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SCIENCE · INVESTIGATE AND EXPLAIN

Integrate resistance rather than averaging a cross section

A long, gently tapered conductor can be represented by thin resistive slices when section-average current is a justified approximation. Here length is 1 m, entrance area A0=1 mm² and radius grows as r0(1+αx/L). Resistivity is fixed at 2×10⁻⁸ Ω m. This is a stipulated one-dimensional element, not an exact three-dimensional boundary solution.

Learning outcome: Compare α=0,1,2 at the same current. Derive the integral before reading the ledger, and reconcile its power with the plotted spatial density. State why this model does not resolve lateral fields near the taper ends.

Starting recap

Review charge continuity, definite integrals, first-order differential equations, initial conditions and signed source work. Distinguish displayed time from physical time.

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Try

With α=1 the final radius is twice the initial radius and R=0.01 Ω. At 2 A the voltage drop is 0.02 V and conversion is 0.04 W. Entrance power per length is 0.08 W/m, exit power per length 0.02 W/m; their simple endpoint average is not the integral.

Open the experiment

Predict

For α=1 and current 2 A, what is the total resistive power?

Experiment

Compare α=0,1,2 at the same current. Derive the integral before reading the ledger, and reconcile its power with the plotted spatial density. State why this model does not resolve lateral fields near the taper ends.

Integrate a slowly tapered resistive element

Worked teaching model · synthetic values · One-dimensional slender-element approximation: length 1 m, entrance area 1 mm², radius grows as r0(1+alpha x/L), resistivity 2e−8 ohm m. Steady prescribed current, uniform section averages and fixed temperature. No exact three-dimensional field, heating evolution or material identification.

Reset keeps your prediction, captures and practice history.

Distributed resistive conversion

power per length (W/m)position along element (m)010.080

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: one-dimensional element model (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Distributed resistive conversion

one-dimensional element model

position along element (m)power per length (W/m)
00.08
0.01250.07803688
0.0250.07614515
0.03750.07432138
0.050.07256236
0.06250.07086505
0.0750.06922661
0.08750.06764434
0.10.0661157
0.11250.0646383
0.1250.06320988
0.13750.06182828
0.150.06049149
0.16250.0591976
0.1750.05794477
0.18750.0567313
0.20.05555556
0.21250.05441598
0.2250.05331112
0.23750.05223957
0.250.0512
0.26250.05019116
0.2750.04921184
0.28750.04826091
0.30.04733728
0.31250.04643991
0.3250.04556782
0.33750.04472006
0.350.04389575
0.36250.04309402
0.3750.04231405
0.38750.04155507
0.40.04081633
0.41250.04009711
0.4250.03939674
0.43750.03871456
0.450.03804994
0.46250.03740229
0.4750.03677104
0.48750.03615564
0.50.03555556
0.51250.03497029
0.5250.03439936
0.53750.03384229
0.550.03329865
0.56250.032768
0.5750.03224994
0.58750.03174406
0.60.03125
0.61250.03076738
0.6250.03029586
0.63750.02983509
0.650.02938476
0.66250.02894454
0.6750.02851415
0.68750.02809328
0.70.02768166
0.71250.02727902
0.7250.02688511
0.73750.02649966
0.750.02612245
0.76250.02575323
0.7750.02539179
0.78750.0250379
0.80.02469136
0.81250.02435196
0.8250.02401952
0.83750.02369383
0.850.02337473
0.86250.02306202
0.8750.02275556
0.88750.02245516
0.90.02216066
0.91250.02187193
0.9250.0215888
0.93750.02131113
0.950.02103879
0.96250.02077163
0.9750.02050953
0.98750.02025236
10.02

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Integrated resistance0.01ohm
Terminal voltage0.02V
Resistive power0.04W
Entrance voltage gradient magnitude0.04V/m
Exit voltage gradient magnitude0.01V/m
Entrance power per length0.08W/m
Exit power per length0.02W/m

The same current passes every section while current density and local conversion vary.

With A(x)=A0(1+alpha x/L)², dR=rho dx/A(x). Integrating gives R=rho L/[A0(1+alpha)], including the alpha=0 limit. The voltage drop and integrated power are I R and I² R. Replacing the varying area with an arithmetic average generally changes the result. This slender-section model does not resolve end fields, lateral current redistribution or temperature-dependent resistivity.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

The same current passes every section while current density and local conversion vary.

With A(x)=A0(1+alpha x/L)², dR=rho dx/A(x). Integrating gives R=rho L/[A0(1+alpha)], including the alpha=0 limit. The voltage drop and integrated power are I R and I² R. Replacing the varying area with an arithmetic average generally changes the result. This slender-section model does not resolve end fields, lateral current redistribution or temperature-dependent resistivity.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

State the current, source and measurement model

A long, gently tapered conductor can be represented by thin resistive slices when section-average current is a justified approximation. Here length is 1 m, entrance area A0=1 mm² and radius grows as r0(1+αx/L). Resistivity is fixed at 2×10⁻⁸ Ω m. This is a stipulated one-dimensional element, not an exact three-dimensional boundary solution.

Derive the integral or initial-value solution

Steady charge continuity keeps the same total current in every slice, but J=I/A(x) varies. Since A(x)=A0(1+αx/L)², integrate dR=ρ dx/A(x). The result is R=ρL/[A0(1+α)], including the continuous α=0 limit. The relevant average is of reciprocal area, not area itself.

Test conservation, uncertainty and limits

Local conversion per length is I²ρ/A(x). Its integral must equal I²R, while the terminal drop is IR. These two independent totals check units and normalization. No temperature evolution is solved; applying this fixed-resistivity relation to a strongly heated real element would require additional constitutive and thermal evidence.

Worked original case

With α=1 the final radius is twice the initial radius and R=0.01 Ω. At 2 A the voltage drop is 0.02 V and conversion is 0.04 W. Entrance power per length is 0.08 W/m, exit power per length 0.02 W/m; their simple endpoint average is not the integral.

Investigation

Compare α=0,1,2 at the same current. Derive the integral before reading the ledger, and reconcile its power with the plotted spatial density. State why this model does not resolve lateral fields near the taper ends.

Changed-case practice

Try the changed case before feedback

For α=2 and current 3 A, find the total resistive power in watts.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original derivations and synthetic evidence checked 31 October 2026 against the primary explanation. No live circuit construction, energized switching, component rating or electrical handling instruction is requested. Preserve first predictions, critique, revision and fresh assigned work separately from public practice. Software agreement does not certify measurement technique or learning.

Apply

For α=1 and current 2 A, what is the total resistive power?

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Which initial state, calibration or constitutive assumption is needed for this conclusion, and what fresh evidence could test it?

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