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SCIENCE · INVESTIGATE AND EXPLAIN

Derive a radial barrier from angular momentum

In a central force, angular momentum per mass h = r²θdot is conserved. Tangential speed is h/r, so its kinetic energy per mass is h²/(2r²). Combining this with gravitational potential −μ/r gives the radial effective potential Ueff = h²/(2r²) − μ/r.

Learning outcome: Derive Ueff, its stationary radius and curvature, then compare an actual circular energy with a higher-energy passage and a forbidden radius.

Starting recap

Integrate mass moments about named axes, derive torque and angular-momentum constraints, and test orbital energy, angular and numerical consistency against independent evidence.

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Try

At h = 1 and r = 0.25 m, Ueff = 4 m²/s², above E = −0.2. That radius is rejected for the specified energy; clipping its negative radial kinetic energy to zero would falsely turn a forbidden state into a turning point.

Open the experiment

Predict

At h = 1, r = 1 and E = −0.2, the radial speed magnitude is:

Experiment

Derive Ueff, its stationary radius and curvature, then compare an actual circular energy with a higher-energy passage and a forbidden radius.

Separate radial accessibility from angular motion

Worked teaching model · synthetic values · Unit test mass in a fixed Newtonian central field with mu=1 m³/s². Effective potential per mass h²/(2r²)−mu/r, fixed specific energy−.2 m²/s². No central-body surface, encounters or relativistic corrections.

Reset keeps your prediction, captures and practice history.

Angular barrier plus attractive potential

effective potential per mass (m²/s²)radius (m)044-0.5

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: h²/(2r²)−1/r (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Angular barrier plus attractive potential

h²/(2r²)−1/r

radius (m)effective potential per mass (m²/s²)
0.254
0.2968752.304709
0.343751.322314
0.3906250.7168
0.43750.3265306
0.4843750.06659729
0.53125-0.1107266
0.578125-0.2337473
0.625-0.32
0.671875-0.3807463
0.71875-0.4234405
0.765625-0.4531445
0.8125-0.4733728
0.859375-0.4866116
0.90625-0.4946492
0.953125-0.4987906
1-0.5
1.046875-0.4989975
1.09375-0.4963265
1.140625-0.4924001
1.1875-0.4875346
1.234375-0.481974
1.28125-0.4759072
1.328125-0.469481
1.375-0.4628099
1.421875-0.4559836
1.46875-0.449072
1.515625-0.4421299
1.5625-0.4352
1.609375-0.4283156
1.65625-0.4215023
1.703125-0.4147799
1.75-0.4081633
1.796875-0.4016635
1.84375-0.3952887
1.890625-0.3890445
1.9375-0.3829344
1.984375-0.3769608
2.03125-0.3711243
2.078125-0.3654248
2.125-0.3598616
2.171875-0.354433
2.21875-0.3491371
2.265625-0.3439715
2.3125-0.3389335
2.359375-0.3340204
2.40625-0.3292292
2.453125-0.3245568
2.5-0.32
2.546875-0.3155557
2.59375-0.3112208
2.640625-0.3069921
2.6875-0.3028664
2.734375-0.2988408
2.78125-0.2949123
2.828125-0.2910778
2.875-0.2873346
2.921875-0.2836798
2.96875-0.2801108
3.015625-0.2766249
3.0625-0.2732195
3.109375-0.2698922
3.15625-0.2666405
3.203125-0.2634622
3.25-0.260355
3.296875-0.2573168
3.34375-0.2543454
3.390625-0.2514388
3.4375-0.248595
3.484375-0.2458123
3.53125-0.2430887
3.578125-0.2404226
3.625-0.2378121
3.671875-0.2352558
3.71875-0.2327519
3.765625-0.2302991
3.8125-0.2278957
3.859375-0.2255405
3.90625-0.223232
3.953125-0.2209689
4-0.21875

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Effective potential per mass-0.5m²/s²
Specified total energy per mass-0.2m²/s²
Selected radius energetically accessible1flag
Stable circular radius for selected angular momentum1m
Effective potential curvature at circular radius11/s²
Radial equation acceleration0m/s²
Compatible radial speed magnitude0.7745967m/s

A radial effective potential contains tangential kinetic energy; it is not solely gravitational potential.

Conserved h=r² θdot gives tangential speed h/r. Substitution into total energy yields radial kinetic energy plus Ueff. Its derivative vanishes at r=h²/mu; for mu=1 the second derivative there is1/h^6>0. A negative available radial kinetic energy rejects the radius at this energy; no imaginary or clipped speed is reported.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

A radial effective potential contains tangential kinetic energy; it is not solely gravitational potential.

Conserved h=r² θdot gives tangential speed h/r. Substitution into total energy yields radial kinetic energy plus Ueff. Its derivative vanishes at r=h²/mu; for mu=1 the second derivative there is1/h^6>0. A negative available radial kinetic energy rejects the radius at this energy; no imaginary or clipped speed is reported.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Derive a radial barrier from angular momentum

In a central force, angular momentum per mass h = r²θdot is conserved. Tangential speed is h/r, so its kinetic energy per mass is h²/(2r²). Combining this with gravitational potential −μ/r gives the radial effective potential Ueff = h²/(2r²) − μ/r.

The full specific energy is radial kinetic energy rdot²/2 plus Ueff. At a selected radius, E − Ueff must be nonnegative before a real radial speed is assigned. The angular-barrier term is already tangential kinetic energy; counting it again as a separate energy in this equation would double count.

For μ = 1, differentiate Ueff: its stationary radius is r = h². The second derivative there is 1/h⁶, positive for nonzero h, giving a stable radial circular configuration. This is a statement at fixed angular momentum. It does not claim that dissipative motion settles into that circle.

At h = 1 and r = 1, Ueff = −0.5 m²/s². With the displayed E = −0.2, radial speed magnitude is sqrt(0.6) ≈ 0.774597 m/s, so that state is not circular despite being at the potential minimum radius. The circular orbit at that radius would instead have E = −0.5 and zero radial speed. Accessibility, equilibrium radius and actual initial state must remain distinct.

Changed-case check

Predict before reading the comparison. At h = 1 and r = 0.25 m, Ueff = 4 m²/s², above E = −0.2. That radius is rejected for the specified energy; clipping its negative radial kinetic energy to zero would falsely turn a forbidden state into a turning point.

Retained investigation

Derive Ueff, its stationary radius and curvature, then compare an actual circular energy with a higher-energy passage and a forbidden radius. Why is the angular barrier not an additional physical repulsive force?

Source and boundary

Primary conceptual reference checked 30 October 2026: OpenStax University Physics Volume 1. All models, packets and teaching prose are original. These are bounded mathematical investigations, not measured apparatus, physical procedures, practical certification or institutional credit.

Apply

At h = 1, r = 1 and E = −0.2, the radial speed magnitude is:

Public practice checks a specific claim. It does not establish independent mastery.

Why is the angular barrier not an additional physical repulsive force?

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