Enclose a nonuniform current and its return path
Ampère’s law becomes a local-field formula only after the symmetry is justified. The ideal source here is infinitely long and coaxial: an inner conductor of radius 1 m carries +4 A with J=J0[1+α(r/R)²], with R=1 m, while a uniform annulus from radius 2 to 3 m carries −4 A. Vacuum permeability and no end effects are stipulated.
Learning outcome: Change α while comparing one radius inside the inner conductor, one in the empty gap and one outside the return. Predict which observations depend on the inner profile and which depend only on total current. Retain the symmetry statement before extracting B from circulation.
Starting recap
Review cross products, source integration measures, line integrals, differential initial states and signed work. Distinguish symmetry premises from integral laws.
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For α=2 at r=0.5 m, enclosed current is 4×(1/4+1/16)/2=0.625 A and field is 0.25 µT. At r=2 m the field is 0.4 µT. At r=2.5 m the enclosed current is 2.2 A and field 0.176 µT. At r=3 m the return cancels the total exactly.
Open the experimentPredict
Outside the complete return annulus, what fixes the zero field in this model?
Experiment
Change α while comparing one radius inside the inner conductor, one in the empty gap and one outside the return. Predict which observations depend on the inner profile and which depend only on total current. Retain the symmetry statement before extracting B from circulation.
Normalize enclosed current before using symmetry
Worked teaching model · synthetic values · Infinitely long coaxial model: inner radius 1 m carries +4 A with J=J0[1+alpha(r/R)²], R=1 m; annular return from radius 2 to 3 m carries uniform total −4 A. Empty region between. Cylindrical symmetry and vacuum permeability, no ends or transient displacement current. Radius zero uses its exact limit.
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Piecewise field including the return current
Unlike graph quantities rescale independently; read units and values, not screen angles. 1: normalized enclosed current (solid). Joined curves show the supplied model, not additional observations.
Equivalent numerical coordinates for Piecewise field including the return current
normalized enclosed current
| radius (m) | azimuthal field (T) |
|---|---|
| 0 | 0 |
| 0.05 | 2.00500e-8 |
| 0.1 | 4.04000e-8 |
| 0.15 | 6.13500e-8 |
| 0.2 | 8.32000e-8 |
| 0.25 | 1.06250e-7 |
| 0.3 | 1.30800e-7 |
| 0.35 | 1.57150e-7 |
| 0.4 | 1.85600e-7 |
| 0.45 | 2.16450e-7 |
| 0.5 | 2.50000e-7 |
| 0.55 | 2.86550e-7 |
| 0.6 | 3.26400e-7 |
| 0.65 | 3.69850e-7 |
| 0.7 | 4.17200e-7 |
| 0.75 | 4.68750e-7 |
| 0.8 | 5.24800e-7 |
| 0.85 | 5.85650e-7 |
| 0.9 | 6.51600e-7 |
| 0.95 | 7.22950e-7 |
| 1 | 8.00000e-7 |
| 1.05 | 7.61905e-7 |
| 1.1 | 7.27273e-7 |
| 1.15 | 6.95652e-7 |
| 1.2 | 6.66667e-7 |
| 1.25 | 6.40000e-7 |
| 1.3 | 6.15385e-7 |
| 1.35 | 5.92593e-7 |
| 1.4 | 5.71429e-7 |
| 1.45 | 5.51724e-7 |
| 1.5 | 5.33333e-7 |
| 1.55 | 5.16129e-7 |
| 1.6 | 5.00000e-7 |
| 1.65 | 4.84848e-7 |
| 1.7 | 4.70588e-7 |
| 1.75 | 4.57143e-7 |
| 1.8 | 4.44444e-7 |
| 1.85 | 4.32432e-7 |
| 1.9 | 4.21053e-7 |
| 1.95 | 4.10256e-7 |
| 2 | 4.00000e-7 |
| 2.05 | 3.74439e-7 |
| 2.1 | 3.49714e-7 |
| 2.15 | 3.25767e-7 |
| 2.2 | 3.02545e-7 |
| 2.25 | 2.80000e-7 |
| 2.3 | 2.58087e-7 |
| 2.35 | 2.36766e-7 |
| 2.4 | 2.16000e-7 |
| 2.45 | 1.95755e-7 |
| 2.5 | 1.76000e-7 |
| 2.55 | 1.56706e-7 |
| 2.6 | 1.37846e-7 |
| 2.65 | 1.19396e-7 |
| 2.7 | 1.01333e-7 |
| 2.75 | 8.36364e-8 |
| 2.8 | 6.62857e-8 |
| 2.85 | 4.92632e-8 |
| 2.9 | 3.25517e-8 |
| 2.95 | 1.61356e-8 |
| 3 | 0 |
| 3.05 | 0 |
| 3.1 | 0 |
| 3.15 | 0 |
| 3.2 | 0 |
| 3.25 | 0 |
| 3.3 | 0 |
| 3.35 | 0 |
| 3.4 | 0 |
| 3.45 | 0 |
| 3.5 | 0 |
| 3.55 | 0 |
| 3.6 | 0 |
| 3.65 | 0 |
| 3.7 | 0 |
| 3.75 | 0 |
| 3.8 | 0 |
| 3.85 | 0 |
| 3.9 | 0 |
| 3.95 | 0 |
| 4 | 0 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
| Quantity | Value | Unit |
|---|---|---|
| Enclosed signed current | 0.625 | A |
| Azimuthal field | 2.50000e-7 | T |
| Inner central current density | 0.6366198 | A/m² |
| Circular field circulation | 7.85398e-7 | T m |
| Total current outside return | 0 | A |
Ampere symmetry uses the current actually enclosed at each radius, not the full current everywhere.
Inside the central conductor, integrate J0[1+alpha(r/R)²] over annular area, with R=1 m and displayed radial polynomial arguments in units of R, to obtain the normalized enclosed fraction. Between radii 1 and 2 all +4 A is enclosed. The uniform return annulus subtracts 4(r²−4)/5 A until radius 3, beyond which the net is exactly zero. Cylindrical symmetry justifies B times 2pi r; zero circulation alone without that symmetry would not force zero local field.
Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.
Ampere symmetry uses the current actually enclosed at each radius, not the full current everywhere.
Inside the central conductor, integrate J0[1+alpha(r/R)²] over annular area, with R=1 m and displayed radial polynomial arguments in units of R, to obtain the normalized enclosed fraction. Between radii 1 and 2 all +4 A is enclosed. The uniform return annulus subtracts 4(r²−4)/5 A until radius 3, beyond which the net is exactly zero. Cylindrical symmetry justifies B times 2pi r; zero circulation alone without that symmetry would not force zero local field.
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