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SCIENCE · INVESTIGATE AND EXPLAIN

Infer a spring constant and retain the restoring sign

An ideal spring near its equilibrium length exerts a restoring force Fₛ=−kx, where x is signed displacement from the equilibrium configuration and k is positive. Extension to the right produces a leftward force; compression to the left produces a rightward force. The minus sign describes direction, not a negative stiffness.

Learning outcome: Compare positive, zero and negative extension at fixed k. Then compare two spring constants at the same extension. Fit a slope from two table values and distinguish the spring’s force from an external holding force. Explain why a line through total length would need a nonzero intercept.

Starting recap

Review signed vectors, components, acceleration, graph slopes and system boundaries. Every force must name its agent and recipient.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

For k=60 N/m and x=+0.10 m, the spring force is−6 N and the external equilibrium holding force is+6 N. At x=−0.10 m the signs reverse. Comparing spring forces−3 and−9 N at extensions 0.05 and 0.15 m gives slope−6/0.10=−60 N/m.

Open the experiment

Predict

If extension reverses sign without changing its magnitude, which of force direction and force magnitude changes?

Experiment

Compare positive, zero and negative extension at fixed k. Then compare two spring constants at the same extension. Fit a slope from two table values and distinguish the spring’s force from an external holding force. Explain why a line through total length would need a nonzero intercept.

Calibrate a restoring spring force

Worked teaching model · synthetic values · An ideal massless spring obeys F_s=−kx about x=0. Positive x is extension to the right; negative x is compression. Valid only within the assigned ±0.20 m range. No mass dynamics, energy loss, buckling or beyond-elastic-limit behavior.

Reset keeps your prediction, captures and practice history.

Interaction arrows are grouped by recipient. For horizontal-only cart/block diagrams, balanced vertical interactions are omitted explicitly; this is a component diagram, not a claim that gravity vanished. For the spring case only the selected spring interaction is drawn; the opposite external holding force is tabulated but omitted from that diagram. For circular cases, the arrow is the required tension, not a claim it is available when the feasibility check fails. All arrows in one view share a scale; scale changes with controls. A zero force has no visible arrow. The force table supplies exact signs and units.

Spring end / attached objectF1: (-6, 0) N
Proposed-model interaction components — right and up are positive
RecipientInteractionFx (N)Fy (N)
Spring end / attached objectSpring restoring force-60
spring force (N)-0.21signed extension (m)12-12

Axes rescale with settings; use values, not screen angles. In the mass-position display, the dashed vertical line marks the center-of-mass coordinate, not an extra object.

Calculated primary plot coordinates
signed extension (m)spring force (N)
-0.212
-0.159
-0.16
-0.053
00
0.05-3
0.1-6
0.15-9
0.2-12
Bounded synthetic force-model results
QuantityValueUnit
Restoring force-6N
External holding force for equilibrium6N
Force-versus-extension slope-60N/m

The force opposes displacement from equilibrium; the negative slope has magnitude equal to the spring constant.

F=−kx uses signed extension, not total spring length. For a held object the external holding force is +kx. Do not extrapolate this ideal law beyond the assigned elastic interval.

The force opposes displacement from equilibrium; the negative slope has magnitude equal to the spring constant.

F=−kx uses signed extension, not total spring length. For a held object the external holding force is +kx. Do not extrapolate this ideal law beyond the assigned elastic interval.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

1. Orient: Infer a spring constant and retain the restoring sign

An ideal spring near its equilibrium length exerts a restoring force Fₛ=−kx, where x is signed displacement from the equilibrium configuration and k is positive. Extension to the right produces a leftward force; compression to the left produces a rightward force. The minus sign describes direction, not a negative stiffness.

2. Explain and derive

A graph of signed spring force against extension is a line with slope−k. A graph of the external force needed to hold it in equilibrium has slope+k, because that force balances the spring force. Label whose force you measured before interpreting the slope. Total spring length is not the same variable as extension.

Calibration requires a known equilibrium length, a force reference and several points within the elastic range. A residual pattern can reveal that the linear law is inadequate even when one point appears consistent. A constant length-zero error shifts the apparent intercept; it does not justify reporting a different stiffness from a single F/x ratio.

The bounded model uses an ideal massless spring within±0.20 m and does not model oscillation, damping, buckling or failure. A spring can store energy, but the present force analysis does not yet establish the later work–energy relation. Use supplied values rather than stretching an unknown physical spring to a predicted failure point.

3. Work an example

For k=60 N/m and x=+0.10 m, the spring force is−6 N and the external equilibrium holding force is+6 N. At x=−0.10 m the signs reverse. Comparing spring forces−3 and−9 N at extensions 0.05 and 0.15 m gives slope−6/0.10=−60 N/m.

4. Predict and investigate

Predict first: If extension reverses sign without changing its magnitude, which of force direction and force magnitude changes?

Compare positive, zero and negative extension at fixed k. Then compare two spring constants at the same extension. Fit a slope from two table values and distinguish the spring’s force from an external holding force. Explain why a line through total length would need a nonzero intercept. Use the lesson controls and record the settings with your evidence.

5. Transfer and explain

Try a new practice case

A spring-force graph changes from−2 N at x=0.02 m to−8 N at x=0.08 m. Find positive spring constant k.

This extra practice is not saved and does not award mastery. Record your first answer, explanation and whether you revealed help in the lesson notebook. Use the lesson’s saved question separately.

6. Reflect and retain evidence

What measurements would distinguish a wrong equilibrium-length zero from a genuinely nonlinear spring response?

Retain your first answer, force diagram, equations, units, assumptions and a changed-case prediction. Public worked checks are practice, not independent mastery evidence. Supplied synthetic outputs do not certify actual laboratory skill.

Framework and source notes

Original teaching prose and numerical cases. College Board AP Physics 1 CED, Unit 2 topic mapping: 2.8. Checked 30 October 2026. This is a content cross-reference, not AP authorization.

Apply

An ideal spring has k=80 N/m and signed extension x=−0.05 m. What signed spring force acts?

Public practice checks a specific claim. It does not establish independent mastery.

What measurements would distinguish a wrong equilibrium-length zero from a genuinely nonlinear spring response?

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

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