Build a signed source-to-observer field kernel
A point-source field is a vector-valued function of the observer position. Keep the source coordinate separate from the observation coordinate: the displacement P−rs points from source to observer, and its magnitude enters the inverse-square law. Combining the unit vector with the distance gives Kq(P−rs)/|P−rs|³. This representation makes sign and geometry auditable rather than hiding them in an arrow sketch.
Learning outcome: Predict the north-field sign at x=−0.5,0,+0.5 m with y=1 m before opening the ledger. Retain each displacement and signed component. Reflect the observer across the vertical axis and identify which component is even and which is odd.
Starting recap
Review signed vector components, definite integrals, radians, density units and elementary derivatives. Distinguish observer coordinates from source integration coordinates.
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Try
At P=(0,1) m, each distance is √2 m. The positive source contributes (9,9)/(2√2) N/C and the negative source contributes (9,−9)/(2√2) N/C. Thus E=(9/√2,0) N/C. A separate −2 nC test charge feels Fx=−18×10⁻⁹/√2 N, opposite the field.
Open the experimentPredict
At P=(0,1) m, which net field follows from the stated opposite sources?
Experiment
Predict the north-field sign at x=−0.5,0,+0.5 m with y=1 m before opening the ledger. Retain each displacement and signed component. Reflect the observer across the vertical axis and identify which component is even and which is odd.
Construct source-to-observer displacement vectors
Worked teaching model · synthetic values · Prescribed +1 nC at (−1,0) m and −1 nC at (1,0) m in vacuum. Observer always lies above the source line. Use rounded K=9×10^9 N m²/C². Field excludes a source acting on itself; force is illustrated for a separate −2 nC test charge without source rearrangement.
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Source-to-observer displacement geometry
Spatial axes use the same pixels per physical unit, preserving geometry. 1: positive source to observer displacement (solid).2: negative source to observer displacement, not field direction (dashed). Joined curves show the supplied model, not additional observations.
Equivalent numerical coordinates for Source-to-observer displacement geometry
positive source to observer displacement
| east position (m) | north position (m) |
|---|---|
| -1 | 0 |
| 0.5 | 1 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
negative source to observer displacement, not field direction
| east position (m) | north position (m) |
|---|---|
| 1 | 0 |
| 0.5 | 1 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
| Quantity | Value | Unit |
|---|---|---|
| Positive-source east field | 2.304139 | N/C |
| Positive-source north field | 1.536093 | N/C |
| Negative-source east field | 3.219938 | N/C |
| Negative-source north field | -6.439876 | N/C |
| Total east field | 5.524077 | N/C |
| Total north field | -4.903783 | N/C |
| Field magnitude | 7.386644 | N/C |
| Negative test-charge east force | -1.10482e-8 | N |
| Negative test-charge north force | 9.80757e-9 | N |
The signed source charge multiplies the source-to-observer displacement divided by its cubed length.
For each source use E=Kq(P−rs)/|P−rs|³. The displacement vector always points from source to observer; a negative q reverses the resulting field, not the geometry. Sum components before taking a magnitude. F=qtest E changes sign for a negative test charge; the source field itself does not.
Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.
The signed source charge multiplies the source-to-observer displacement divided by its cubed length.
For each source use E=Kq(P−rs)/|P−rs|³. The displacement vector always points from source to observer; a negative q reverses the resulting field, not the geometry. Sum components before taking a magnitude. F=qtest E changes sign for a negative test charge; the source field itself does not.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
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Public practice checks a specific claim. It does not establish independent mastery.
Which geometry, calibration or source assumption could fail while an exact arithmetic fit remains possible?
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Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
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