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SCIENCE · INVESTIGATE AND EXPLAIN

Distinguish zero net force from stable orientation

A closed loop in a uniform magnetic field can have zero net force and a nonzero torque. For constant B, the integral of I dl crossed with B vanishes because the closed displacement integral is zero. Opposite forces acting at separated parts of the loop can nevertheless form a couple.

Learning outcome: Compare 0°,60°,90°,180° at the same field. Predict the sign of torque from the energy slope before reading the ledger. Explain why zero force, zero torque and a stable energy minimum are three distinct statements.

Starting recap

Review cross products, source integration measures, line integrals, differential initial states and signed work. Distinguish symmetry premises from integral laws.

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Try

At B=1 T and θ=60°, torque toward increasing angle is −0.3√3 N m≈−0.519615 N m and U=−0.3 J. Slowly rotating from alignment requires external work 0.3 J. Anti-alignment has zero torque but U=+0.6 J, the unstable maximum rather than the stable minimum.

Open the experiment

Predict

Why is the anti-aligned zero-torque state unstable in this ideal model?

Experiment

Compare 0°,60°,90°,180° at the same field. Predict the sign of torque from the energy slope before reading the ledger. Explain why zero force, zero torque and a stable energy minimum are three distinct statements.

Distinguish zero net force from a rotational tendency

Worked teaching model · synthetic values · Rigid rectangular loop .5 by .6 m carries maintained current 2 A, magnetic moment .6 A m². Uniform imposed B, angle between moment and B. Torque component is defined positive toward increasing angle. Effective orientation potential U=−m dot B assumes fixed current and imposed field, not the entire source self-energy.

Reset keeps your prediction, captures and practice history.

Effective orientation energy under fixed current

orientation energy (J)moment angle (degrees)01800.6-0.6

Unlike graph quantities rescale independently; read units and values, not screen angles. 1: uniform imposed field (solid). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Effective orientation energy under fixed current

uniform imposed field

moment angle (degrees)orientation energy (J)
0-0.6
2.25-0.5995374
4.5-0.5981504
6.75-0.5958411
9-0.592613
11.25-0.5884712
13.5-0.583422
15.75-0.5774731
18-0.5706339
20.25-0.5629148
22.5-0.5543277
24.75-0.5448859
27-0.5346039
29.25-0.5234976
31.5-0.5115841
33.75-0.4988818
36-0.4854102
38.25-0.4711902
40.5-0.4562436
42.75-0.4405935
45-0.4242641
47.25-0.4072804
49.5-0.3896688
51.75-0.3714564
54-0.3526712
56.25-0.3333421
58.5-0.3134991
60.75-0.2931727
63-0.2723943
65.25-0.2511958
67.5-0.2296101
69.75-0.2076702
72-0.1854102
74.25-0.1628643
76.5-0.1400672
78.75-0.1170542
81-0.09386068
83.25-0.07052244
85.5-0.04707546
87.75-0.02355589
90-3.67394e-17
92.250.02355589
94.50.04707546
96.750.07052244
990.09386068
101.250.1170542
103.50.1400672
105.750.1628643
1080.1854102
110.250.2076702
112.50.2296101
114.750.2511958
1170.2723943
119.250.2931727
121.50.3134991
123.750.3333421
1260.3526712
128.250.3714564
130.50.3896688
132.750.4072804
1350.4242641
137.250.4405935
139.50.4562436
141.750.4711902
1440.4854102
146.250.4988818
148.50.5115841
150.750.5234976
1530.5346039
155.250.5448859
157.50.5543277
159.750.5629148
1620.5706339
164.250.5774731
166.50.583422
168.750.5884712
1710.592613
173.250.5958411
175.50.5981504
177.750.5995374
1800.6

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Loop magnetic moment magnitude0.6A m²
Torque toward increasing angle-0.5196152N m
Effective orientation energy-0.3J
External quasistatic work from aligned state0.3J
Net force in uniform field0N
Angular curvature of effective energy0.3J/rad²

A uniform field gives zero net force on the closed loop but can produce a nonzero torque.

Integrate I dl cross B around a closed loop: constant B factors out and the closed displacement integral is zero. Opposite forces at separated sides still form a couple, giving tau=m cross B with m=I A n. For the declared increasing-angle coordinate tau_theta=−mB sin(theta)=−dU/dtheta and U=−mB cos(theta). Both aligned and anti-aligned orientations have zero torque, but their energy curvatures have opposite signs. This effective fixed-current interaction energy is not an accounting of all circuit-source self-energy.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

A uniform field gives zero net force on the closed loop but can produce a nonzero torque.

Integrate I dl cross B around a closed loop: constant B factors out and the closed displacement integral is zero. Opposite forces at separated sides still form a couple, giving tau=m cross B with m=I A n. For the declared increasing-angle coordinate tau_theta=−mB sin(theta)=−dU/dtheta and U=−mB cos(theta). Both aligned and anti-aligned orientations have zero torque, but their energy curvatures have opposite signs. This effective fixed-current interaction energy is not an accounting of all circuit-source self-energy.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Specify sources, directions and independent premises

A closed loop in a uniform magnetic field can have zero net force and a nonzero torque. For constant B, the integral of I dl crossed with B vanishes because the closed displacement integral is zero. Opposite forces acting at separated parts of the loop can nevertheless form a couple.

Derive the integral or vector evolution

The rectangular loop here is 0.5 by 0.6 m with maintained current 2 A, so its moment magnitude is m=IA=0.6 A m². Let θ be the angle from the imposed field to its moment, positive toward increasing misalignment. The angular torque is −mB sinθ, and the effective orientation potential is U=−mB cosθ. Differentiating U checks the torque sign.

Check energy, symmetry and evidence limits

Both θ=0 and θ=π have zero torque, but U has positive curvature at alignment and negative curvature at anti-alignment. Thus zero torque alone does not establish stable equilibrium. The fixed-current interaction potential presumes maintained current and imposed field; it is not the total self-energy of every source circuit. No motor construction, magnet handling or actual energy-delivery claim is requested.

Worked original case

At B=1 T and θ=60°, torque toward increasing angle is −0.3√3 N m≈−0.519615 N m and U=−0.3 J. Slowly rotating from alignment requires external work 0.3 J. Anti-alignment has zero torque but U=+0.6 J, the unstable maximum rather than the stable minimum.

Investigation

Compare 0°,60°,90°,180° at the same field. Predict the sign of torque from the energy slope before reading the ledger. Explain why zero force, zero torque and a stable energy minimum are three distinct statements.

Changed-case practice

Try the changed case before feedback

For B=2 T, find the external quasistatic work in joules to rotate the loop from alignment to 90°.

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original derivations and synthetic numerical evidence checked 31 October 2026 against the primary explanation. The rounded teaching permeability is not asserted to be an exact modern SI constant; NIST CODATA 2022 lists its measured uncertainty. No live electrical construction, beam, strong-magnet handling, medical or physical certification claim is requested. Public feedback remains separate from retained first work, critique, revision and fresh assigned evidence.

Apply

Why is the anti-aligned zero-torque state unstable in this ideal model?

Public practice checks a specific claim. It does not establish independent mastery.

Which source geometry, symmetry, initial state or calibration premise is necessary, and what independent observation could reject it?

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