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SCIENCE · INVESTIGATE AND EXPLAIN

Close a finite-mass motional-induction energy account

A sliding rod can induce a current that opposes the mechanical drive, but its speed need not instantly equal a terminal value. In this original ideal model mass, rod length, field magnitude and total resistance are each one in SI units. A constant force F drives it from rest. Friction, loop inductance and radiation are neglected explicitly.

Learning outcome: Compare early and late times at fixed drive, then change the drive force. Retain velocity, displacement, kinetic storage and heat. Explain what additional state would be needed if loop inductance were no longer negligible.

Starting recap

Review flux integrals, linear differential equations, initial conditions, complex numbers and vector derivatives. Keep source constraints, RMS conventions and calibration roles explicit.

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Try

With F=2 N at t=1 s, speed is 2(1−1/e)≈1.264241 m/s and displacement 2/e≈0.735759 m. Drive work is about 1.471518 J. Kinetic energy is about 0.799153 J and resistive conversion about 0.672365 J; the totals close without assuming terminal motion.

Open the experiment

Predict

Why is current proportional to instantaneous speed in this particular model?

Experiment

Compare early and late times at fixed drive, then change the drive force. Retain velocity, displacement, kinetic storage and heat. Explain what additional state would be needed if loop inductance were no longer negligible.

Solve a driven rod with magnetic damping

Worked teaching model · synthetic values · Ideal sliding rod mass1 kg,length1 m,B1 T,total resistance1 ohm, starting from rest. Neglect loop inductance, friction and radiation; mechanical drive is constant. Induced current gives force −v in SI, so vprime=F−v. All motion is virtual; no current apparatus.

Reset keeps your prediction, captures and practice history.

Finite-mass approach to magnetic terminal speed

rod speed (m/s)time (s)041.9633690

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: solution of vprime=F−v (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Finite-mass approach to magnetic terminal speed

solution of vprime=F−v

time (s)rod speed (m/s)
00
0.050.09754115
0.10.1903252
0.150.278584
0.20.3625385
0.250.4423984
0.30.5183636
0.350.5906238
0.40.6593599
0.450.7247437
0.50.7869387
0.550.8461004
0.60.9023767
0.650.9559084
0.71.006829
0.751.055267
0.81.101342
0.851.14517
0.91.186861
0.951.226518
11.264241
1.051.300125
1.11.334258
1.151.366726
1.21.397612
1.251.42699
1.31.454936
1.351.481519
1.41.506806
1.451.530859
1.51.55374
1.551.575504
1.61.596207
1.651.6159
1.71.634633
1.751.652452
1.81.669402
1.851.685526
1.91.700863
1.951.715452
21.729329
2.051.74253
2.11.755087
2.151.767032
2.21.778394
2.251.789202
2.31.799482
2.351.809262
2.41.818564
2.451.827413
2.51.83583
2.551.843837
2.61.851453
2.651.858698
2.71.865589
2.751.872144
2.81.87838
2.851.884311
2.91.889954
2.951.895321
31.900426
3.051.905282
3.11.909902
3.151.914296
3.21.918476
3.251.922452
3.31.926234
3.351.929831
3.41.933253
3.451.936509
3.51.939605
3.551.942551
3.61.945353
3.651.948018
3.71.950553
3.751.952965
3.81.955258
3.851.957441
3.91.959516
3.951.961491
41.963369

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Rod speed1.264241m/s
Rod displacement0.7357589m
Motional emf magnitude1.264241V
Induced current magnitude1.264241A
Magnetic drag magnitude1.264241N
Drive work1.471518J
Kinetic energy0.7991528J
Resistor conversion0.672365J
Energy residual0J
Terminal speed2m/s

External work divides between kinetic storage and resistive conversion; magnetic drag is not a free energy source.

The moving rod gives emf=B ell v and I=emf/R; its magnetic force opposes motion with magnitude B²ell²v/R. With the stated constants, vprime=F−v and v=F(1−e^(−t)). Integrate v to obtain displacement and integrate I²R to obtain heat. The no-inductance approximation makes current instantaneous; a real loop with appreciable inductance would add a dynamic state and magnetic storage.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

External work divides between kinetic storage and resistive conversion; magnetic drag is not a free energy source.

The moving rod gives emf=B ell v and I=emf/R; its magnetic force opposes motion with magnitude B²ell²v/R. With the stated constants, vprime=F−v and v=F(1−e^(−t)). Integrate v to obtain displacement and integrate I²R to obtain heat. The no-inductance approximation makes current instantaneous; a real loop with appreciable inductance would add a dynamic state and magnetic storage.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

State geometry, sources and initial data

A sliding rod can induce a current that opposes the mechanical drive, but its speed need not instantly equal a terminal value. In this original ideal model mass, rod length, field magnitude and total resistance are each one in SI units. A constant force F drives it from rest. Friction, loop inductance and radiation are neglected explicitly.

Derive the field or circuit relation

Motional emf is B ell v, current is that emf divided by R, and the opposing magnetic force has magnitude B²ell²v/R. The equation becomes vprime=F−v. Solving gives v=F(1−e^(−t)); integrating once more gives displacement F[t−1+e^(−t)]. The terminal speed F is approached, not imposed as the initial state.

Audit energy, uncertainty and domain

Drive work is F times displacement. Kinetic storage is v²/2, while resistor conversion is the integral of v² dt under these unit choices. Their sum equals drive work. The magnetic term mediates energy transfer; it is not a new power supply. Appreciable inductance would require an additional current state and magnetic storage, invalidating the instantaneous-current approximation.

Worked original case

With F=2 N at t=1 s, speed is 2(1−1/e)≈1.264241 m/s and displacement 2/e≈0.735759 m. Drive work is about 1.471518 J. Kinetic energy is about 0.799153 J and resistive conversion about 0.672365 J; the totals close without assuming terminal motion.

Investigation

Compare early and late times at fixed drive, then change the drive force. Retain velocity, displacement, kinetic storage and heat. Explain what additional state would be needed if loop inductance were no longer negligible.

Changed-case practice

Try the changed case before feedback

For F=3 N at t=ln 2 s, find rod speed in m/s.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original derivations and synthetic evidence checked 31 October 2026 against the primary explanation. Constants are rounded teaching values and are mutually consistent where Maxwell relations require it. No live circuit, high-voltage, energized-inductor, magnet, beam or optical exposure activity is requested. Retain first work, criterion-linked critique, revision and newly assigned evidence; public numerical feedback is not practical or learner certification.

Apply

Why is current proportional to instantaneous speed in this particular model?

Public practice checks a specific claim. It does not establish independent mastery.

Which source, initial-state, calibration or field-law premise makes the result conditional, and what unused evidence would challenge it?

Continue

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