Distinguish titration landmarks from indicator endpoints
Label curve landmarks and evaluate complete indicator transitions against a stated volume tolerance across matched strong and weak systems.
Learning outcome: Use stoichiometry and equilibrium to distinguish half-equivalence, equivalence and a stipulated observed endpoint, then justify an indicator-window decision.
Starting recap
Equivalence matches analyte and titrant equivalents. Half-equivalence uses half that titrant amount. Neither definition specifies a universal pH, and a visible endpoint is a separate detection rule.
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Try
The selected weak-acid curve is at 100 mL titrant, but the initial label says half-equivalence. Its pH exceeds7. Which definition decides the landmark?
Open the experimentPredict
Predict equivalence volume for 10 mmol analyte and 0.100mol/L titrant. Predict whether the same indicator window is suitable for a weak base titrated by strong acid.
Experiment
Repair the initial landmark label, then select 50 mL and identify half-equivalence. Compare weak-acid, weak-base and strong-acid curves on the same axes. Change indicator windows and use both transition-volume bounds, not merely the midpoint, to decide whether the±1mL criterion passes. Capture a suitable and unsuitable window with reasoning.
Interpret curve landmarks and indicator windows
Worked teaching model · synthetic values · Original ideal 25°C curves:10mmol analyte in 100 mL,0.100mol/L titrant, additive volumes; weakKa/Kb=1e−5, classroomKw=1e−14. Indicator ranges are stipulated teaching windows, not measured dye properties;±1mL is a decision tolerance, not uncertainty. Full water/species balances; no activities, kinetics, calibration/noise or gas exchange. Display samples do not set instrument resolution.
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The gold dot is your selected sample; the band is the stipulated transition range. The line joins 41 display samples, not measured data. Window volumes below are solved continuously from the charge equation, not read from this sample spacing.
| Quantity | Result |
|---|---|
| Your sample label | Half-equivalence at 100mL: does not match; expected Equivalence |
| Half-equivalence | 50mL; pH 5.0002604 |
| Equivalence | 100mL; pH 8.8494977 |
| Selected sample | pH 8.8494977, total volume 200mL |
| Whole transition in modeled volume range | 99.009901–100.010000mL |
| Entire window within 99–101mL? | Yes |
| Stipulated midpoint-pH endpoint | 99.902079mL; signed difference from equivalence -0.097921mL |
All systems begin with 10 mmol analyte in 100 mL and use 0.100mol/L titrant, so equivalence is 100 mL. Weak HA and neutral B are assigned Ka or Kb=10⁻⁵; the base curve mirrors the acid curve under those matched assumptions. At half-equivalence, pH≈pKa for the acid and pOH≈pKb for the base; the full balance retains small corrections. A strong-acid half-equivalence point does not reveal a weak-acid pKa.
The full indicator window must meet the declared ±1mL criterion. Its midpoint pH is a separate illustrative endpoint rule, not a measured observer threshold. Multiple windows can pass in one system and none in another; the decision follows the supplied tolerance and chemistry.
Continuous inversion and sources
For the weak-acid curve, write d=h−Kw/h. With V in mL, charge balance gives V=[10Ka/(Ka+h)−100d]/(.1+d). For the strong acid, replace the first numerator term by 10. The mirrored weak-base curve uses the corresponding hydroxide value. Volumes outside 0–200mL are reported unavailable, never clipped to a curve edge.
OpenStax Chemistry 2e, 14.7 supplies titration-curve and indicator context. All curves, constants and transition windows here are original stipulated teaching models, not measured dye properties. Classroom 25°C water/concentration assumptions, additive volumes and inert spectators apply. Actual indicator chemistry, calibration, mixing lag, noise, activities and gas exchange are absent. No practical titration credit is supplied.
Landmark proposal does not match stoichiometry. Indicator window passes the declared ±1mL criterion.
At 100mL, pH 8.8494977. Equivalence is 100 mL with pH 8.8494977. Transition spans 99.009901–100.010000mL.
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Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
Explain why equivalence pH differs by system, why half-equivalence pH≈pKa or pOH≈pKb is an approximation in the full model, and why a stipulated midpoint endpoint need not equal stoichiometric equivalence. State what empirical indicator or instrument evidence is missing.
Continue
Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
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