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SCIENCE · INVESTIGATE AND EXPLAIN

Build a disk field from ring elements

A disk is not a collection of equally charged rings when its surface density is uniform. A ring of radius r and width dr has area 2πr dr, so dq=σ2πr dr. Omitting this radial Jacobian gives the wrong amount of charge and the wrong axial field.

Learning outcome: At fixed σ, compare increasing R while keeping z fixed. Retain the changing Q as well as the field. Then hold R fixed and compare positive z values; test whether point or plane approximation meets a stated relative-error tolerance.

Starting recap

Review signed vector components, definite integrals, radians, density units and elementary derivatives. Distinguish observer coordinates from source integration coordinates.

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Try

For σ=1 nC/m², R=1 m and z=0.5 m, Q=π nC and Ez=18π(1−1/√5)≈31.259335 N/C. The infinite-plane comparison is 18π≈56.548668 N/C, substantially larger. A finite disk has less field than that infinite source at the same σ.

Open the experiment

Predict

Which charge element is correct for a uniform disk decomposed into rings?

Experiment

At fixed σ, compare increasing R while keeping z fixed. Retain the changing Q as well as the field. Then hold R fixed and compare positive z values; test whether point or plane approximation meets a stated relative-error tolerance.

Build a disk field from area-weighted rings

Worked teaching model · synthetic values · Uniform prescribed surface charge density 1 nC/m² on a disk in vacuum. Surface density, not total charge, stays fixed as radius changes. Use K=9×10^9 and dQ=σ 2πr dr. Observation stays strictly off the ideal zero-thickness charged surface.

Reset keeps your prediction, captures and practice history.

Finite disk axial field

field (N/C)axial distance (m)0450.921870

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: ring-integrated disk field (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Finite disk axial field

ring-integrated disk field

axial distance (m)field (N/C)
0.150.92187
0.1487548.2286
0.197545.59195
0.2462543.02748
0.29540.5485
0.3437538.16584
0.392535.8878
0.4412533.72017
0.4931.66639
0.5387529.72782
0.587527.90399
0.6362526.19293
0.68524.59146
0.7337523.09549
0.782521.70026
0.8312520.40059
0.8819.19104
0.9287518.06609
0.977517.02024
1.0262516.0481
1.07515.14448
1.1237514.30441
1.172513.52319
1.2212512.79638
1.2712.11986
1.3187511.48975
1.367510.90248
1.4162510.35474
1.4659.843481
1.513759.365877
1.56258.919342
1.611258.501496
1.668.110155
1.708757.743312
1.75757.399129
1.806257.075918
1.8556.77213
1.903756.486347
1.95256.217263
2.001255.963684
2.055.72451
2.098755.49873
2.14755.285416
2.196255.083714
2.2454.892836
2.293754.712059
2.34254.540713
2.391254.378181
2.444.223895
2.488754.077327
2.53753.937991
2.586253.805437
2.6353.679245
2.683753.559031
2.73253.444434
2.781253.33512
2.833.230781
2.878753.131127
2.92753.03589
2.976252.94482
3.0252.857684
3.073752.774264
3.12252.694358
3.171252.617775
3.222.544338
3.268752.473882
3.31752.40625
3.366252.341297
3.4152.278886
3.463752.218889
3.51252.161186
3.561252.105663
3.612.052214
3.658752.000738
3.70751.951143
3.756251.903337
3.8051.857239
3.853751.812769
3.90251.769852
3.951251.728419
41.688402

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Total disk charge at fixed density3.141593nC
Finite disk axial field31.25933N/C
Infinite-plane comparison56.54867N/C
Infinite-plane relative overestimate0.809017ratio
Point-charge comparison113.0973N/C

The area element contributes a radial factor, and the finite disk approaches different limiting models near and far.

Integrate the ring kernel K z dq/(r²+z²)^(3/2) with dq=2πσr dr to obtain 2πKσ[1−z/√(R²+z²)] for z>0. The implementation rationalizes this difference as R²/[h(h+z)] to reduce cancellation. Near the positive side it tends to 2πKσ; far away it tends to KQ/z². The ideal charged surface itself is outside this model.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

The area element contributes a radial factor, and the finite disk approaches different limiting models near and far.

Integrate the ring kernel K z dq/(r²+z²)^(3/2) with dq=2πσr dr to obtain 2πKσ[1−z/√(R²+z²)] for z>0. The implementation rationalizes this difference as R²/[h(h+z)] to reduce cancellation. Near the positive side it tends to 2πKσ; far away it tends to KQ/z². The ideal charged surface itself is outside this model.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Define the source and observer

A disk is not a collection of equally charged rings when its surface density is uniform. A ring of radius r and width dr has area 2πr dr, so dq=σ2πr dr. Omitting this radial Jacobian gives the wrong amount of charge and the wrong axial field.

Derive before approximating

Combine this area element with the ring kernel: Ez=2πKσz times the integral of r/(r²+z²)^(3/2) from 0 to R. For z>0 the result is 2πKσ[1−z/√(R²+z²)]. The workbench evaluates the equivalent factor R²/[h(h+z)], h=√(R²+z²), avoiding subtraction of nearly equal terms at large z.

Check evidence and the domain

At fixed σ, the total charge is πR²σ. Near the positive side of a large disk the field tends toward 2πKσ; far away it tends toward KQ/z². These are limiting approximations to a finite source, not two simultaneously exact descriptions. The observation remains above the ideal zero-thickness surface, where its limiting discontinuity must not be mistaken for an ordinary point value.

Worked original case

For σ=1 nC/m², R=1 m and z=0.5 m, Q=π nC and Ez=18π(1−1/√5)≈31.259335 N/C. The infinite-plane comparison is 18π≈56.548668 N/C, substantially larger. A finite disk has less field than that infinite source at the same σ.

Investigation

At fixed σ, compare increasing R while keeping z fixed. Retain the changing Q as well as the field. Then hold R fixed and compare positive z values; test whether point or plane approximation meets a stated relative-error tolerance.

Changed-case practice

Try the changed case before feedback

For σ=1 nC/m² and z=R=1 m, find Ez in N/C.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original derivations and numerical packets checked 30 October 2026 against the primary explanation. The electrostatic field construction also uses continuous source integration. All records are synthetic; no electrical apparatus, high-voltage handling or practical certification is requested. Public feedback is not independent mastery; retain first predictions, alternative models and criterion-linked critique in the separate course evidence workspace.

Apply

Which charge element is correct for a uniform disk decomposed into rings?

Public practice checks a specific claim. It does not establish independent mastery.

Which geometry, calibration or source assumption could fail while an exact arithmetic fit remains possible?

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