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SCIENCE · INVESTIGATE AND EXPLAIN

Diagnose numerical overshoot in a stable physical model

Compare discretization error and stability against an exact same-time solution.

Learning outcome: Compare step ratios.5,1,1.5 and 2.5; retain recurrence multiplier and final time. Independently halve dt and double step count at one fixed final time.

Starting recap

Resolve recipient-specific forces, integrate the stated model and test its domain and constraints.

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Try

For dt/tau=.5 and four steps, Euler gives 3.75 m/s at 4 s; exact 4(1−e⁻²)≈3.45866.

Open the experiment

Predict

If a computed velocity oscillates around terminal speed, must the physical object oscillate?

Experiment

Compare step ratios.5,1,1.5 and 2.5; retain recurrence multiplier and final time. Independently halve dt and double step count at one fixed final time.

Distinguish numerical overshoot from physical dynamics

Worked teaching model · synthetic values · Original dv/dt=(4−v)/2 in SI units, v 0=0,tau 2 s. Forward Euler uses selected fixed dt, compared with exact exponential at the identical final time. Large steps intentionally expose numerical instability, not physical speed reversal.

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Euler sequence

velocity (m/s)time (s)043.750

Axes rescale independently. Curves join sampled coordinates; a joining segment is not additional measured evidence. Read physical units rather than screen angles or apparent slopes.

Euler sequence: numerical coordinates
time (s)velocity (m/s)
00
12
23
33.5
43.75

Exact comparison

velocity (m/s)time (s)043.458660

Axes rescale independently. Curves join sampled coordinates; a joining segment is not additional measured evidence. Read physical units rather than screen angles or apparent slopes.

Exact comparison: numerical coordinates
time (s)velocity (m/s)
00
0.1333330.257972
0.2666670.499307
0.40.725077
0.5333330.936287
0.6666671.13387
0.81.31872
0.9333331.49164
1.066671.65342
1.21.80475
1.333331.94633
1.466672.07878
1.62.20268
1.733332.3186
1.866672.42704
22.52848
2.133332.62338
2.266672.71217
2.42.79522
2.533332.87292
2.666672.94561
2.83.01361
2.933333.07723
3.066673.13674
3.23.19241
3.333333.2445
3.466673.29322
3.63.3388
3.733333.38145
3.866673.42134
43.45866
Calculated values under the declared model
QuantityValueUnit
Time step1s
Compared final time4s
Euler final velocity3.75m/s
Exact final velocity3.45866m/s
Signed global discrepancy0.291341m/s
Transient multiplier per step0.5ratio
Asymptotically stable Euler choice1flag

A numerical recurrence has its own stability constraint; the physical ODE remains well behaved.

Euler gives v[n+1]=v[n]+(dt/2)(4−v[n]); its transient multiplier is 1−dt/tau. Values above 1 for the ratio cause alternating overshoot; at 2 oscillations do not decay and beyond 2 they grow. Compare half steps at the same final time, not equal step counts.

Derive before checking. Retain contrasting captures and explain one assumption that could fail; calculated evidence is not actual laboratory work.

A numerical recurrence has its own stability constraint; the physical ODE remains well behaved.

Euler gives v[n+1]=v[n]+(dt/2)(4−v[n]); its transient multiplier is 1−dt/tau. Values above 1 for the ratio cause alternating overshoot; at 2 oscillations do not decay and beyond 2 they grow. Compare half steps at the same final time, not equal step counts.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

The Euler stability analysis in this lesson is optional numerical enrichment. It extends the core Newtonian and resistive-force model by distinguishing a numerical approximation from its exact solution; the detailed stability criterion is not presented as a required AP exam formula.

Separate physics from its numerical approximation

The original ODE is dv/dt=(4−v)/2 with v0=0. Its exact solution 4(1−e^(−t/2)) approaches 4 monotonically from below. Forward Euler replaces each short interval by a tangent step: v[n+1]=v[n]+dt(4−v[n])/2. That approximation is a separate mathematical object with its own error and stability constraints.

Derive the recurrence behavior

Set r=dt/tau, where tau=2 s, and define deviation e[n]=v[n]−4. Subtraction gives e[n+1]=(1−r)e[n], so v[n]=4[1−(1−r)^n]. For 0<r<1, the deviation decays without sign changes. For 1<r<2 it alternates sign while decaying, producing numerical overshoot absent from the exact rest-release solution.

Locate the stability boundary

At r=2 the multiplier is −1, so oscillations never decay. Above 2 its magnitude exceeds one and the numerical sequence diverges. The underlying physical ODE has not become unstable. A negative or enormous Euler result here is evidence of an unsuitable time step, not a newly discovered reversal or a violation of Newton’s law.

Compare at an identical physical time

With r=.5, dt=1 s and four steps reach 4 s. Euler gives 3.75 m/s, while exact 4(1−e⁻²)≈3.45866. Halving dt to.5 s requires eight steps to reach that same 4 s; Euler then gives 4(1−.75⁸)≈3.59955. The smaller error is a convergence check. Holding the step count fixed would compare different physical times and obscure that inference.

Transfer and interpret a special step

At r=.5 the first two values are 2 and 3 m/s. At r=1 Euler reaches equilibrium in one step, but the exact trajectory reaches it only asymptotically. A numerically convenient value is not automatically an accurate time history. Retain the exact reference or a justified refinement study and state which quantity is being compared.

Extend cautiously

This example has a known solution and a linear stability calculation. Nonlinear force models can have changing time scales and event boundaries. A solver must check those limits rather than assume a step size that worked once is universally safe. No physical control system or real-time controller is implemented by this teaching recurrence.

Public numerical transfer practice

Try a new practice case

For v0=0,terminal 4 and Euler ratio r=.5, find velocity after two steps.

This public, unsaved check is not a secure assessment. Explain the derivative, integral or boundary in the retained course evidence workspace.

Sources and evidence boundary

Original prose, models and cases, checked 30 October 2026 against the current official AP Physics C Mechanics CED and OpenStax University Physics. Values are supplied or generated, not measured apparatus records. No physical launch, suspension, moving machinery or practical safety validation is requested. Virtual captures and public answers do not certify independent mastery or laboratory participation.

Apply

For v[n+1]=v[n]+r(4−v[n]), the transient multiplier is:

Public practice checks a specific claim. It does not establish independent mastery.

Why is comparing equal step counts at different dt not a convergence test at the same physical time?

Continue

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