Compare molecular speed distributions and threshold fractions
Predict changes in a whole distribution and distinguish density, tail probability and three speed averages.
Learning outcome: Use normalized speed curves and threshold areas to distinguish mass, temperature and energy effects.
Starting recap
RMS speed is the square root of mean squared speed. Equal temperature gives equal mean translational energy, not equal speeds across different masses.
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Try
A curve can have a taller peak but fewer molecules above 600 m/s. Curve height alone is not a probability.
Open the experimentPredict
Predict which equal-temperature gas has the greater fraction above 600 m/s. Predict whether equal RMS speeds force equal temperature or equal mean energy.
Experiment
Compare all three controlled pairs at 0, 600 and 1200 m/s. Capture one prediction, one contrasting tail and the equal-curve case; account for probability outside the fixed chart.
Compare full speed distributions, not one average
Theoretical equilibrium distributions · stipulated ideal gases · Classical dilute ideal gases in equilibrium with zero bulk flow; hypothetical molar masses and temperatures. Maxwell speed densities, not measured histograms or simulated particle trajectories. Fractions use bounded numerical quadrature; no diffusion, effusion or reaction rate is inferred.
Reset keeps your prediction, captures and practice history.
Predict an area before comparing the curves
Equal temperature, different molar mass. A is A: 16 g/mol, 300 K; B is B: 64 g/mol, 300 K. Each curve has total area one over all nonnegative speeds, independently of the number of molecules. The vertical axis is a probability density in (m/s)⁻¹, not a fraction at one exact speed.
Fraction above threshold: A 51.076%; B 2.630%. Beyond the chart’s 3000 m/s boundary, A has 1.794e-10% and B 8.735e-48%. These tails are included in the reported threshold fractions; the finite chart does not end the physical distribution.
| Summary | A | B |
|---|---|---|
| Most probable speed (m/s) | 558.384 | 279.192 |
| Mean speed (m/s) | 630.069 | 315.034 |
| RMS speed (m/s) | 683.878 | 341.939 |
| Mean translational energy (J/mol) | 3741.508 | 3741.508 |
| Mean velocity vector | Zero under no-bulk-flow assumption | Zero under no-bulk-flow assumption |
Most probable, mean and RMS speeds are different summaries. No single marker says that every molecule moves at that speed. At equal temperature the average translational energies agree even when speed curves differ; at equal T/M the curves agree even when energies differ. The table’s energy is translational energy per mole, not necessarily total internal energy.
Formula, units and numerical method
Let s = √(2RT/M), with R = 8.314462618 J/(mol K), temperature T in kelvin and molar mass M in kg/mol. Then x = v/s and f(v) = 4x² exp(−x²)/(√π s). Most probable speed is s; mean is 2s/√π; RMS is √(3/2)s. The mean translational energy is 3RT/2 per mole.
Threshold fractions integrate 4x² exp(−x²)/√π using 512-panel Simpson quadrature up to x=12; the omitted upper tail is below 4×10⁻⁶². This numerical cutoff is not an experimental uncertainty bound. At zero threshold the exact fraction is one. The model assumes a classical equilibrium gas; it does not predict relaxation time, collisions, trajectories or reaction yields.
OpenStax distribution definitions and derivation contextAbove 600 m/s: A 51.076%, B 2.630%.
Curve height is density per m/s; area is a fraction. Equal temperature fixes mean translational energy, while equal T/M fixes the entire ideal speed distribution. Neither condition alone fixes every molecule’s speed.
Captures retain the stipulated gas comparison and threshold. Replay reconstructs theoretical equilibrium densities and numerical tail fractions; it does not record molecular trajectories or measure a new distribution.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
Explain why all curves have area one, why a peak is not a fraction, and why coincident speed distributions need not imply equal translational energy. Distinguish average velocity from average speed and this equilibrium distribution from a diffusion or reaction-rate model.
Continue
Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
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