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SCIENCE · INVESTIGATE AND EXPLAIN

Preserve the energy missing from a final-state-only calculation

Final electrostatic states do not automatically explain the energy transferred while reaching them. Here two capacitors have a common bottom reference conductor and isolated top-node charges, initially at V1=6 V and signed V2. Connecting the top nodes through a positive finite resistor conserves their combined charge but allows resistive energy conversion.

Learning outcome: Compare V2=−4,0,+4 V with C1=2 µF. Retain signed total charge, final common voltage and all energy terms. Explain why equal final voltage does not imply equal energy history and why resistance cannot be inferred from the final state alone.

Starting recap

Review charge conservation, conductor equipotential conditions, definite field integrals and energy derivatives under a stated electrical constraint. Convert capacitance and charge units before interpreting small energies.

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Try

For C1=2 µF, C2=3 µF and V2=0, combined top charge is 12 µC and final voltage 2.4 V. Initial energy is 36 µJ, final energy 14.4 µJ and resistor conversion 21.6 µJ. If V2=−4 V instead, total top charge is zero and final field energy is zero, but the initial 60 µJ is still converted rather than erased.

Open the experiment

Predict

Which quantity fixes the final common voltage in this isolated model?

Experiment

Compare V2=−4,0,+4 V with C1=2 µF. Retain signed total charge, final common voltage and all energy terms. Explain why equal final voltage does not imply equal energy history and why resistance cannot be inferred from the final state alone.

Account for energy during isolated charge redistribution

Worked teaching model · synthetic values · Two linear capacitors C1 selected and C2=3 µF, initially V1=6 V and selected V2 relative to their common negative reference conductor. Their top nodes are connected through a positive finite resistor in an isolated system, then allowed to equilibrate. No battery, leakage or inductor; resistor dissipates the energy difference. Virtual only.

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Initial second voltage changes the final common voltage

final common voltage (V)second initial voltage (V)-444.80

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: charge-conserving final state (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Initial second voltage changes the final common voltage

charge-conserving final state

second initial voltage (V)final common voltage (V)
-40
-3.90.06
-3.80.12
-3.70.18
-3.60.24
-3.50.3
-3.40.36
-3.30.42
-3.20.48
-3.10.54
-30.6
-2.90.66
-2.80.72
-2.70.78
-2.60.84
-2.50.9
-2.40.96
-2.31.02
-2.21.08
-2.11.14
-21.2
-1.91.26
-1.81.32
-1.71.38
-1.61.44
-1.51.5
-1.41.56
-1.31.62
-1.21.68
-1.11.74
-11.8
-0.91.86
-0.81.92
-0.71.98
-0.62.04
-0.52.1
-0.42.16
-0.32.22
-0.22.28
-0.12.34
02.4
0.12.46
0.22.52
0.32.58
0.42.64
0.52.7
0.62.76
0.72.82
0.82.88
0.92.94
13
1.13.06
1.23.12
1.33.18
1.43.24
1.53.3
1.63.36
1.73.42
1.83.48
1.93.54
23.6
2.13.66
2.23.72
2.33.78
2.43.84
2.53.9
2.63.96
2.74.02
2.84.08
2.94.14
34.2
3.14.26
3.24.32
3.34.38
3.44.44
3.54.5
3.64.56
3.74.62
3.84.68
3.94.74
44.8

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Conserved combined top-node charge1.20000e-5C
Final common voltage2.4V
Initial stored energy3.60000e-5J
Final stored energy1.44000e-5J
Resistive energy conversion2.16000e-5J
Energy residual-6.77626e-21J
Charge transferred into second top plate7.20000e-6C

Charge conservation determines the final voltage; an independent energy ledger exposes finite resistive conversion.

Vfinal=(C1V1+C2V2)/(C1+C2). Expanding initial minus final stored energy yields C1C2(V1−V2)²/[2(C1+C2)], always nonnegative. A positive finite resistor dissipates this difference; changing its resistance changes the relaxation timescale, not the ideal final state or total heat. An instantaneous ideal-wire connection cannot explain the energy deficit by deleting it. Opposite initial polarities are signed charge, not negative capacitance.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

Charge conservation determines the final voltage; an independent energy ledger exposes finite resistive conversion.

Vfinal=(C1V1+C2V2)/(C1+C2). Expanding initial minus final stored energy yields C1C2(V1−V2)²/[2(C1+C2)], always nonnegative. A positive finite resistor dissipates this difference; changing its resistance changes the relaxation timescale, not the ideal final state or total heat. An instantaneous ideal-wire connection cannot explain the energy deficit by deleting it. Opposite initial polarities are signed charge, not negative capacitance.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

State conductor and source constraints

Final electrostatic states do not automatically explain the energy transferred while reaching them. Here two capacitors have a common bottom reference conductor and isolated top-node charges, initially at V1=6 V and signed V2. Connecting the top nodes through a positive finite resistor conserves their combined charge but allows resistive energy conversion.

Derive charge, voltage and energy

Charge conservation gives Vf=(C1V1+C2V2)/(C1+C2). Compute initial and final field energies separately. Expanding their difference yields C1C2(V1−V2)²/[2(C1+C2)], always nonnegative. This identity is a direct check that both the signed voltage and the capacitance weighting were retained.

Check evidence and excluded mechanisms

Changing the positive resistance changes the relaxation timescale, not this ideal final state or total converted energy. Declaring the connection to be an instantaneous ideal wire would not explain away the energy deficit; a dynamical loss or radiation model would still be needed. Negative initial V2 means opposite initial polarity, not negative stored energy or capacitance.

Worked original case

For C1=2 µF, C2=3 µF and V2=0, combined top charge is 12 µC and final voltage 2.4 V. Initial energy is 36 µJ, final energy 14.4 µJ and resistor conversion 21.6 µJ. If V2=−4 V instead, total top charge is zero and final field energy is zero, but the initial 60 µJ is still converted rather than erased.

Investigation

Compare V2=−4,0,+4 V with C1=2 µF. Retain signed total charge, final common voltage and all energy terms. Explain why equal final voltage does not imply equal energy history and why resistance cannot be inferred from the final state alone.

Changed-case practice

Try the changed case before feedback

For C1=1 µF,C2=3 µF,V1=6 V,V2=2 V, find final voltage in volts.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original derivations and synthetic numerical packets checked 30 October 2026 against the primary explanation. No charged-capacitor handling, high-voltage apparatus, material safety limit or practical certification is requested. Preserve first predictions, independent critique, revision and newly assigned work separately from public practice feedback.

Apply

Which quantity fixes the final common voltage in this isolated model?

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Which geometry, calibration or source assumption could fail while an exact arithmetic fit remains possible?

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