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SCIENCE · INVESTIGATE AND EXPLAIN

Test alloy-property claims against matched reference data

Normalize wire geometry, compare source uncertainty bounds, and diagnose confounded material claims.

Learning outcome: Separate resistance from resistivity and judge which composition or temperature comparisons support a material claim.

Starting recap

Resistance depends on material, length and cross-sectional area. A ratio compares target with reference; one means equal.

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Try

A thicker copper–nickel wire can have less resistance than a thin copper wire even when its material resistivity is higher.

Open the experiment

Predict

At equal temperature and dimensions, predict the direction of the change from copper to 10% nickel alloy. Then predict how much larger the target area must be to reverse the wire resistance ranking.

Experiment

Capture the equal-area comparison and a thicker-wire counterexample. Contrast pure copper and 10% alloy temperature changes using the endpoint envelopes. Finish with the confounded temperature/composition pair and request the missing matched comparison.

Separate material evidence from wire geometry

Evaluated material reference values · original wire and site representations · Frozen NIST-hosted recommended resistivity values; wire dimensions are stipulated. Bounds use source uncertainty endpoints without assuming independence or a confidence level.

Reset keeps your prediction, captures and practice history.

Normalize the geometry before explaining the material

Reference: Pure Cu, 293 K. Target: Cu–1% Ni, 293 K. Nickel percentages in these labels are by mass. Both selected states are solid. The reference wire is stipulated to be 1 m long with area 1 mm²; target length is 1 m and area is 1 mm². These are calculated wires, not new experimental measurements.

Resistance R = ρL/A, where ρ is resistivity, L length and A cross-sectional area. Thus R₂/R₁ = (ρ₂/ρ₁)(L₂/L₁)/(A₂/A₁) = 1.698451 × 1 / 1 = 1.698451. Reference R = 0.01678 Ω; target R = 0.0285 Ω.

Resistivity ratio: 1.698451Length / area factor: 1Resistance ratio: 1.698451015101520

The source estimates ±0.5% for the reference and ±5% for the target. Using opposite endpoints gives resistivity ratio [1.605501, 1.792335] and resistance ratio [1.605501, 1.792335]. Geometry is treated as exact in this calculation. These are conservative endpoint envelopes, not independent Gaussian errors or 95% intervals.

At matched temperature and geometry, the reference resistivity increases. Both remain metals; a larger resistivity does not establish ionic bonding. A higher material resistivity can coexist with a lower wire resistance if the target is sufficiently thick. Changing area does not change the reference material value.

Before changing the area, write a prediction. Find a thickness that reverses the resistance ranking for the 10% alloy. Then compare the two temperature cases: is a change in the central value enough to establish a resolved difference under these bounds?

Material / TNi mass % / atom %ρ / 10⁻⁸ Ω mSource estimated uncertainty
Pure Cu, 293 K0 / 01.678±0.5%
Cu–0.5% Ni, 293 K0.5 / 0.542.23±5%
Cu–1% Ni, 293 K1 / 1.082.85±5%
Cu–3% Ni, 293 K3 / 3.245.32±5%
Cu–5% Ni, 293 K5 / 5.397.77±5%
Cu–10% Ni, 293 K10 / 10.7313.89±5%
Pure Cu, 400 K0 / 02.398±1%
Cu–10% Ni, 400 K10 / 10.7314.81±3%
Source definitions and comparison limits

Ho et al. (1983), Electrical Resistivity of Ten Selected Binary Alloy Systems, Table 4, printed p. 228. Accessed 2026-10-28. Recommended, smoothed reference values for well-homogenized alloys with low clustering, without severe quenching or cold work. Pure copper is well-annealed and high-purity. Room-temperature dimensions are used without thermal-expansion correction (printed pp. 187–188, 227, 240). Exact impurity concentrations, pressure, common specimen preparation and covariance are not specified for these recommended rows. The stated percentages are source estimated uncertainties, not declared confidence intervals. All selected rows are unstarred; source stars elsewhere flag temperature ranges without experimental data. These values are evaluated recommendations, not a new raw-data cohort. Only selected factual numbers are reproduced; diagrams and tasks are original.

Target/reference resistance = 1.698451.

At matched temperature and geometry, the reference resistivity increases. Both remain metals; a larger resistivity does not establish ionic bonding.

Captures retain your reference comparison and wire geometry or each editable substitution site. Replay recalculates the source comparison and your counting representation; it does not measure a new alloy, infer a unique structure or grade the explanation.

Understand

A material claim needs a geometry check

Two solid wires connect identical low-current measuring instruments. One is copper; the other is copper–nickel alloy. If the alloy wire gives the lower resistance, has alloying made the material intrinsically more conductive? Predict before opening the calculation. A thick wire can carry current through more cross-sectional area, so its geometry may reverse the material ranking.

The investigation uses selected Ho et al. reference values, Table 4. At 293 K, pure copper has resistivity 1.678 × 10⁻⁸ Ω m, while copper with 10% nickel by mass has 13.89 × 10⁻⁸ Ω m. These are evaluated recommendations based on experimental literature, not measurements made by this browser. Their nominal ratio is about 8.2777. Both describe metallic material; neither number establishes a transition to ionic bonding.

Use three columns in your prediction: material property, geometry, inference. State what is matched before attributing a difference to composition.

Make the calculation visible

Resistivity ρ describes the material under the stated conditions; resistance R describes a specimen. For a uniform wire, R = ρL/A. Here L is length in metres and A is cross-sectional area in square metres. The calculation neglects contact resistance and self-heating. The reference dimensions are stipulated, not additional source measurements.

A 1 m copper wire with area 1 mm² has R = (1.678 × 10⁻⁸) × 1/(10⁻⁶) = 0.01678 Ω. Give the same-length 10% alloy wire ten times that area: its resistance becomes 0.01389 Ω. The alloy material still has higher resistivity. The larger area makes the whole wire’s resistance lower.

Use the equal-length 10% case. Predict an area ratio that will reverse the ranking, capture the initial comparison, then change the area. The threshold is A₂/A₁ greater than ρ₂/ρ₁. Now switch to a twice-as-long target: the threshold doubles. Explain both using the diagram and the ratio formula, not only the final number.

Temperature is another competing explanation

Keep composition fixed and compare 293 K with 400 K. Then inspect the deliberately mismatched case: hot copper versus cooler 1% alloy. Geometry normalization cannot turn that into a composition-only comparison. Request a common temperature rather than inventing a correction.

The reference convention uses room-temperature dimensions without thermal-expansion correction. The selected alloy values concern homogenized, low-clustering material without severe quenching or cold work; pure copper is annealed and high-purity. An arbitrary processed wire need not match those conditions. Exact impurity concentrations, pressure and a common specimen history are not supplied for these recommended rows.

The qualitative metallic explanation combines positive cores and delocalized electrons. Atomic vibrations, disorder and electronic structure can affect electron transport while metallic bonding remains. This packet does not measure each mechanism separately. Likewise, ions moving in a liquid can conduct without metallic bonding; magnitude alone is not a unique classifier.

Use the uncertainty information that actually exists

The display preserves the source’s estimated percentage uncertainties. For a ratio, a conservative lower endpoint divides the low target value by the high reference value; the upper endpoint does the opposite. No probability distribution or covariance is given. Do not relabel this envelope a 95% confidence interval or use it to calculate a p-value.

For the 10% alloy temperature comparison, the central value rises from 13.89 to 14.81 in the table’s units, but the endpoint ratio envelope contains one. Describe the central trend and the unresolved distinction separately. The bound is conservative, so inclusion of one also does not prove identical resistivities.

Transfer the argument

An unfamiliar wire has three times the reference resistivity, twice its length, and eight times its area. Predict the resistance ratio before checking the public practice question. Then write the evidence you would need to distinguish geometry, temperature, composition and processing explanations in a real unknown sample.

Continue to the editable alloy representation. The HS conductor design supplies the earlier geometry context; here the new work is auditing empirical references and competing explanations. Captures and submitted prose preserve your argument, but an independent reviewer must judge its quality.

Apply

At one temperature, a target material has three times the resistivity of the reference. Its wire is twice as long and has eight times the area. What follows?

Public practice checks a specific claim. It does not establish independent mastery.

Write a supported claim, a competing geometry or preparation explanation, and an observation that would distinguish them. Explain why higher resistivity does not turn a metal into an ionic solid.

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

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