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SCIENCE · INVESTIGATE AND EXPLAIN

Solve net-charge constraints on coupled floating conductors

A floating conductor need not be at zero potential or have zero charge on every attached capacitor. Its conserved net charge is the sum of its plate charges. The original network has 2 nF from node 1 to ground, 3 nF from node 2 to ground and 1 nF between the nodes. Ground fixes the reference; the two node charges are specified.

Learning outcome: At fixed q2=0, compare q1=−3,0,+3 nC. Retain each node plate charge and reconstruct its specified net charge. Verify energy using both branch terms and half charge dot potential; then change q2 and explain why potential changes at both nodes.

Starting recap

Review charge conservation, conductor equipotential conditions, definite field integrals and energy derivatives under a stated electrical constraint. Convert capacitance and charge units before interpreting small energies.

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Try

At q1=3 nC and q2=0, V1=12/11 V and V2=3/11 V. Node 2 has +9/11 nC on its ground capacitor and −9/11 nC on its coupling plate, so its net charge is zero without either capacitor being uncharged. Stored energy is 18/11 nJ by either account.

Open the experiment

Predict

For q2=0, must floating node 2 have zero potential?

Experiment

At fixed q2=0, compare q1=−3,0,+3 nC. Retain each node plate charge and reconstruct its specified net charge. Verify energy using both branch terms and half charge dot potential; then change q2 and explain why potential changes at both nodes.

Solve coupled floating-conductor charge balances

Worked teaching model · synthetic values · Node1 has2 nF to ground, node2 has3 nF to ground, and1 nF couples the nodes. Net node charges are prescribed and conserved. Ground is a fixed reference. Matrix charge balances, not simple series equal-charge assumptions, determine potentials. No switching history or physical wiring.

Reset keeps your prediction, captures and practice history.

Induced floating potential at fixed second-node charge

second-node potential (V)first-node charge (nC)-440.3636364-0.3636364

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: matrix solution with coupling (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Induced floating potential at fixed second-node charge

matrix solution with coupling

first-node charge (nC)second-node potential (V)
-4-0.3636364
-3.9-0.3545455
-3.8-0.3454545
-3.7-0.3363636
-3.6-0.3272727
-3.5-0.3181818
-3.4-0.3090909
-3.3-0.3
-3.2-0.2909091
-3.1-0.2818182
-3-0.2727273
-2.9-0.2636364
-2.8-0.2545455
-2.7-0.2454545
-2.6-0.2363636
-2.5-0.2272727
-2.4-0.2181818
-2.3-0.2090909
-2.2-0.2
-2.1-0.1909091
-2-0.1818182
-1.9-0.1727273
-1.8-0.1636364
-1.7-0.1545455
-1.6-0.1454545
-1.5-0.1363636
-1.4-0.1272727
-1.3-0.1181818
-1.2-0.1090909
-1.1-0.1
-1-0.09090909
-0.9-0.08181818
-0.8-0.07272727
-0.7-0.06363636
-0.6-0.05454545
-0.5-0.04545455
-0.4-0.03636364
-0.3-0.02727273
-0.2-0.01818182
-0.1-0.009090909
00
0.10.009090909
0.20.01818182
0.30.02727273
0.40.03636364
0.50.04545455
0.60.05454545
0.70.06363636
0.80.07272727
0.90.08181818
10.09090909
1.10.1
1.20.1090909
1.30.1181818
1.40.1272727
1.50.1363636
1.60.1454545
1.70.1545455
1.80.1636364
1.90.1727273
20.1818182
2.10.1909091
2.20.2
2.30.2090909
2.40.2181818
2.50.2272727
2.60.2363636
2.70.2454545
2.80.2545455
2.90.2636364
30.2727273
3.10.2818182
3.20.2909091
3.30.3
3.40.3090909
3.50.3181818
3.60.3272727
3.70.3363636
3.80.3454545
3.90.3545455
40.3636364

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Floating node1 potential1.090909V
Floating node2 potential0.2727273V
Node1-to-ground plate charge2.181818nC
Node2-to-ground plate charge0.8181818nC
Coupling plate charge on node1 side0.8181818nC
Reconstructed node1 net charge3nC
Reconstructed node2 net charge0nC
Energy from half charge dot potential1.63636e-9J
Energy from three branches1.63636e-9J
Energy-account residual2.06795e-25J

A floating node can have zero net charge and a nonzero potential because its capacitor plate charges need not vanish individually.

In nC/nF units the balances are3V1−V2=q1 and−V1+4V2=q2. The determinant11 is positive, giving V1=(4q1+q2)/11 and V2=(q1+3q2)/11. Summing branch energies equals(1/2)(q1V1+q2V2), with nC converted to C. A zero net node charge is a sum constraint, not an assertion that every connected capacitor is uncharged.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

A floating node can have zero net charge and a nonzero potential because its capacitor plate charges need not vanish individually.

In nC/nF units the balances are3V1−V2=q1 and−V1+4V2=q2. The determinant11 is positive, giving V1=(4q1+q2)/11 and V2=(q1+3q2)/11. Summing branch energies equals(1/2)(q1V1+q2V2), with nC converted to C. A zero net node charge is a sum constraint, not an assertion that every connected capacitor is uncharged.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

State conductor and source constraints

A floating conductor need not be at zero potential or have zero charge on every attached capacitor. Its conserved net charge is the sum of its plate charges. The original network has 2 nF from node 1 to ground, 3 nF from node 2 to ground and 1 nF between the nodes. Ground fixes the reference; the two node charges are specified.

Derive charge, voltage and energy

In nC and volts, the balances are q1=2V1+(V1−V2)=3V1−V2 and q2=3V2+(V2−V1)=4V2−V1. Solving the two-by-two system with determinant 11 gives V1=(4q1+q2)/11 and V2=(q1+3q2)/11. Equal-charge series shortcuts do not apply to this general floating-node topology.

Check evidence and excluded mechanisms

The stored energy can be computed from three branches: one half times [2V1²+3V2²+(V1−V2)²] in nJ. Independently it is one half times (q1V1+q2V2), also in nJ. These agree by the charge balances. A zero net node charge can coexist with nonzero potential and equal opposite plate-charge contributions.

Worked original case

At q1=3 nC and q2=0, V1=12/11 V and V2=3/11 V. Node 2 has +9/11 nC on its ground capacitor and −9/11 nC on its coupling plate, so its net charge is zero without either capacitor being uncharged. Stored energy is 18/11 nJ by either account.

Investigation

At fixed q2=0, compare q1=−3,0,+3 nC. Retain each node plate charge and reconstruct its specified net charge. Verify energy using both branch terms and half charge dot potential; then change q2 and explain why potential changes at both nodes.

Changed-case practice

Try the changed case before feedback

For q1=0 and q2=−2 nC, find V1 in volts.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original derivations and synthetic numerical packets checked 30 October 2026 against the primary explanation. No charged-capacitor handling, high-voltage apparatus, material safety limit or practical certification is requested. Preserve first predictions, independent critique, revision and newly assigned work separately from public practice feedback.

Apply

For q2=0, must floating node 2 have zero potential?

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Which geometry, calibration or source assumption could fail while an exact arithmetic fit remains possible?

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