Distinguish internal recoil from an external impulse
The change in total momentum of a chosen system equals the net external impulse on that system. Internal interaction impulses occur in equal and opposite pairs and cancel when the members’ momentum changes are summed. They do not cancel on each individual object, whose momentum can change substantially.
Learning outcome: Hold internal impulse at 3 N s and compare external impulses−2,0 and+2 N s. Verify the sum of individual momentum changes. Then hold external impulse fixed and change internal impulse; identify which system quantity stays the same.
Starting recap
Review signed velocity components, force-time areas, kinetic energy and system boundaries. Keep momentum vectors distinct from scalar energy.
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With internal impulse 3 N s and no external impulse, final velocities are−3/2=−1.5 m/s and+3/3=+1 m/s. Their momentum sum is zero. Adding external impulse+2 N s to the first object changes its final momentum to−1 kg m/s; total final momentum is+2 and center velocity 2/5=0.4 m/s.
Open the experimentPredict
Can an internal stored-energy release change total momentum from zero without any external impulse?
Experiment
Hold internal impulse at 3 N s and compare external impulses−2,0 and+2 N s. Verify the sum of individual momentum changes. Then hold external impulse fixed and change internal impulse; identify which system quantity stays the same.
Separate internal recoil from external impulse
Worked teaching model · synthetic values · Two objects of 2 and 3 kg start at rest. A virtual internal stored-energy release gives object 1 impulse −J and object 2 +J; a selected external impulse also acts on object 1. No release apparatus or energetic-material procedure is specified.
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| Quantity | Value | Unit |
|---|---|---|
| Object 1 final momentum | -3 | kg m/s |
| Object 2 final momentum | 3 | kg m/s |
| System final momentum | 0 | kg m/s |
| Object 1 final velocity | -1.5 | m/s |
| Object 2 final velocity | 1 | m/s |
| Center-of-mass final velocity | 0 | m/s |
Accessible plot coordinates
| time (s) | net force (N) |
|---|
Internal recoil redistributes momentum without changing the system total.
Δp1=Jexternal−Jinternal and Δp2=Jinternal. Internal stored energy can become kinetic energy during release without creating system momentum. An impulse alone does not specify the work done by its external agent.
Internal recoil redistributes momentum without changing the system total.
Δp1=Jexternal−Jinternal and Δp2=Jinternal. Internal stored energy can become kinetic energy during release without creating system momentum. An impulse alone does not specify the work done by its external agent.
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A cart collides with a wall. Why is momentum of cart alone not conserved, and how would enlarging the system to include the wall and Earth change the accounting?
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