Include the ring area when deriving disk inertia
A disk with radial density cannot be treated as a line of equally weighted radii. An annulus has area 2πr dr, so its mass is that area times local surface density. Omitting the area factor changes both total mass and rotational inertia.
Learning outcome: Normalize the density, derive mass and inertia from separate ring integrals, and compare the uniform and graded cases.
Starting recap
Integrate mass moments about named axes, derive torque and angular-momentum constraints, and test orbital energy, angular and numerical consistency against independent evidence.
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At β = 0 and R = 3 m, I = MR²/2 = 18 kg m² and the half-radius region contains 1 kg. Increasing R at fixed mass is not the same operation as adding more material at fixed density.
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At β = 2, the mass fraction inside half radius is:
Experiment
Normalize the density, derive mass and inertia from separate ring integrals, and compare the uniform and graded cases.
Normalize a radial density before integrating rotation
Worked teaching model · synthetic values · A hypothetical thin disk of fixed mass4 kg has area density sigma0(1+beta r²/R²). Rotation axis is perpendicular through the center. Radial rings have area2pi r dr; no thickness or material-strength model.
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Cumulative mass versus radial fraction
Unlike graph quantities rescale independently; read units and values, not screen angles. 1: normalized ring integral (solid). Joined curves show the supplied model, not additional observations.
Equivalent numerical coordinates for Cumulative mass versus radial fraction
normalized ring integral
| radius fraction | enclosed mass (kg) |
|---|---|
| 0 | 0 |
| 0.0125 | 0.0003125488 |
| 0.025 | 0.001250781 |
| 0.0375 | 0.002816455 |
| 0.05 | 0.0050125 |
| 0.0625 | 0.007843018 |
| 0.075 | 0.01131328 |
| 0.0875 | 0.01542974 |
| 0.1 | 0.0202 |
| 0.1125 | 0.02563286 |
| 0.125 | 0.03173828 |
| 0.1375 | 0.03852739 |
| 0.15 | 0.0460125 |
| 0.1625 | 0.05420708 |
| 0.175 | 0.06312578 |
| 0.1875 | 0.07278442 |
| 0.2 | 0.0832 |
| 0.2125 | 0.09439067 |
| 0.225 | 0.1063758 |
| 0.2375 | 0.1191758 |
| 0.25 | 0.1328125 |
| 0.2625 | 0.1473086 |
| 0.275 | 0.1626883 |
| 0.2875 | 0.1789766 |
| 0.3 | 0.1962 |
| 0.3125 | 0.214386 |
| 0.325 | 0.2335633 |
| 0.3375 | 0.2537618 |
| 0.35 | 0.2750125 |
| 0.3625 | 0.2973477 |
| 0.375 | 0.3208008 |
| 0.3875 | 0.3454063 |
| 0.4 | 0.3712 |
| 0.4125 | 0.3982188 |
| 0.425 | 0.4265008 |
| 0.4375 | 0.4560852 |
| 0.45 | 0.4870125 |
| 0.4625 | 0.5193243 |
| 0.475 | 0.5530633 |
| 0.4875 | 0.5882735 |
| 0.5 | 0.625 |
| 0.5125 | 0.6632891 |
| 0.525 | 0.7031883 |
| 0.5375 | 0.7447461 |
| 0.55 | 0.7880125 |
| 0.5625 | 0.8330383 |
| 0.575 | 0.8798758 |
| 0.5875 | 0.9285782 |
| 0.6 | 0.9792 |
| 0.6125 | 1.031797 |
| 0.625 | 1.086426 |
| 0.6375 | 1.143145 |
| 0.65 | 1.202013 |
| 0.6625 | 1.26309 |
| 0.675 | 1.326438 |
| 0.6875 | 1.39212 |
| 0.7 | 1.4602 |
| 0.7125 | 1.530742 |
| 0.725 | 1.603813 |
| 0.7375 | 1.679481 |
| 0.75 | 1.757813 |
| 0.7625 | 1.838879 |
| 0.775 | 1.922751 |
| 0.7875 | 2.0095 |
| 0.8 | 2.0992 |
| 0.8125 | 2.191925 |
| 0.825 | 2.287751 |
| 0.8375 | 2.386754 |
| 0.85 | 2.489012 |
| 0.8625 | 2.594606 |
| 0.875 | 2.703613 |
| 0.8875 | 2.816117 |
| 0.9 | 2.9322 |
| 0.9125 | 3.051945 |
| 0.925 | 3.175438 |
| 0.9375 | 3.302765 |
| 0.95 | 3.434012 |
| 0.9625 | 3.56927 |
| 0.975 | 3.708626 |
| 0.9875 | 3.852172 |
| 1 | 4 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
| Quantity | Value | Unit |
|---|---|---|
| Central area density | 0.1591549 | kg/m² |
| Fixed disk mass | 4 | kg |
| Axial moment of inertia | 9.333333 | kg m² |
| Normalized axial inertia | 0.5833333 | ratio |
| Mass inside half radius | 0.625 | kg |
The radial area factor and squared lever arm weight mass and inertia differently.
dm=2pi sigma0(1+beta r²/R²)r dr. Normalize M=pi sigma0 R²(1+beta/2); then I=pi sigma0 R⁴(1/2+beta/3). A half-radius region has mass fraction(1/4+beta/32)/(1+beta/2), not automatically one half or one quarter for a nonuniform disk.
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The radial area factor and squared lever arm weight mass and inertia differently.
dm=2pi sigma0(1+beta r²/R²)r dr. Normalize M=pi sigma0 R²(1+beta/2); then I=pi sigma0 R⁴(1/2+beta/3). A half-radius region has mass fraction(1/4+beta/32)/(1+beta/2), not automatically one half or one quarter for a nonuniform disk.
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Which assumption must change if radius grows but both density and mass are claimed fixed?
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