Carry timing bounds into an inferred spring constant
A period measurement must count complete cycles using the same phase and direction at both ends. Timing from the positive endpoint to the negative endpoint gives half a cycle, not a full one. Repeating a recognizable crossing can help, but a mistaken cycle count produces a systematic error that averaging does not fix.
Learning outcome: At assigned timing error +0.1 s, compare N=1,5 and10. Save inferred periods and stiffness bounds. Check whether the true20 N/m is compatible, and explain which uncertainty sources the recipe deliberately excludes.
Starting recap
Review Newton’s second law, radians, sine/cosine graphs, energy and momentum boundaries, and bounded measurement errors.
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Try
Five cycles observed in 7.00±0.20 s give T=1.40 s with bounds 1.36 to 1.44 s. For exact m=1 kg, inferred k≈20.14 N/m, with bounds 4π²/1.44²≈19.04 and 4π²/1.36²≈21.34 N/m. The interval describes the stipulated bound, not a 95% confidence interval.
Open the experimentPredict
If the same ±0.20 s total-time bound applies to ten rather than one cycle, what happens to the period bound?
Experiment
At assigned timing error +0.1 s, compare N=1,5 and10. Save inferred periods and stiffness bounds. Check whether the true20 N/m is compatible, and explain which uncertainty sources the recipe deliberately excludes.
Infer stiffness from bounded multi-cycle timing
Worked teaching model · synthetic values · Synthetic true oscillator m=1 kg,k=20 N/m. Observed total time=N×true period+assigned error. Each total-time reading has a stipulated ±0.2 s bound; exact mass and cycle count. Bounds are not a statistical confidence interval.
Reset keeps your prediction, captures and practice history.
| Quantity | Value | Unit |
|---|---|---|
| Observed total elapsed time | 7.12481 | s |
| Inferred period | 1.42496 | s |
| Period lower bound | 1.38496 | s |
| Period upper bound | 1.46496 | s |
| Inferred spring constant | 19.44252 | N/m |
| Stiffness lower bound | 18.39528 | N/m |
| Stiffness upper bound | 20.5818 | N/m |
Accessible plot coordinates
| coordinate | value |
|---|
A fixed elapsed-time bound becomes a smaller per-cycle period bound when more cycles are timed.
Divide total time and its bound by N. Because k=4π²m/T² decreases with T, the largest period gives the lowest stiffness. This does not remove systematic clock calibration error or missed-cycle errors; mass uncertainty is excluded here.
A fixed elapsed-time bound becomes a smaller per-cycle period bound when more cycles are timed.
Divide total time and its bound by N. Because k=4π²m/T² decreases with T, the largest period gives the lowest stiffness. This does not remove systematic clock calibration error or missed-cycle errors; mass uncertainty is excluded here.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
Why can repeated timing agree very closely yet remain systematically wrong?
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