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SCIENCE · INVESTIGATE AND EXPLAIN

Parameterize work along competing planar paths

Use the line integral to distinguish a selected interaction, a net force and a conservative field.

Learning outcome: Compare A=1,B=2 with A=B=2. Independently parameterize both legs, then reverse one path to build a closed-loop argument. Retain a unit audit and explain the role of unspecified forces.

Starting recap

Derive the integral or derivative, preserve the system boundary, and reject physically inaccessible continuations.

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Try

A=1,B=2 gives curved work 40/3 J, horizontal-first work 16 J and vertical-first work 8 J. For A=B=2 all are 16 J.

Open the experiment

Predict

What makes these three path works agree within the supplied field family?

Experiment

Compare A=1,B=2 with A=B=2. Independently parameterize both legs, then reverse one path to build a closed-loop argument. Retain a unit audit and explain the role of unspecified forces.

Compare work along specified planar paths

Worked teaching model · synthetic values · Selected field F=(Ay,Bx). Paths connect (0,0) to (2,4) m: parabola y=x²/(1 m), or coordinate-aligned legs. Other path-maintaining interactions are unspecified; selected-field work alone is not necessarily net work.

Reset keeps your prediction, captures and practice history.

Parabolic line-integral integrand

dW/du (N)parameter u (m)02200

Axes rescale independently. Curves join sampled coordinates; a joining segment is not additional measured evidence. Read physical units rather than screen angles or apparent slopes.

Parabolic line-integral integrand: numerical coordinates
parameter u (m)dW/du (N)
00
0.050.0125
0.10.05
0.150.1125
0.20.2
0.250.3125
0.30.45
0.350.6125
0.40.8
0.451.0125
0.51.25
0.551.5125
0.61.8
0.652.1125
0.72.45
0.752.8125
0.83.2
0.853.6125
0.94.05
0.954.5125
15
1.055.5125
1.16.05
1.156.6125
1.27.2
1.257.8125
1.38.45
1.359.1125
1.49.8
1.4510.5125
1.511.25
1.5512.0125
1.612.8
1.6513.6125
1.714.45
1.7515.3125
1.816.2
1.8517.1125
1.918.05
1.9519.0125
220
Calculated values under the declared model
QuantityValueUnit
Parabolic-path selected work13.3333J
Horizontal-then-vertical work16J
Vertical-then-horizontal work8J
Leg-path work difference-8J
Conservative within this field family0flag

Parameterize both position and its differential before taking the dot product.

On r(u)=(u,u²), dr=(1,2u)du and F·dr=(A+2B)u²du in the stipulated SI scaling. When A=B, U=−Axy has this force as its negative gradient. For unequal coefficients the paths give different work; no single position-only potential describes this field.

Derive before checking. Retain contrasting captures and explain one assumption that could fail; calculated evidence is not actual laboratory work.

Parameterize both position and its differential before taking the dot product.

On r(u)=(u,u²), dr=(1,2u)du and F·dr=(A+2B)u²du in the stipulated SI scaling. When A=B, U=−Axy has this force as its negative gradient. For unequal coefficients the paths give different work; no single position-only potential describes this field.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Specify the vector field and the path

A line integral needs both the force vector and the differential displacement at each location. In the supplied SI scaling, F=(Ay,Bx) and the curved path is r(u)=(u,u²), from u=0 to 2. The coefficient of u² carries the required inverse-length unit; writing the numerical polynomial is not permission to add unlike dimensions.

Differentiate the path before taking the dot product

The tangent differential is dr=(1,2u)du. Along the curve F=(Au²,Bu), so F·dr=(A+2B)u²du. Integrating from 0 to 2 gives work 8(A+2B)/3. Multiplying a force magnitude by the straight-line endpoint distance would omit both varying direction and varying force.

Compare coordinate-aligned alternatives

All paths share endpoints (0,0) and (2,4). Along horizontal-then-vertical legs, the first leg contributes zero because y=0; the vertical leg gives Bx dy=2B dy, total 8B. Along vertical-then-horizontal legs, the first contributes zero because x=0; the second gives Ay dx=4A dx, total 8A. Reversing a path reverses its signed selected work.

Test the conservative condition

When A=B, all three results agree and the potential U=−Axy gives F=−gradient U. If A differs from B, the two leg paths differ by 8(A−B), so their closed traversal has nonzero work and no position-only potential represents this field over the region. Agreement on only one pair of paths would not prove all-path independence for an arbitrary unknown field.

Do not infer a free trajectory from a chosen path

The workbench prescribes a path and one force field. Other constraints or actuators may be required to maintain that path; they have not been shown to do zero work. Therefore the selected field’s work cannot automatically be equated with the object’s entire kinetic-energy change. State what would be needed to make that identification.

Worked original case

A=1,B=2 gives curved work 40/3 J, horizontal-first work 16 J and vertical-first work 8 J. For A=B=2 all are 16 J.

Investigation

Compare A=1,B=2 with A=B=2. Independently parameterize both legs, then reverse one path to build a closed-loop argument. Retain a unit audit and explain the role of unspecified forces.

Public numerical transfer practice

Try a new practice case

For A=B=3 in the given field, what is the work from (0,0) to (2,4) in joules?

This public, unsaved check is not a secure assessment. Explain the derivative, integral or boundary in the retained course evidence workspace.

Sources and evidence boundary

Original teaching, values and calculations, checked 30 October 2026 against the official calculus-based Mechanics framework and OpenStax work and kinetic energy. The numerical packets are supplied or generated, not measured apparatus records. No physical launch, machinery, loading or field intervention is requested. Public feedback and virtual captures do not establish independent mastery or supervised laboratory participation.

Apply

What makes these three path works agree within the supplied field family?

Public practice checks a specific claim. It does not establish independent mastery.

Why does path dependence prevent a single potential difference from replacing this selected-force integral?

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

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