Differentiate a trajectory without losing its units
A derivative describes local change, not simply a difference between arbitrary endpoints.
Learning outcome: Compare β<0, β=0 and β>0. Retain a turning case and transform the same derivative into minute units without changing the physical motion.
Starting recap
Read derivatives as local rates and integrals as signed accumulation. Review power and chain rules, vector components, units and initial conditions where used.
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Try
At β=.50 and t=2, x=1 m, v=4 m/s and a=6 m/s². Check each derivative directly before comparing signs.
Open the experimentPredict
At β=.25 and t=2, which pair is velocity and acceleration?
Experiment
Compare β<0, β=0 and β>0. Retain a turning case and transform the same derivative into minute units without changing the physical motion.
Differentiate a dimensioned trajectory
Worked teaching model · synthetic values · Supplied one-dimensional trajectory x=1−2t+βt³ in metres with t in seconds. Analytic derivatives describe this exact bounded polynomial, not inferred physical forces. Position and velocity may change sign independently.
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Exact position and its turning behavior
Unlike graph quantities rescale independently; read units and values, not screen angles. 1: supplied cubic (solid). Joined curves show the supplied model, not additional observations.
Equivalent numerical coordinates for Exact position and its turning behavior
supplied cubic
| time (s) | position (m) |
|---|---|
| 0 | 1 |
| 0.05 | 0.9000313 |
| 0.1 | 0.80025 |
| 0.15 | 0.7008437 |
| 0.2 | 0.602 |
| 0.25 | 0.5039063 |
| 0.3 | 0.40675 |
| 0.35 | 0.3107188 |
| 0.4 | 0.216 |
| 0.45 | 0.1227812 |
| 0.5 | 0.03125 |
| 0.55 | -0.05840625 |
| 0.6 | -0.146 |
| 0.65 | -0.2313438 |
| 0.7 | -0.31425 |
| 0.75 | -0.3945313 |
| 0.8 | -0.472 |
| 0.85 | -0.5464687 |
| 0.9 | -0.61775 |
| 0.95 | -0.6856562 |
| 1 | -0.75 |
| 1.05 | -0.8105938 |
| 1.1 | -0.86725 |
| 1.15 | -0.9197812 |
| 1.2 | -0.968 |
| 1.25 | -1.011719 |
| 1.3 | -1.05075 |
| 1.35 | -1.084906 |
| 1.4 | -1.114 |
| 1.45 | -1.137844 |
| 1.5 | -1.15625 |
| 1.55 | -1.169031 |
| 1.6 | -1.176 |
| 1.65 | -1.176969 |
| 1.7 | -1.17175 |
| 1.75 | -1.160156 |
| 1.8 | -1.142 |
| 1.85 | -1.117094 |
| 1.9 | -1.08525 |
| 1.95 | -1.046281 |
| 2 | -1 |
| 2.05 | -0.9462188 |
| 2.1 | -0.88475 |
| 2.15 | -0.8154063 |
| 2.2 | -0.738 |
| 2.25 | -0.6523438 |
| 2.3 | -0.55825 |
| 2.35 | -0.4555312 |
| 2.4 | -0.344 |
| 2.45 | -0.2234687 |
| 2.5 | -0.09375 |
| 2.55 | 0.04534375 |
| 2.6 | 0.194 |
| 2.65 | 0.3524062 |
| 2.7 | 0.52075 |
| 2.75 | 0.6992188 |
| 2.8 | 0.888 |
| 2.85 | 1.087281 |
| 2.9 | 1.29725 |
| 2.95 | 1.518094 |
| 3 | 1.75 |
| 3.05 | 1.993156 |
| 3.1 | 2.24775 |
| 3.15 | 2.513969 |
| 3.2 | 2.792 |
| 3.25 | 3.082031 |
| 3.3 | 3.38425 |
| 3.35 | 3.698844 |
| 3.4 | 4.026 |
| 3.45 | 4.365906 |
| 3.5 | 4.71875 |
| 3.55 | 5.084719 |
| 3.6 | 5.464 |
| 3.65 | 5.856781 |
| 3.7 | 6.26325 |
| 3.75 | 6.683594 |
| 3.8 | 7.118 |
| 3.85 | 7.566656 |
| 3.9 | 8.02975 |
| 3.95 | 8.507469 |
| 4 | 9 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
| Quantity | Value | Unit |
|---|---|---|
| Position | -1 | m |
| Velocity | 1 | m/s |
| Acceleration | 3 | m/s² |
| Jerk | 1.5 | m/s³ |
| Cubic coefficient when time is in minutes | 54000 | m/min³ |
Derivative coefficients carry units and change when the time coordinate is rescaled.
Differentiate each power: velocity−2+3βt² and acceleration6βt. A negative position is not negative speed, and zero velocity does not generally imply zero acceleration. With tau=t/60 in minutes the linear coefficient is−120 m/min and the cubic coefficient is216000β m/min³; convert derivative units consistently.
Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.
Derivative coefficients carry units and change when the time coordinate is rescaled.
Differentiate each power: velocity−2+3βt² and acceleration6βt. A negative position is not negative speed, and zero velocity does not generally imply zero acceleration. With tau=t/60 in minutes the linear coefficient is−120 m/min and the cubic coefficient is216000β m/min³; convert derivative units consistently.
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