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SCIENCE · INVESTIGATE AND EXPLAIN

Audit formal charge and compare resonance contributors

Use per-atom ledgers and symmetry to reject invalid or unequal structural interpretations.

Learning outcome: Reconcile ion electron budgets, local octets and formal charges; distinguish equivalent contributors from less-supported non-equivalent proposals and from measured partial charge.

Starting recap

A bond line contains two shared electrons. Count each shared pair once for the total, but include it around both bonded atoms when checking local octets. Signed negative charge adds electrons to the entity.

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Try

Nitrate has 24 valence electrons. Its all-single drawing can use exactly 24 while leaving nitrogen with only six surrounding electrons. Can the correct total certify it?

Open the experiment

Predict

Predict which check rejects all single bonds and which rejects two double bonds around nitrate nitrogen. Predict what changes when the single double bond moves among equivalent O sites.

Experiment

Capture nitrate all-single and proposal A, then B and C. Compare their per-atom formal charges and unchanged total. Repeat with carbonate. For CO2 compare two double bonds with a triple/single proposal, checking octets and charge separation separately.

Audit formal charge and resonance proposals

Original Lewis proposals · inspectable electron bookkeeping · Restricted second-period Lewis bookkeeping with supplied connectivity and paired terminal lone electrons. Formal charges assume equal bond-electron assignment, not measured partial charge. Equivalent contributors are representations, not switching physical molecules.

Reset keeps your prediction, captures and practice history.

Nitrate, NO3−: audit the drawing before comparing contributors

Available electrons = neutral valence sum − signed charge = 5 + 3 × 6 − (-1) = 24. A bond line is two electrons; each dot below an O is one nonbonding electron.

O1FC -1O2FC -1O3FC -1NFC +2Total entity charge: -1; schematic positions, not measured geometry
AtomNeutral valence VNonbonding NBonding BAround atom N+BFormal V−N−B/2
N50662
O16628-1
O26628-1
O36628-1

Distinct electrons drawn: 6 bonding + 18 nonbonding = 24; total budget passes. Local octets fail. Formal-charge sum -1 matches entity charge: yes. Sum of absolute formal charges: 5. Passing the total budget alone cannot repair a second-period atom with six, ten or twelve surrounding electrons.

Repair the local octet failure before interpreting this as an equally acceptable contributor. Formal charge and a conserved total do not waive the second-period octet constraints of this exercise.

Formal charge assigns half of each bond’s electrons to each atom regardless of electronegativity. It is bookkeeping, not measured partial charge or oxidation state. This paired-electron checker does not represent radicals: NO has 11 valence electrons and cannot put every electron into a pair.

Sources and scope

Source definitions guide these original finite exercises. Curves and proposals are teaching constructions, not experimental datasets. Prior high-school activities remain prerequisite returns; this package does not complete Unit 2.

At least one local octet fails despite the total electron budget.

Inspect each atom’s formal charge and the total charge separately from the electron budget. No resonance picture is a time-resolved molecular switch.

Captures retain original teaching-curve or Lewis-proposal settings and replay their calculations. They are model comparisons, not new measurements or independent structural determinations.

Understand

A correct total is only the first check

Nitrate, NO₃⁻, has 5 + 3 × 6 + 1 = 24 valence electrons. Start with its all-single proposal. Three bonds use six distinct electrons; eighteen terminal nonbonding electrons bring the total to 24. Each oxygen has an octet, but nitrogen has only six surrounding electrons. A correct total does not establish the selected second-period Lewis model.

Switch to proposal A. One oxygen now shares a double bond; its nonbonding count decreases from six to four. The total remains 24 while nitrogen reaches eight surrounding electrons. Capture both proposals and use the per-atom ledger to identify what changed. In the too-many-multiple-bonds proposal, the total still matches, but nitrogen has ten surrounding electrons. That fails a different local constraint.

Each bond line represents two shared electrons. Count a pair once in the total electron budget; include that pair around each bonded atom when checking local octets. These two counting rules answer different questions. The existing high-school chemistry Lewis ledger supplies a return for neutral molecules; the ion budgets and contributor comparisons here add distinct work.

Calculate a formal charge at each atom

Formal charge assigns all nonbonding electrons to their atom and half of each bond’s electrons to each bonded atom. In symbols, FC = V − N − B/2, where V is the neutral atom’s valence-electron count, N is the number of nonbonding electrons drawn there, and B is the number of shared bonding electrons around that atom. These are electron counts, not measured charges in coulombs.

In nitrate proposal A, nitrogen has V = 5, N = 0 and B = 8, so FC = +1. The double-bond oxygen has 6 − 4 − 4/2 = 0. Each single-bond oxygen has 6 − 6 − 2/2 = −1. The sum is −1, matching nitrate’s entity charge.

Now choose carbonate, CO₃²⁻, with the same bond arrangement. Carbon supplies four neutral valence electrons, and the extra two electrons required by the −2 charge again give a total of 24. Carbon’s formal charge becomes zero, while the oxygen charges remain 0, −1 and −1. Their sum is −2. Reusing a drawing without checking the central element would miss this distinction.

Equivalent contributors represent one entity

Nitrate proposals A, B and C place the double bond at different labeled oxygen sites. The nuclear connectivity and total electrons remain fixed; in the ideal isolated entity the oxygen positions are symmetry-equivalent. Choosing one drawing cannot privilege one particular site as permanently different.

Treating the three equivalent contributors equally gives formal average bond order (2 + 1 + 1)/3 = 4/3 at each position. This is a representational summary, not evidence that the molecule rapidly switches between a single and a double bond. Nor does averaging the assigned formal charges turn them into measured partial charges. The real electron distribution requires more than these integer drawings.

The IUPAC resonance-form definition identifies contributors to a description of the electronic structure. It does not identify separately existing molecules whose populations the menu measures. The diagram’s fixed positions and numbered oxygens make bookkeeping inspectable; no animation or physical switching is implied.

Non-equivalent proposals need a different comparison

For CO₂, compare two double bonds with a triple bond on one side and a single bond on the other. Both have 16 valence electrons, local octets and zero total charge. But the two-double-bond proposal has zero formal charge on each atom; the triple/single proposal assigns +1 to one oxygen and −1 to the other.

These two descriptions are not equivalent under symmetry: swapping the oxygens changes which side of the triple/single proposal carries each charge, but cannot turn it into two double bonds. Do not apply the nitrate equal-weight arithmetic automatically. Within this restricted comparison, octets and reduced formal-charge separation favor the two-double-bond representation. The activity does not calculate quantum contributor weights or promise that formal-charge minimization is an infallible rule for arbitrary chemistry.

Know which charge and model you are using

IUPAC’s formal-charge convention shares bonding electrons equally regardless of electronegativity. Partial charge describes an assigned distribution of actual electron density under a specified scheme; oxidation-state bookkeeping uses another convention. Neither is supplied by the formal-charge table alone.

The finite checker assumes paired terminal electrons and these selected second-period structures. NO has 5 + 6 = 11 valence electrons, an odd total. It cannot put every electron into pairs. An odd-electron species exposes a limitation of the paired-octet exercise rather than permission to invent a missing electron. For the new carbonate practice, show the budget, local counts and charge sum separately before deciding which inference follows.

Apply

A carbonate proposal has one C=O and two C–O bonds, with terminal O octets and no central lone electrons. Formal charge on C and the total entity charge are:

Public practice checks a specific claim. It does not establish independent mastery.

Explain why resonance contributors are not molecules switching with time and why non-equivalent proposals cannot receive automatic equal weights. Distinguish formal charge, entity charge, partial charge and the limitation exposed by odd-electron NO.

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

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