A² v/2 under the small-slope linear approximation.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

The wave equation constrains spatial and temporal derivatives without making material speed equal phase speed.

For y=A cos(kx−omega t), ytt=−omega²y and yxx=−k²y. The string equation ytt=(T/mu)yxx requires omega²=(T/mu)k². Here sqrt(T/mu)=20, while maximum transverse particle speed is omega A. Mean traveling power is mu omega² A² v/2 under the small-slope linear approximation.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Verify a traveling wave through derivatives and energy flux

The ideal small-slope string equation is ytt = (T/μ) yxx, where T is tension and μ is mass per unit length. It follows by balancing the small difference of transverse tension components on a short string segment. The approximation keeps tension constant and neglects terms beyond the small transverse slope.

For y = A cos(kx − ωt), the second time derivative is −ω²y and the second position derivative is −k²y. Substitution requires ω² = (T/μ)k². With T = 40 N and μ = 0.1 kg/m, phase speed is 20 m/s and ω = 20k.

At k = 1 rad/m and A = 0.02 m, the largest transverse material speed is ωA = 0.4 m/s, much less than the phase speed. Maximum slope is Ak = 0.02. Wave propagation carries a pattern along the string; individual elements oscillate transversely rather than moving along it at 20 m/s.

Mean power in this single traveling harmonic wave is μω²A²v/2. For the same packet it is 0.16 W. Doubling amplitude quadruples mean power within the linear regime. This relation is not an instruction to add intensities of coherent superpositions before accounting for interference and directions.

Changed-case check

Predict before reading the comparison. At k = 2 rad/m and A = 0.01 m, ω = 40 rad/s and maximum material speed remains 0.4 m/s. Mean power is again 0.16 W because ω²A² is unchanged, although wavelength is halved.

Retained investigation

Check the wave equation by two derivatives, compare phase and material velocities and derive the amplitude-squared mean-power scaling. Which assumptions allow the tension and slope linearization to remain valid?

Source and boundary

Primary conceptual reference checked 30 October 2026: OpenStax University Physics Volume 1. All prose, functions and evidence packets are original. Bounded mathematical models do not establish measured apparatus, supervised practical skill, independent learner mastery or institutional credit. No physical loading, liquids, heat or sound exposure is requested.

The energy-flux derivation is supported by OpenStax University Physics 16.4: Energy and power of a wave, checked 30 October 2026.

Apply

For k = 1 and A = 0.02 in this model, maximum transverse particle speed is:

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Which assumptions allow the tension and slope linearization to remain valid?

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