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SCIENCE · INVESTIGATE AND EXPLAIN

Derive independent modes before interpreting energy exchange

Two equal 1 kg masses each connect to a fixed wall with a 4 N/m spring and to each other with a spring of stiffness kc. Their equations are x1ddot = −4x1 − kc(x1 − x2) and x2ddot = −4x2 − kc(x2 − x1). The coupling acts on both recipients with opposite forces.

Learning outcome: Derive sum and difference equations, reconstruct the physical coordinates and audit every energy term at two times.

Starting recap

Derive equations with their initial or boundary conditions, integrate distributed profiles, and check model domains independently of numerical outputs.

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Try

At kc = 2, the antisymmetric frequency is sqrt(8) while the symmetric frequency remains 2. Initial energy becomes 0.03 J because the initially stretched connector stores more energy.

Open the experiment

Predict

Increasing only the coupling stiffness changes which normal frequency?

Experiment

Derive sum and difference equations, reconstruct the physical coordinates and audit every energy term at two times.

Decompose two coupled coordinates into normal modes

Worked teaching model · synthetic values · Two equal1 kg masses each attached to a fixed wall by a4 N/m spring, connected by a selected coupling spring. Initial positions(.1,0) m and velocities zero. Linear conservative one-dimensional model with no apparatus.

Reset keeps your prediction, captures and practice history.

Mode superposition in both physical coordinates

displacement (m)time (s)0100.1-0.09847451

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: first mass (solid).2: second mass (dashed). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Mode superposition in both physical coordinates

first mass

time (s)displacement (m)
00.1
0.1250.09612012
0.250.08479346
0.3750.06693276
0.50.04397441
0.6250.01775885
0.75-0.009622335
0.875-0.03599936
1-0.05930263
1.125-0.07773137
1.25-0.08989834
1.375-0.09493853
1.5-0.09257305
1.625-0.08312323
1.75-0.06747449
1.875-0.04699351
2-0.0234067
2.1250.001349329
2.250.02529187
2.3750.04655667
2.50.06354876
2.6250.07506703
2.750.08039233
2.8750.07933249
30.07222131
3.1250.05987292
3.250.04349654
3.3750.02458025
3.50.004754741
3.625-0.01435036
3.75-0.03124473
3.875-0.04469812
4-0.05383362
4.125-0.05818592
4.25-0.05772069
4.375-0.05281473
4.5-0.0442002
4.625-0.03287935
4.75-0.02001881
4.875-0.006833997
50.005525124
5.1250.01607625
5.250.02408573
5.3750.02912136
5.50.03107319
5.6250.03014143
5.750.02679407
5.8750.02169971
60.01564307
6.1250.009432735
6.250.003810667
6.375-0.0006270301
6.5-0.003490094
6.625-0.004629014
6.75-0.00414167
6.875-0.002351562
70.0002395854
7.1250.003019327
7.250.005344566
7.3750.006625276
7.50.006402631
7.6250.004412796
7.750.0006291677
7.875-0.004721991
8-0.01117478
8.125-0.01806504
8.25-0.02459605
8.375-0.02992241
8.5-0.03324339
8.625-0.03389644
8.75-0.03144079
8.875-0.0257221
9-0.01691058
9.125-0.005507679
9.250.007680796
9.3750.02160377
9.50.03505177
9.6250.04676407
9.750.05554661
9.8750.06038954
100.06057318

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

second mass

time (s)displacement (m)
00
0.1250.0007711177
0.250.002964797
0.3750.00623613
0.50.01005582
0.6250.01377338
0.750.01669606
0.8750.01817476
10.01768794
1.1250.01491401
1.250.00978398
1.3750.002508296
1.5-0.006426202
1.625-0.01628974
1.75-0.02617118
1.875-0.03506243
2-0.04195766
2.125-0.04595808
2.25-0.04637145
2.375-0.04279645
2.5-0.03518254
2.625-0.02385848
2.75-0.009525356
2.8750.006786755
30.02379572
3.1250.04007203
3.250.05416222
3.3750.06472038
3.50.07063548
3.6250.07114278
3.750.06590826
3.8750.05507755
40.03928361
4.1250.01961113
4.25-0.002480502
4.375-0.02526984
4.5-0.04691282
4.625-0.06559716
4.75-0.0796984
4.875-0.08792398
5-0.08943228
5.125-0.08391564
5.25-0.07163942
5.375-0.0534327
5.5-0.03063062
5.625-0.004972461
5.750.0215364
5.8750.04678733
60.06874233
6.1250.08560435
6.250.09596916
6.3750.09894577
6.50.09423477
6.6250.08215756
6.750.06363374
6.8750.04010822
70.01343414
7.125-0.01427871
7.25-0.04083699
7.375-0.064144
7.5-0.08237142
7.625-0.09410828
7.75-0.09847451
7.875-0.09518967
8-0.08459116
8.125-0.06760094
8.25-0.04564365
8.375-0.02052386
8.50.005727052
8.6250.03102087
8.750.05338479
8.8750.07112128
90.08294225
9.1250.08806631
9.250.08627169
9.3750.07790107
9.50.06381869
9.6250.04532473
9.750.02403489
9.8750.001736664
10-0.01976498

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Symmetric angular frequency2rad/s
Antisymmetric angular frequency2.44949rad/s
First mass displacement-0.05383362m
Second mass displacement0.03928361m
Total kinetic energy0.01178207J
Wall-spring energy0.008882522J
Coupling-spring energy0.00433541J
Total conserved model energy0.025J
Initial energy0.025J

Adding and subtracting the coupled equations isolates two independent normal coordinates.

Equations x1ddot=−4x1−kc(x1−x2),x2ddot=−4x2−kc(x2−x1). Their sum has frequency2 and difference sqrt(4+2kc). Equal initial mode amplitudes reconstruct the disclosed one-sided displacement. Slow modulation for nearby frequencies resembles beats, but displacement zeros alone do not certify complete transfer of all kinetic/spring energy.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

Adding and subtracting the coupled equations isolates two independent normal coordinates.

Equations x1ddot=−4x1−kc(x1−x2),x2ddot=−4x2−kc(x2−x1). Their sum has frequency2 and difference sqrt(4+2kc). Equal initial mode amplitudes reconstruct the disclosed one-sided displacement. Slow modulation for nearby frequencies resembles beats, but displacement zeros alone do not certify complete transfer of all kinetic/spring energy.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Derive independent modes before interpreting energy exchange

Two equal 1 kg masses each connect to a fixed wall with a 4 N/m spring and to each other with a spring of stiffness kc. Their equations are x1ddot = −4x1 − kc(x1 − x2) and x2ddot = −4x2 − kc(x2 − x1). The coupling acts on both recipients with opposite forces.

Add the equations to obtain a symmetric normal coordinate with angular frequency 2. Subtract them to obtain an antisymmetric coordinate with frequency sqrt(4 + 2kc). These independent coordinates are combinations of the physical positions, not two extra masses.

The initial state is x1 = 0.1 m, x2 = 0 and both velocities zero. Thus x1(t) = 0.05[cos(2t) + cos(ωat)] and x2(t) = 0.05[cos(2t) − cos(ωat)]. At kc = 1, the mode frequencies are 2 and sqrt(6), and initial energy is 0.02 J in a wall spring plus 0.005 J in the connector.

At later times, add both particle kinetic energies, both wall-spring energies and the connector energy. Their sum remains 0.025 J for that packet. Nearby frequencies can produce a slowly varying displacement envelope, but a moment when one displacement vanishes does not establish that all of that particle’s kinetic energy has vanished or that all energy resides in the other mass.

Changed-case check

Predict before reading the comparison. At kc = 2, the antisymmetric frequency is sqrt(8) while the symmetric frequency remains 2. Initial energy becomes 0.03 J because the initially stretched connector stores more energy.

Retained investigation

Derive sum and difference equations, reconstruct the physical coordinates and audit every energy term at two times. Why does a displacement node not by itself locate all of the energy?

Source and boundary

Primary conceptual reference checked 30 October 2026: OpenStax University Physics Volume 1. All prose, functions and evidence packets are original. Bounded mathematical models do not establish measured apparatus, supervised practical skill, independent learner mastery or institutional credit. No physical loading, liquids, heat or sound exposure is requested.

Direct normal-coordinate context: MIT 8.03, Lecture 4: Coupled oscillators and normal modes, checked 30 October 2026. The displayed two-mass coefficients, initial conditions and energy checks are derived here.

Apply

Increasing only the coupling stiffness changes which normal frequency?

Public practice checks a specific claim. It does not establish independent mastery.

Why does a displacement node not by itself locate all of the energy?

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