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SCIENCE · INVESTIGATE AND EXPLAIN

Distinguish alloy composition from a geometric fit

Compare replacement and insertion in a declared cage, then test what the radius calculation can establish.

Learning outcome: Represent substitutional versus interstitial changes, reconcile atom fractions and site occupancy, and evaluate a stated geometric clearance without inferring real alloy stability or properties.

Starting recap

Metallic bonding involves positive cores and delocalized valence electrons. A substitution replaces an occupied site; an insertion adds an atom to a space between host sites.

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Try

One guest replaces a host in an eight-host cage, or is inserted without removing a host. Are the guest atom fractions equal? Does fitting a hole establish a real alloy?

Open the experiment

Predict

Predict the total atom counts and guest fractions for replacement and insertion. Predict which guest radius can fit the declared cubic void and whether fitting alone identifies the preferred structure.

Experiment

Capture replacement and insertion at guest radius 1. Compare fractions and clearances. Reduce the inserted guest radius to 0.7 and 0.3. Test a small guest in the replacement site too, then explain why two geometric fits do not select a real phase.

Distinguish replacement, insertion and geometric fit

Original geometric cage · composition and clearance · Original eight-corner simple-cubic hard-sphere teaching cage, host radius 1 and edge 2. Not a close-packed real metal, alloy phase diagram, hardness or conductivity predictor. Delocalized electrons are a qualitative background, not counted particles.

Reset keeps your prediction, captures and practice history.

Replace one corner host with one guest

Eight declared corner sites have coordinates (0 or 2, 0 or 2, 0 or 2), with host radius 1. This simple-cubic teaching cage is not a close-packed metal or a proposed real alloy phase. H/G mean generic host/guest, not hydrogen or named elements; the markers represent cores in the metallic bonding picture. The blue field below represents delocalized electronic support qualitatively; it is not counted electron trajectories.

Position sketch inside a qualitative delocalized-electron fieldG0H1H2H3H4H5H6H7Markers identify sites; they are not a projected hard-sphere overlap test.
Host atomsGuest atomsTotal atomsGuest atom fractionGuest on host sitesInterstitial guests
7181/8 = 12.5%1/80

Check geometric clearance in actual 3D coordinates

Guest radius = 1. Minimum guest-pair clearance = 0. The fixed cage has 0 overlapping pair(s). Clearance means center distance minus the two radii; zero is tangency, negative is overlap in the stipulated hard-sphere model.

Distance = 2Radii sum = 2Clearance = 0Both circles and their separation use the same scale.

The center-to-corner distance is √3, so the largest sphere fitting this undeformed cubic void has radius √3 − 1 = 0.732051. This is a property of this invented cage, not a universal interstitial-radius cutoff. A small guest can fit both a replacement site and this void; fit alone cannot choose a real alloy structure.

Replacement preserves eight total atoms but changes which species occupies a host site. Insertion preserves all eight hosts and adds a ninth atom, so one guest means a different atom fraction. Atom fractions are not mass fractions without atomic masses. Metallic carriers are delocalized electrons; this geometry does not calculate carrier mobility, resistivity, hardness, phase stability or the effect of processing.

Source framework and representation limits

The AP Chemistry framework topics 2.2–2.4 motivates charge/distance comparisons and ionic/metallic/alloy representations. Specific crystal-structure memorization is excluded. These finite coordinate packets are original teaching constructions, not experimental crystal structures or property measurements.

Guest atom fraction 1/8.

A geometry fit cannot by itself establish an actual alloy structure, stability or property.

Captures replay constrained finite coordinates, composition and pair calculations. They are teaching-model evidence, not measured crystal structures, alloy properties or materials tests.

Understand

Begin with the metallic representation

A metallic solid can maintain cohesion while conducting charge. Its introductory representation contains positive metal cores and delocalized valence electrons that are not assigned permanently to one atom or one local bond. Mobile electrons can respond to an applied field while the cores remain in a solid arrangement. Metallic cohesion also permits some planes to shift without the simple alternating-charge alignment problem of a typical ionic model, helping explain malleability and ductility.

Actual deformation depends on defects, structure, processing and composition. Introducing other atoms can disturb the arrangement and affect resistance to movement; it does not create one universal alloy hardness or conductivity. The existing metallic-bonding investigation calculates resistance for specified copper/aluminum properties and wire geometry. This new activity investigates representation and composition instead of assigning an invented material constant to an arbitrary alloy.

Explain a tendency without making every alloy identical

Interstitial atoms can hinder changes in the host arrangement, often increasing rigidity while reducing malleability and ductility relative to an appropriate host comparison. The delocalized-electron description can still apply, so reduced ease of deformation does not imply loss of metallic conduction. Composition, phase, defects and processing determine the actual magnitude and can produce exceptions. Current CED 3.2.A.6, checked 31 October 2026.

Changed claim: A supplied matched record reports that an interstitial alloy deforms less readily than its host but still conducts electricity. Must its electrons have become immobile because its metal cores move less easily?

Check two different motions

No. Resistance to rearranging the core lattice and electrical motion of delocalized carriers are different mechanisms. The record is compatible with inhibited deformation and retained metallic conduction; it supplies neither an exact electron mobility nor a universal alloy-strength rule.

Replacement and insertion are different operations

In a substitutional picture, an atom replaces a host at a host-lattice site. Comparable atomic sizes can support that representation. In an interstitial picture, a substantially smaller atom occupies space between host sites. The terms specify placement; they are not synonyms for “mixture” and do not by themselves predict whether a particular composition forms a stable phase.

Start with the declared eight-host cage. One guest replacement leaves seven hosts and one guest, eight atoms total. The guest atom fraction is 1/8 = 12.5%. One insertion leaves all eight hosts and adds one guest, nine atoms total; the guest fraction is 1/9, about 11.1111%. Both contain one guest, but the denominators differ. Guest occupancy of host sites is 1/8 for replacement and zero for insertion.

These are atom fractions. To compute mass fractions you would need the atomic masses as well as counts. This packet deliberately uses generic H and G markers for host and guest, not hydrogen and a named chemical element. Their identity labels do not supply atomic masses or actual alloy compositions.

Test a declared geometric rule

The original cage is simple cubic, with corners at coordinates (0 or 2, 0 or 2, 0 or 2), host radius 1 and edge length 2 in radius units. It is not a close-packed metal and is not asserted to be a real host crystal. The cube view marks positions; its projected marker overlap is not a physical collision test.

An inserted guest sits at (1,1,1). Its distance to each corner is √(1² + 1² + 1²) = √3. Define clearance as center distance minus the sum of radii. With host radius 1 and guest radius r, the center-to-corner clearance is √3 − 1 − r. Positive means a gap, zero tangency and negative overlap in the fixed hard-sphere construction.

For r = 0.7, clearance is about 0.032051, a small positive gap. For r = 1, clearance is about −0.267949, so all eight center-to-corner pairs overlap. Reducing the radius to 0.3 gives clearance about 0.432051. The largest guest fitting this undeformed cubic void is √3 − 1 ≈ 0.732051. That number belongs to this cage, not to every interstitial site in every metal.

The true-distance two-sphere view uses one scale and the calculated distance, independently of the oblique cube drawing. Compare the picture with the signed clearance rather than guessing from projected circles.

Use a counterexample to prevent overidentification

A radius-0.3 guest also fits a replacement site without overlap. Geometry therefore permits more than one placement; fitting the hole cannot uniquely select the actual alloy structure. Chemical interactions, host relaxation, defects, processing and temperature are missing. A guest can disturb lattice motion, but this simple cage cannot tell you a strength increment, phase diagram or electron-scattering rate.

Likewise, a radius-1 replacement fits the original host-sized site but fails the central-void test. That supports a geometric contrast under the stated assumptions, not a universal experimental rule that every similarly sized pair of elements must form a substitutional alloy.

The AP Chemistry framework, topic 2.4 connects metallic bonding and substitutional/interstitial representations. Use the nearby practice to transfer the atom-fraction calculation to twenty initial hosts. Then propose a matched measurement of a real material’s resistivity or deformation response, naming which variables the cage did not determine. The model and public practice are not conducted materials testing or independent alloy identification.

Separate heat conduction from electrical current

Mobile electrons in a metal can carry thermal energy from a hotter region toward a colder region. Lattice vibrations also contribute. This heat conduction need not involve a net externally driven charge current or an external electrical circuit. It differs from Joule heating, where electrical work is dissipated; a metal can conduct existing thermal energy without being connected to a power supply.

Changed thermal boundary: An unpowered metal bar initially has a hotter left end and colder right end. Predict the direction of net conducted energy. If both ends are brought to the same temperature with no other gradient, does continued microscopic electron motion imply continued net heat flow in the original direction?

Check energy transport versus charge drift

Net thermal transfer is from the hot left toward the cold right under the stated conditions. At uniform temperature the thermal gradient no longer drives that directional net flow, although microscopic motion continues. Neither comparison requires a net charge current. Actual thermal conductivity also depends on material, temperature and scattering; the electrical-resistivity table alone is not a measured thermal-conductivity dataset.

Solid-state bonding and properties, checked 31 October 2026.

Apply

A finite sample begins with 20 host atoms. One guest replaces a host in sample S; one guest is added without removal in sample I. Their guest atom fractions are:

Public practice checks a specific claim. It does not establish independent mastery.

Distinguish positive core/electron representation, atom fraction, host-site occupancy and mass fraction. Explain the cubic-cage assumption and the measurements still needed to compare an actual alloy’s strength or resistivity.

Continue

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