Learn

Learning preferences

Make learning more comfortable. Changes apply immediately.

Enlarges page content, including diagrams and their labels. You can also use your browser’s zoom.

Choose the colours that are easiest for you to distinguish. Applies to lesson diagrams and lab plots. Labels, shapes, hatching and line patterns also distinguish meanings. Source photographs and raw image brightness stay unchanged; mask-only views are available for image overlays.

ExampleComparisonSample link

Saved in this browser on this device. Preferences are separate from progress backups.

SCIENCE · INVESTIGATE AND EXPLAIN

Integrate a nonuniform field through an oriented patch

Flux is an oriented surface integral, not a count of actual particles and not the magnitude of the electric field. For each small patch, use E dot n times its area. A tangent field can be large while contributing no flux. For an open patch, reversing the chosen normal reverses flux; enclosed-charge language applies only after specifying a closed surface.

Learning outcome: Compare β=−1,0,1,2 at L=2 m. Retain signed flux, center approximation and its error before inspecting the graph. Explain why a zero net flux through part of the patch would not prove that the local field vanishes.

Starting recap

Review oriented normals, definite integrals, source volume measures and partial derivatives as one-coordinate rates. Potential differences use an explicit reference and field work uses a signed line integral.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

For L=2 m and β=1 N/C/m², exact flux is 20/3 N m²/C, and the area-average normal field is 10/3 N/C. Center-field times area gives 6 N m²/C, an error −2/3. The tangent 5 N/C contributes zero. Reversing the surface normal gives −20/3.

Open the experiment

Predict

For L=2 m and β=1, what is the exact flux through the +z patch?

Experiment

Compare β=−1,0,1,2 at L=2 m. Retain signed flux, center approximation and its error before inspecting the graph. Explain why a zero net flux through part of the patch would not prove that the local field vanishes.

Integrate a nonuniform normal field over a patch

Worked teaching model · synthetic values · Patch z=0,0≤x≤L,0≤y≤1 m with chosen +z normal. Prescribed field on the patch is E=(5,0,2+βx²) N/C with dimensioned coefficients. The tangent component has no flux through this patch. A local patch is not a closed surface and does not alone determine enclosed charge.

Reset keeps your prediction, captures and practice history.

Nonuniform normal component on the patch

normal field (N/C)x coordinate (m)0260

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: prescribed patch field (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Nonuniform normal component on the patch

prescribed patch field

x coordinate (m)normal field (N/C)
02
0.0252.000625
0.052.0025
0.0752.005625
0.12.01
0.1252.015625
0.152.0225
0.1752.030625
0.22.04
0.2252.050625
0.252.0625
0.2752.075625
0.32.09
0.3252.105625
0.352.1225
0.3752.140625
0.42.16
0.4252.180625
0.452.2025
0.4752.225625
0.52.25
0.5252.275625
0.552.3025
0.5752.330625
0.62.36
0.6252.390625
0.652.4225
0.6752.455625
0.72.49
0.7252.525625
0.752.5625
0.7752.600625
0.82.64
0.8252.680625
0.852.7225
0.8752.765625
0.92.81
0.9252.855625
0.952.9025
0.9752.950625
13
1.0253.050625
1.053.1025
1.0753.155625
1.13.21
1.1253.265625
1.153.3225
1.1753.380625
1.23.44
1.2253.500625
1.253.5625
1.2753.625625
1.33.69
1.3253.755625
1.353.8225
1.3753.890625
1.43.96
1.4254.030625
1.454.1025
1.4754.175625
1.54.25
1.5254.325625
1.554.4025
1.5754.480625
1.64.56
1.6254.640625
1.654.7225
1.6754.805625
1.74.89
1.7254.975625
1.755.0625
1.7755.150625
1.85.24
1.8255.330625
1.855.4225
1.8755.515625
1.95.61
1.9255.705625
1.955.8025
1.9755.900625
26

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Patch area2m²
Flux with positive-z normal6.666667N m²/C
Flux with reversed normal-6.666667N m²/C
Area-averaged normal field3.333333N/C
Center-field times area approximation6N m²/C
Center approximation minus exact flux-0.6666667N m²/C
Tangent-field contribution to flux0N m²/C

Flux integrates the normal component over oriented area, not field magnitude times area.

The y integration contributes its 1 m width. Integrating 2+βx² from 0 to L gives 2L+βL³/3. Using the center value gives 2L+βL³/4, differing by −βL³/12; the midpoint shortcut happens to be exact for a linear profile, not this quadratic. Reversing the normal changes the sign of every contribution. The tangent component contributes zero regardless of its magnitude.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

Flux integrates the normal component over oriented area, not field magnitude times area.

The y integration contributes its 1 m width. Integrating 2+βx² from 0 to L gives 2L+βL³/3. Using the center value gives 2L+βL³/4, differing by −βL³/12; the midpoint shortcut happens to be exact for a linear profile, not this quadratic. Reversing the normal changes the sign of every contribution. The tangent component contributes zero regardless of its magnitude.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Define the geometry and reference

Flux is an oriented surface integral, not a count of actual particles and not the magnitude of the electric field. For each small patch, use E dot n times its area. A tangent field can be large while contributing no flux. For an open patch, reversing the chosen normal reverses flux; enclosed-charge language applies only after specifying a closed surface.

Derive the integral or gradient

The supplied patch lies at z=0, spans x=0 to L and y=0 to 1 m, and has +z normal. Its normal field is 2+βx² N/C in the stated dimensioned convention, while a 5 N/C east component is tangent. Integrate over y and x to get Φ=2L+βL³/3. Divide by area L to obtain the area-average normal field, not the total field magnitude.

Check the inference boundary

The center-value shortcut gives L[2+β(L/2)²]=2L+βL³/4. Its signed error is −βL³/12. The midpoint shortcut would be exact for a linear profile on this rectangular interval, but not for this quadratic. A negative local normal field contributes negative flux; one must not replace it by its absolute value.

Worked original case

For L=2 m and β=1 N/C/m², exact flux is 20/3 N m²/C, and the area-average normal field is 10/3 N/C. Center-field times area gives 6 N m²/C, an error −2/3. The tangent 5 N/C contributes zero. Reversing the surface normal gives −20/3.

Investigation

Compare β=−1,0,1,2 at L=2 m. Retain signed flux, center approximation and its error before inspecting the graph. Explain why a zero net flux through part of the patch would not prove that the local field vanishes.

Changed-case practice

Try the changed case before feedback

For L=1 m and β=2, find the +z flux in N m²/C.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original calculations checked 30 October 2026 against the primary explanation. All source distributions, fields and readings are hypothetical. This is not a physical high-voltage or electrical handling activity, and public numerical feedback does not establish independent mastery. Preserve first predictions, critique, revision and newly assigned work in the separate retained course workspace.

Apply

For L=2 m and β=1, what is the exact flux through the +z patch?

Public practice checks a specific claim. It does not establish independent mastery.

Which geometry, calibration or source assumption could fail while an exact arithmetic fit remains possible?

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

Skipping retains experiments and awards no mastery.

Save a science backup or import one

Science work is stored locally in this browser, separately from mathematics and AI. It does not sync automatically. Use this science-only backup; this checkout's older all-subject export does not include science.

A legacy file is available only when the complete snapshot fits the 36 MB limit. For larger snapshots, prepare a complete file set below; never discard notebooks to make a smaller file.

Matching imported notebook drafts replace their current drafts. Omitted lessons and known first attempts remain. Export your current work first if you want to retain both drafts.

Complete file sets and course backups

A file set can hold more work than one science file. Keep its manifest and every part together. Each file is limited to 36 MB. This format needs this version of LearnAI or a compatible newer version; older versions can use only the legacy single-file backup above.

The set includes every saved science course and global continuation at this moment. Later edits need a new export. A conflicting tab exports its own visible work, which may differ from saved work in another tab.

0 file(s) selected. File order and filenames do not determine identity. Missing, changed or conflicting parts block the entire restore; no good part is applied by itself.

Science storage: loading. No account or remote computation is required.