Read rotational work from an angle-dependent torque
A tangential force acting through a small arc transfers work FₜΔs. With Δs=rΔθ and τ=rFₜ, the same transfer is τΔθ. For a constant signed torque about a fixed axis, W=τΔθ, where radians are used. Torque and angular displacement with opposite signs transfer negative work.
Learning outcome: Compare start/end torques (4,−2), (2,−2) and (−4,−4). Compute each signed area and energy change. Sketch the cumulative work, identify where it reaches an extreme, and check that kinetic energy never reaches zero before the endpoint.
Starting recap
Review axis-specific inertia, force application locations, torque-angle versus torque-time area, energy conservation and system boundaries.
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Try
The net torque changes linearly from +4 to −2 N m over 2 rad. Work is ½×(4−2)×2=2 J. With initial rotational energy 20 J and I=2 kg m², final energy is 22 J and positive angular velocity is √22≈4.690 rad/s. The negative late torque removes some energy but does not reverse the rotor in this supported case.
Open the experimentPredict
Can a graph include both positive and negative torque while still adding net energy?
Experiment
Compare start/end torques (4,−2), (2,−2) and (−4,−4). Compute each signed area and energy change. Sketch the cumulative work, identify where it reaches an extreme, and check that kinetic energy never reaches zero before the endpoint.
Read a torque-angle area without confusing it with impulse
Worked teaching model · synthetic values · Net torque varies linearly with angle over0–2 rad about a fixed axis. Inertia2 kg m² and initial rotational kinetic energy20 J. Positive initial angular velocity; supported settings keep kinetic energy positive along the entire path. No torque-time history is supplied.
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Axes rescale with settings; compare numerical values, not screen angles or apparent lengths. Solid/points show the selected model relationship or observations; the dashed comparison is explained below.
| Quantity | Value | Unit |
|---|---|---|
| Signed net work | 2 | J |
| Initial rotational kinetic energy | 20 | J |
| Final rotational kinetic energy | 22 | J |
| Final positive angular velocity | 4.69042 | rad/s |
Accessible plot coordinates
| angular displacement (rad) | net torque (N m) |
|---|---|
| 0 | 4 |
| 0.1 | 3.7 |
| 0.2 | 3.4 |
| 0.3 | 3.1 |
| 0.4 | 2.8 |
| 0.5 | 2.5 |
| 0.6 | 2.2 |
| 0.7 | 1.9 |
| 0.8 | 1.6 |
| 0.9 | 1.3 |
| 1 | 1 |
| 1.1 | 0.7 |
| 1.2 | 0.4 |
| 1.3 | 0.1 |
| 1.4 | -0.2 |
| 1.5 | -0.5 |
| 1.6 | -0.8 |
| 1.7 | -1.1 |
| 1.8 | -1.4 |
| 1.9 | -1.7 |
| 2 | -2 |
The signed torque-angle area changes rotational kinetic energy.
A linear torque profile gives W=½(τstart+τend)Δθ. Positive and negative areas can cancel without the rotor having been at rest. Torque-time area would instead be angular impulse; elapsed time is not supplied here.
The signed torque-angle area changes rotational kinetic energy.
A linear torque profile gives W=½(τstart+τend)Δθ. Positive and negative areas can cancel without the rotor having been at rest. Torque-time area would instead be angular impulse; elapsed time is not supplied here.
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What additional information would be required to infer angular impulse from a torque-angle graph?
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