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SCIENCE · INVESTIGATE AND EXPLAIN

Derive local uniformity instead of matching one amplitude

An on-axis loop integral cancels transverse components while retaining the common axial projection. One loop of radius R and current I gives Bz=μ0IR²/[2(R²+z²)^(3/2)]. Two identical, same-current coaxial loops centered at ±d/2 add shifted copies of this result. In the workbench R=1 m and I=2 A.

Learning outcome: Compare separation ratios 0.5,1,1.5 at z/R=0,0.25,0.5. Retain center amplitude, second derivative and normalized departure as separate evidence. Explain why the zero-curvature profile still changes at finite distance.

Starting recap

Review cross products, source integration measures, line integrals, differential initial states and signed work. Distinguish symmetry premises from integral laws.

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Try

At d=R=1 m, the center field is 2μ0/(1.25)^(3/2)≈1.798352 µT and the second derivative is exactly zero. At separation d=0.5 m the curvature is negative; at d=1.5 m it is positive. All three center first derivatives vanish, so first-derivative symmetry alone does not select the flat-profile spacing.

Open the experiment

Predict

What distinguishes d=R from other symmetric loop separations?

Experiment

Compare separation ratios 0.5,1,1.5 at z/R=0,0.25,0.5. Retain center amplitude, second derivative and normalized departure as separate evidence. Explain why the zero-curvature profile still changes at finite distance.

Compare center strength with spatial uniformity

Worked teaching model · synthetic values · Two identical coaxial loops radius 1 m, current 2 A each with the same axial moment, centered at z=±d/2. On-axis Biot–Savart field only. d=R cancels the center second derivative; this local condition does not make an exactly uniform field everywhere.

Reset keeps your prediction, captures and practice history.

Paired-loop axial field normalized to its center

field divided by center fieldz divided by radius-1110

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: same-current coaxial loops (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Paired-loop axial field normalized to its center

same-current coaxial loops

z divided by radiusfield divided by center field
-10.6192642
-0.9750.6384682
-0.950.6577861
-0.9250.6771575
-0.90.6965178
-0.8750.7157982
-0.850.734926
-0.8250.7538258
-0.80.7724203
-0.7750.790631
-0.750.8083796
-0.7250.825589
-0.70.8421847
-0.6750.8580964
-0.650.8732587
-0.6250.8876131
-0.60.901109
-0.5750.9137044
-0.550.9253677
-0.5250.9360776
-0.50.9458242
-0.4750.954609
-0.450.9624448
-0.4250.9693558
-0.40.9753764
-0.3750.9805509
-0.350.984932
-0.3250.9885798
-0.30.9915603
-0.2750.9939433
-0.250.9958016
-0.2250.9972085
-0.20.9982365
-0.1750.9989554
-0.150.9994311
-0.1250.9997235
-0.10.9998861
-0.0750.9999638
-0.050.9999928
-0.0250.9999996
01
0.0250.9999996
0.050.9999928
0.0750.9999638
0.10.9998861
0.1250.9997235
0.150.9994311
0.1750.9989554
0.20.9982365
0.2250.9972085
0.250.9958016
0.2750.9939433
0.30.9915603
0.3250.9885798
0.350.984932
0.3750.9805509
0.40.9753764
0.4250.9693558
0.450.9624448
0.4750.954609
0.50.9458242
0.5250.9360776
0.550.9253677
0.5750.9137044
0.60.901109
0.6250.8876131
0.650.8732587
0.6750.8580964
0.70.8421847
0.7250.825589
0.750.8083796
0.7750.790631
0.80.7724203
0.8250.7538258
0.850.734926
0.8750.7157982
0.90.6965178
0.9250.6771575
0.950.6577861
0.9750.6384682
10.6192642

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Center axial field1.79835e-6T
Observer axial field1.70093e-6T
Relative departure from center-0.05417581ratio
Center second axial derivative0T/m²
Center first axial derivative by symmetry0T/m

Symmetry removes the first derivative for every separation; only a special separation removes the second.

Integrating one loop cancels transverse components and gives Bz=mu0 I R²/[2(R²+z²)^(3/2)]. Superpose two shifted loops. At their midpoint Bprime=0 by reflection symmetry. Differentiation gives Bsecond=3 mu0 I R²(d²−R²)/(R²+d²/4)^(7/2), so d=R cancels the quadratic term. Higher-order terms remain: matching a center value or canceling one derivative does not establish uniformity over an arbitrary region.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

Symmetry removes the first derivative for every separation; only a special separation removes the second.

Integrating one loop cancels transverse components and gives Bz=mu0 I R²/[2(R²+z²)^(3/2)]. Superpose two shifted loops. At their midpoint Bprime=0 by reflection symmetry. Differentiation gives Bsecond=3 mu0 I R²(d²−R²)/(R²+d²/4)^(7/2), so d=R cancels the quadratic term. Higher-order terms remain: matching a center value or canceling one derivative does not establish uniformity over an arbitrary region.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Specify sources, directions and independent premises

An on-axis loop integral cancels transverse components while retaining the common axial projection. One loop of radius R and current I gives Bz=μ0IR²/[2(R²+z²)^(3/2)]. Two identical, same-current coaxial loops centered at ±d/2 add shifted copies of this result. In the workbench R=1 m and I=2 A.

Derive the integral or vector evolution

Reflection symmetry makes the center first derivative zero for every separation. Differentiate again: the pair center curvature is 3μ0IR²(d²−R²)/(R²+d²/4)^(7/2). It vanishes when d=R, the Helmholtz spacing. This removes the quadratic term of the local Taylor expansion, not all spatial dependence.

Check energy, symmetry and evidence limits

A matched center value alone does not identify a uniform field. The workbench normalizes each profile by its own center value so shape can be compared without confusing amplitude changes with curvature changes. At d=R higher-order departures remain, and off-axis structure would require its own field analysis. No coil construction or field-exposure procedure is requested.

Worked original case

At d=R=1 m, the center field is 2μ0/(1.25)^(3/2)≈1.798352 µT and the second derivative is exactly zero. At separation d=0.5 m the curvature is negative; at d=1.5 m it is positive. All three center first derivatives vanish, so first-derivative symmetry alone does not select the flat-profile spacing.

Investigation

Compare separation ratios 0.5,1,1.5 at z/R=0,0.25,0.5. Retain center amplitude, second derivative and normalized departure as separate evidence. Explain why the zero-curvature profile still changes at finite distance.

Changed-case practice

Try the changed case before feedback

For the taught loop pair with R=1 m, at what separation d in metres does the center curvature vanish?

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original derivations and synthetic numerical evidence checked 31 October 2026 against the primary explanation. The rounded teaching permeability is not asserted to be an exact modern SI constant; NIST CODATA 2022 lists its measured uncertainty. No live electrical construction, beam, strong-magnet handling, medical or physical certification claim is requested. Public feedback remains separate from retained first work, critique, revision and fresh assigned evidence.

Apply

What distinguishes d=R from other symmetric loop separations?

Public practice checks a specific claim. It does not establish independent mastery.

Which source geometry, symmetry, initial state or calibration premise is necessary, and what independent observation could reject it?

Continue

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