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SCIENCE · INVESTIGATE AND EXPLAIN

Close six faces without inventing a local field

Gauss law relates a closed-surface flux to net enclosed charge. It does not say every field on that surface is uniform, nor that zero net charge means zero field. A useful test case is an affine field whose constant offsets affect individual faces but cancel from their closed sum.

Learning outcome: Change a and b separately, predicting which face pairs change. Retain all six signed terms rather than only the sum. Find two different settings with zero net flux and show that their point fields can differ.

Starting recap

Review oriented normals, definite integrals, source volume measures and partial derivatives as one-coordinate rates. Potential differences use an explicit reference and field work uses a signed line integral.

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Try

For a=1 and b=0, the six outward fluxes are −3,5,4,−4,−2,0 N m²/C, summing to zero. Yet at the origin E=(3,−2,1) N/C and magnitude √14 N/C. Zero enclosed net charge therefore does not establish zero field. At a=2,b=1 the closed flux is 4 N m²/C.

Open the experiment

Predict

What follows from zero closed electric flux without additional symmetry?

Experiment

Change a and b separately, predicting which face pairs change. Retain all six signed terms rather than only the sum. Find two different settings with zero net flux and show that their point fields can differ.

Close six oriented faces without inferring a uniform field

Worked teaching model · synthetic values · Box 0≤x≤2 m,0≤y,z≤1 m with outward normals. Prescribed electrostatic field E=(a x+3,b y−2,1−z) in consistent SI, hence curl zero. Nonzero divergence implies stipulated local charge density. Uniform offsets affect face fluxes but cancel in closed flux. Rounded K=9×10⁹ fixes epsilon0=1/(4πK) consistently.

Reset keeps your prediction, captures and practice history.

East field through the two opposing faces

east field (N/C)x coordinate (m)0250

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: prescribed affine field (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for East field through the two opposing faces

prescribed affine field

x coordinate (m)east field (N/C)
03
0.0253.025
0.053.05
0.0753.075
0.13.1
0.1253.125
0.153.15
0.1753.175
0.23.2
0.2253.225
0.253.25
0.2753.275
0.33.3
0.3253.325
0.353.35
0.3753.375
0.43.4
0.4253.425
0.453.45
0.4753.475
0.53.5
0.5253.525
0.553.55
0.5753.575
0.63.6
0.6253.625
0.653.65
0.6753.675
0.73.7
0.7253.725
0.753.75
0.7753.775
0.83.8
0.8253.825
0.853.85
0.8753.875
0.93.9
0.9253.925
0.953.95
0.9753.975
14
1.0254.025
1.054.05
1.0754.075
1.14.1
1.1254.125
1.154.15
1.1754.175
1.24.2
1.2254.225
1.254.25
1.2754.275
1.34.3
1.3254.325
1.354.35
1.3754.375
1.44.4
1.4254.425
1.454.45
1.4754.475
1.54.5
1.5254.525
1.554.55
1.5754.575
1.64.6
1.6254.625
1.654.65
1.6754.675
1.74.7
1.7254.725
1.754.75
1.7754.775
1.84.8
1.8254.825
1.854.85
1.8754.875
1.94.9
1.9254.925
1.954.95
1.9754.975
25

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Left x face outward flux-3N m²/C
Right x face outward flux5N m²/C
Lower y face outward flux4N m²/C
Upper y face outward flux-4N m²/C
Lower z face outward flux-2N m²/C
Upper z face outward flux0N m²/C
Total closed flux0N m²/C
Local divergence0N/C/m
Inferred uniform volume charge density0C/m³
Enclosed charge0C
Field magnitude at origin3.741657N/C

Zero enclosed net charge or zero closed flux does not imply zero local electric field.

Outward normals reverse the signs on the left, lower-y and lower-z faces. Summing gives 2(a+b−1), equal to volume 2 m³ times divergence a+b−1. Uniform field offsets cancel from net flux but remain in local fields and individual face fluxes. Gauss law constrains an integral; without additional symmetry it does not authorize replacing a varying field by flux divided by total area.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

Zero enclosed net charge or zero closed flux does not imply zero local electric field.

Outward normals reverse the signs on the left, lower-y and lower-z faces. Summing gives 2(a+b−1), equal to volume 2 m³ times divergence a+b−1. Uniform field offsets cancel from net flux but remain in local fields and individual face fluxes. Gauss law constrains an integral; without additional symmetry it does not authorize replacing a varying field by flux divided by total area.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Define the geometry and reference

Gauss law relates a closed-surface flux to net enclosed charge. It does not say every field on that surface is uniform, nor that zero net charge means zero field. A useful test case is an affine field whose constant offsets affect individual faces but cancel from their closed sum.

Derive the integral or gradient

Use the box 0≤x≤2 m and 0≤y,z≤1 m with outward normals. The prescribed field is E=(a x+3,b y−2,1−z) in consistent SI. The left and right face fluxes are −3 and 2a+3. The lower and upper y faces have area 2 m² and fluxes 4 and 2b−4. The z faces contribute −2 and 0. Summing gives 2(a+b−1).

Check the inference boundary

The same result is volume 2 m³ times divergence a+b−1. Here divergence means the sum of the component derivatives with respect to their own coordinates. Gauss law implies local density ε0(a+b−1), using ε0=1/(4πK) consistently with rounded K=9×10⁹. The field has zero curl and is a possible electrostatic field under its stipulated local source and boundary conditions; the box alone does not specify its distant sources.

Worked original case

For a=1 and b=0, the six outward fluxes are −3,5,4,−4,−2,0 N m²/C, summing to zero. Yet at the origin E=(3,−2,1) N/C and magnitude √14 N/C. Zero enclosed net charge therefore does not establish zero field. At a=2,b=1 the closed flux is 4 N m²/C.

Investigation

Change a and b separately, predicting which face pairs change. Retain all six signed terms rather than only the sum. Find two different settings with zero net flux and show that their point fields can differ.

Changed-case practice

Try the changed case before feedback

For a=2 and b=−1 in the stated box field, find total outward flux in N m²/C.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original calculations checked 30 October 2026 against the primary explanation. All source distributions, fields and readings are hypothetical. This is not a physical high-voltage or electrical handling activity, and public numerical feedback does not establish independent mastery. Preserve first predictions, critique, revision and newly assigned work in the separate retained course workspace.

Apply

What follows from zero closed electric flux without additional symmetry?

Public practice checks a specific claim. It does not establish independent mastery.

Which geometry, calibration or source assumption could fail while an exact arithmetic fit remains possible?

Continue

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