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SCIENCE · INVESTIGATE AND EXPLAIN

Compare molecular speed distributions and threshold fractions

Predict changes in a whole distribution and distinguish density, tail probability and three speed averages.

Learning outcome: Use normalized speed curves and threshold areas to distinguish mass, temperature and energy effects.

Starting recap

RMS speed is the square root of mean squared speed. Equal temperature gives equal mean translational energy, not equal speeds across different masses.

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Try

A curve can have a taller peak but fewer molecules above 600 m/s. Curve height alone is not a probability.

Open the experiment

Predict

Predict which equal-temperature gas has the greater fraction above 600 m/s. Predict whether equal RMS speeds force equal temperature or equal mean energy.

Experiment

Compare all three controlled pairs at 0, 600 and 1200 m/s. Capture one prediction, one contrasting tail and the equal-curve case; account for probability outside the fixed chart.

Compare full speed distributions, not one average

Theoretical equilibrium distributions · stipulated ideal gases · Classical dilute ideal gases in equilibrium with zero bulk flow; hypothetical molar masses and temperatures. Maxwell speed densities, not measured histograms or simulated particle trajectories. Fractions use bounded numerical quadrature; no diffusion, effusion or reaction rate is inferred.

Reset keeps your prediction, captures and practice history.

Predict an area before comparing the curves

Equal temperature, different molar mass. A is A: 16 g/mol, 300 K; B is B: 64 g/mol, 300 K. Each curve has total area one over all nonnegative speeds, independently of the number of molecules. The vertical axis is a probability density in (m/s)⁻¹, not a fraction at one exact speed.

00.0010.0020.003050010001500200025003000Density (m/s)⁻¹ · A solid navy / B dashed redThreshold 600 m/s. Shading covers only the displayed part of the upper tail.Speed (m/s), not signed velocity. Identical curves overlap.

Fraction above threshold: A 51.076%; B 2.630%. Beyond the chart’s 3000 m/s boundary, A has 1.794e-10% and B 8.735e-48%. These tails are included in the reported threshold fractions; the finite chart does not end the physical distribution.

Circle: most probable · square: mean · diamond: RMSAB050010001500200025003000Speed (m/s). The summaries have the order most probable < mean < RMS.
SummaryAB
Most probable speed (m/s)558.384279.192
Mean speed (m/s)630.069315.034
RMS speed (m/s)683.878341.939
Mean translational energy (J/mol)3741.5083741.508
Mean velocity vectorZero under no-bulk-flow assumptionZero under no-bulk-flow assumption

Most probable, mean and RMS speeds are different summaries. No single marker says that every molecule moves at that speed. At equal temperature the average translational energies agree even when speed curves differ; at equal T/M the curves agree even when energies differ. The table’s energy is translational energy per mole, not necessarily total internal energy.

Formula, units and numerical method

Let s = √(2RT/M), with R = 8.314462618 J/(mol K), temperature T in kelvin and molar mass M in kg/mol. Then x = v/s and f(v) = 4x² exp(−x²)/(√π s). Most probable speed is s; mean is 2s/√π; RMS is √(3/2)s. The mean translational energy is 3RT/2 per mole.

Threshold fractions integrate 4x² exp(−x²)/√π using 512-panel Simpson quadrature up to x=12; the omitted upper tail is below 4×10⁻⁶². This numerical cutoff is not an experimental uncertainty bound. At zero threshold the exact fraction is one. The model assumes a classical equilibrium gas; it does not predict relaxation time, collisions, trajectories or reaction yields.

OpenStax distribution definitions and derivation context

Above 600 m/s: A 51.076%, B 2.630%.

Curve height is density per m/s; area is a fraction. Equal temperature fixes mean translational energy, while equal T/M fixes the entire ideal speed distribution. Neither condition alone fixes every molecule’s speed.

Captures retain the stipulated gas comparison and threshold. Replay reconstructs theoretical equilibrium densities and numerical tail fractions; it does not record molecular trajectories or measure a new distribution.

Understand

Predict a fraction, not just an average

Two hypothetical dilute gases are at 300 K. A has molar mass 16 g/mol; B has 64 g/mol. Predict which has more of its molecules above 600 m/s. Then compare the shaded areas. These are theoretical equilibrium distributions for stipulated masses, not measured histograms of particular chemical species.

The molecular-motion lesson already establishes RMS speed and mean translational energy. This investigation adds the whole speed distribution: most molecules do not move at exactly the RMS speed, and knowing one average does not mean every individual is identical.

Read area and height differently

The vertical axis is probability density per m/s. A narrow interval of width Δv near speed v contains approximately fraction f(v)Δv; a wider interval needs the area under the curve. The height at one speed is not a fraction, and the continuous model assigns probability zero to one exact speed. The total area over all nonnegative speeds is one.

At threshold zero, the fraction above is one. Increasing the threshold cannot increase that fraction. Compare 600 and 1200 m/s for both gases. The taller, narrower heavy-gas peak does not imply a larger high-speed population. The chart uses one fixed horizontal and vertical scale across every comparison.

The curve continues beyond 3000 m/s. The interface reports that off-chart tail separately and includes it in the numerical threshold fraction. Shading stops at the chart edge only because the drawing has finite width, not because the physical model has a maximum molecular speed.

Three summaries of the same distribution

Let s = √(2RT/M), with temperature T in kelvin, molar mass M in kg/mol and R = 8.314462618 J/(mol K). Convert 16 g/mol to 0.016 kg/mol. With dimensionless x = v/s, the Maxwell speed density is

f(v) = 4x² exp(−x²)/(√π s).

The most probable speed is s, the mean speed is 2s/√π and RMS speed is √(3/2)s. The marker rows and table show their ordering. RMS is larger than the arithmetic mean because it squares speeds before averaging and taking a square root.

At zero bulk flow the mean velocity vector is zero because directions cancel. Mean speed is positive. Random microscopic motion can therefore coexist with a stationary macroscopic gas. This activity displays distributions, not simulated trajectories or a transient collision process.

Change one cause, then challenge an inference

The first pair holds temperature fixed and changes mass. Increasing mass fourfold halves the speed scale. The entire distribution shifts to smaller speeds; its area remains one. Its fraction above a threshold v equals the lighter distribution’s fraction above 2v. Test this by saving the heavy fraction at 600 m/s and comparing the light fraction at 1200 m/s.

The second pair holds mass fixed and increases temperature fourfold. The speed scale doubles, while mean translational energy increases fourfold. A wider curve has a lower peak because its total area stays one.

The third pair holds T/M fixed while changing both. The speed curves and every threshold fraction coincide, but mean translational energy per mole, 3RT/2, differs fourfold. Thus an observed speed distribution alone would not identify temperature without information about molecular mass. Save this as a counterexample to “same speeds means same energy.”

Translational energy is not automatically the total internal energy of a polyatomic gas, which can also have rotational and vibrational contributions. Equal gas speeds also do not imply equal diffusion times, effusion rates or reaction yields without further assumptions and models.

Source and numerical boundaries

The OpenStax Maxwell-distribution reference supplies the density and speed summaries. The AP Chemistry CED, 3.5.A.1–4, connects kinetic motion, temperature and graphical representations. The diagrams, comparison cases and transfer task here are original.

Tail fractions use a bounded numerical integration in dimensionless speed, with 512 Simpson panels and upper cutoff x=12; the omitted tail beyond that cutoff is less than 4×10⁻⁶². This cutoff bound is distinct from quadrature error and from any experimental uncertainty. No measurements or uncertainty intervals are inferred from the displayed precision. The model assumes classical equilibrium ideal gases and makes no claim that an arbitrary real gas remains ideal at every stipulated condition.

Apply

Two hypothetical ideal gases have equal temperature and molar masses M and 4M. Which statement about their speed distributions is correct?

Public practice checks a specific claim. It does not establish independent mastery.

Explain why all curves have area one, why a peak is not a fraction, and why coincident speed distributions need not imply equal translational energy. Distinguish average velocity from average speed and this equilibrium distribution from a diffusion or reaction-rate model.

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

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