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SCIENCE · INVESTIGATE AND EXPLAIN

Distinguish allowed positions from a finite-time crossing

The unit-mass conservative model U=x⁴/4−x² has two minima at±sqrt2 with energy−1 J and a central barrier U = 0=0. Mechanical energy gives K=E−U and speed magnitude sqrt(2(E−U)). Any position with U>E is forbidden in this model, but an allowed-position set need not be one connected interval.

Learning outcome: Solve turning roots for below-barrier, exact-barrier and above-barrier energies; retain disconnected intervals and the selected initial well. Explain the separate timing limitation.

Starting recap

Use vector dot products for work, gradients for conservative force, definite integrals for accumulation and explicit energy/frame boundaries. Check accessible states before assigning trajectories.

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Try

At E=.25, the outer turning magnitude is sqrt(2+sqrt5)≈2.058171 m and the center is allowed with speed sqrt(.5) m/s. Compare with E = 0, whose barrier speed vanishes asymptotically.

Open the experiment

Predict

At E = 0, starting away from the barrier in this ideal double well, central crossing:

Experiment

Solve turning roots for below-barrier, exact-barrier and above-barrier energies; retain disconnected intervals and the selected initial well. Explain the separate timing limitation.

Keep disconnected allowed energy intervals separate

Worked teaching model · synthetic values · Unit-mass particle in U=x⁴/4−x² J, initially at selected minimum x=±sqrt2 with compatible nonnegative speed magnitude. Energy minimum−1 J and central barrier0 J. This is an accessibility diagram, not an integrated trajectory; E0 approaches the barrier asymptotically and does not cross it in finite time.

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Allowed positions require total energy at least potential

energy (J)position (m)-2.52.53.515625-0.9999879

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: double-well potential (solid).2: selected total energy (dashed). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Allowed positions require total energy at least potential

double-well potential

position (m)energy (J)
-2.53.515625
-2.4166672.686933
-2.3333331.966049
-2.251.344727
-2.1666670.8150077
-2.0833330.369225
-20
-1.916667-0.2997565
-1.833333-0.5368441
-1.75-0.7177734
-1.666667-0.8487654
-1.583333-0.9357518
-1.5-0.984375
-1.416667-0.9999879
-1.333333-0.9876543
-1.25-0.9521484
-1.166667-0.8979552
-1.083333-0.8292704
-1-0.75
-0.9166667-0.6637611
-0.8333333-0.5738812
-0.75-0.4833984
-0.6666667-0.3950617
-0.5833333-0.3113305
-0.5-0.234375
-0.4166667-0.1660759
-0.3333333-0.1080247
-0.25-0.06152344
-0.1666667-0.02758488
-0.08333333-0.006932388
00
0.08333333-0.006932388
0.1666667-0.02758488
0.25-0.06152344
0.3333333-0.1080247
0.4166667-0.1660759
0.5-0.234375
0.5833333-0.3113305
0.6666667-0.3950617
0.75-0.4833984
0.8333333-0.5738812
0.9166667-0.6637611
1-0.75
1.083333-0.8292704
1.166667-0.8979552
1.25-0.9521484
1.333333-0.9876543
1.416667-0.9999879
1.5-0.984375
1.583333-0.9357518
1.666667-0.8487654
1.75-0.7177734
1.833333-0.5368441
1.916667-0.2997565
20
2.0833330.369225
2.1666670.8150077
2.251.344727
2.3333331.966049
2.4166672.686933
2.53.515625

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

selected total energy

position (m)energy (J)
-2.5-0.5
2.5-0.5

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Initial minimum position1.414214m
Initial speed magnitude1m/s
Outer turning magnitude1.847759m
Inner turning magnitude for separated wells0.7653669m
Finite-time crossing of central barrier energetically possible0flag
Total energy above barrier-0.5J

The allowed set has separate left and right intervals; the selected initial well cannot cross the central barrier.

Solving U=E via z=x² gives z=2±2sqrt(1+E). Negative energies have two positive roots and two disconnected position intervals; at E−1 each interval shrinks to a minimum. At E0, speed near the barrier is proportional to |x|, so integrating dt=dx/v diverges logarithmically. Energy accessibility alone gives neither direction nor a finite travel time, and no trajectory is numerically integrated here.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

The allowed set has separate left and right intervals; the selected initial well cannot cross the central barrier.

Solving U=E via z=x² gives z=2±2sqrt(1+E). Negative energies have two positive roots and two disconnected position intervals; at E−1 each interval shrinks to a minimum. At E0, speed near the barrier is proportional to |x|, so integrating dt=dx/v diverges logarithmically. Energy accessibility alone gives neither direction nor a finite travel time, and no trajectory is numerically integrated here.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Distinguish allowed positions from a finite-time crossing

The unit-mass conservative model U=x⁴/4−x² has two minima at±sqrt2 with energy−1 J and a central barrier U = 0=0. Mechanical energy gives K=E−U and speed magnitude sqrt(2(E−U)). Any position with U>E is forbidden in this model, but an allowed-position set need not be one connected interval.

To find its boundaries, set U=E and write z=x². The quadratic equation gives z=2±2sqrt(1+E). For−1 < E < 0 both roots are positive, producing separate left and right allowed intervals. A particle initially in one well cannot jump across the forbidden central region merely because an allowed interval exists on the other side.

At E=−.5 J, the positive roots for x² are2±sqrt2; in the right well the allowed interval is approximately .765367 to1.847759 m. At E=−1 the interval shrinks to the minimum and speed is zero. For E>0 the smaller z root is negative and the allowed set connects across the center.

At exactly E = 0, the central point is a separatrix, meaning a boundary between qualitatively different motions. Near x = 0, speed is approximately sqrt2 times|x|, so travel time includes integral dx/|x| and diverges. Starting in a minimum, the ideal particle approaches the barrier asymptotically rather than crossing in finite time. The graph provides accessibility, not an integrated clock or direction of travel.

Changed-case check

Predict before reading the comparison. At E=.25, the outer turning magnitude is sqrt(2+sqrt5)≈2.058171 m and the center is allowed with speed sqrt(.5) m/s. Compare with E = 0, whose barrier speed vanishes asymptotically.

Retained investigation

Solve turning roots for below-barrier, exact-barrier and above-barrier energies; retain disconnected intervals and the selected initial well. Explain the separate timing limitation. What extra information is needed to turn an energy diagram into a trajectory?

Source and boundary

Primary conceptual reference checked30 October2026: OpenStax University Physics Volume1. All functions, numerical packets and teaching prose are original. Bounded supplied models are not measured experiments, apparatus instructions, independent practical skill or institutional credit. Numerical algorithm properties are derived for the disclosed model; do not treat them as universal solver guarantees.

Apply

At E = 0, starting away from the barrier in this ideal double well, central crossing:

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What extra information is needed to turn an energy diagram into a trajectory?

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