Infer a field cancellation from signed source contributions
Separate gravitational field from test-object force and preserve vector directions in superposition.
Learning outcome: Compare right masses 1,5,9 at positions 1,2,3. Compute signed fields and derive the between-source root; explain why adding magnitudes would miss it.
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Resolve recipient-specific forces, integrate the stated model and test its domain and constraints.
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With normalized G1,left mass 4,right mass 1 at separation 4 m, field at midpoint is−.75 model units and the null is 8/3 m from the left.
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Must the zero-field point lie halfway between two unequal positive sources?
Experiment
Compare right masses 1,5,9 at positions 1,2,3. Compute signed fields and derive the between-source root; explain why adding magnitudes would miss it.
Locate a gravitational-field cancellation without scalar addition
Worked teaching model · synthetic values · Two fixed point sources at x 0 and 4 m, left mass 4 reference units and right selected mass. Use normalized G=1 in declared model units. Evaluate between sources only, excluding singular endpoints. Passive test-mass force is proportional to field; source motion omitted.
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| Quantity | Value | Unit |
|---|---|---|
| Left-source field component | -1 | model field units |
| Right-source field component | 0.25 | model field units |
| Net field component | -0.75 | model field units |
| Between-source null coordinate | 2.66667 | m |
| Distance from null to right source | 1.33333 | m |
Opposing field vectors may cancel even while both source contributions are nonzero.
Solve 4/x²=Mright/(4−x)² with positive distances to obtain x=8/(2+sqrt(Mright)). Adding magnitudes would erase cancellation. Outside both sources their fields point the same way on this line, so this between-source root is the only finite collinear cancellation for positive masses.
Derive before checking. Retain contrasting captures and explain one assumption that could fail; calculated evidence is not actual laboratory work.
Opposing field vectors may cancel even while both source contributions are nonzero.
Solve 4/x²=Mright/(4−x)² with positive distances to obtain x=8/(2+sqrt(Mright)). Adding magnitudes would erase cancellation. Outside both sources their fields point the same way on this line, so this between-source root is the only finite collinear cancellation for positive masses.
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Does a vanishing net field imply that each gravitational interaction vanishes?
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