Connect a shared rotation to different point motions
Choose two marks on a rigid rotating surface at different distances from a fixed axis. Each mark completes a turn in the same time, so both have the same angular velocity. Their arc lengths differ: s=rθ for angle in radians. Dividing by time gives tangential speed v=r|ω|. A larger radius gives more distance per turn, not more turns per second.
Learning outcome: Hold radius at 0.4 m and compare ω=2 with ω=4 rad/s. Draw the two perpendicular acceleration components at the rightmost point and compare their magnitudes. Then halve radius while retaining the angular quantities; distinguish an angular comparison from a linear one.
Starting recap
Review signed graph slopes and areas, extended-body force diagrams, Newton’s laws and center-of-mass coordinates. State the rotation axis.
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For r=0.4 m, ω=3 rad/s and α=2 rad/s², the outer point has speed 1.2 m/s, tangential acceleration 0.8 m/s² and inward acceleration 3.6 m/s². The point at r/2 has half each linear quantity. The outer total acceleration is √(0.8²+3.6²)≈3.69 m/s², not 4.4 m/s².
Open the experimentPredict
If ω doubles at fixed α and radius, do tangential and centripetal acceleration change by the same factor?
Experiment
Hold radius at 0.4 m and compare ω=2 with ω=4 rad/s. Draw the two perpendicular acceleration components at the rightmost point and compare their magnitudes. Then halve radius while retaining the angular quantities; distinguish an angular comparison from a linear one.
Compare two points on one rotor
Worked teaching model · synthetic values · Two marked points at radius r and r/2 rotate about a fixed axis. At this instant angular acceleration is +2 rad/s². Angular velocity and acceleration are shared; linear velocity and tangential/centripetal acceleration depend on radius. No motion of the axis.
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Two marks on one fixed-axis rotor
Both marks lie to the right of the axis at this instant. Outer radius 0.4 m; inner radius 0.2 m. The positive tangential direction is upward; at zero angular velocity the speed is zero. Positive tangential acceleration is upward. Centripetal acceleration is leftward toward the axis.
Application locations and directions are meaningful; force arrows are schematic unless explicitly labeled otherwise. Exact quantities and units follow in the ledger.
| Quantity | Value | Unit |
|---|---|---|
| Shared angular velocity | 3 | rad/s |
| Shared angular acceleration | 2 | rad/s² |
| Outer speed | 1.2 | m/s |
| Outer tangential acceleration | 0.8 | m/s² |
| Outer centripetal acceleration | 3.6 | m/s² |
| Outer total acceleration magnitude | 3.68782 | m/s² |
| Inner speed | 0.6 | m/s |
| Inner tangential acceleration | 0.4 | m/s² |
| Inner centripetal acceleration | 1.8 | m/s² |
| Inner total acceleration magnitude | 1.84391 | m/s² |
Accessible plot coordinates
| time (s) | angular velocity (rad/s) |
|---|
One rigid rotation can give different linear speeds at different radii.
v=rω, at=rα, ac=rω². Tangential and inward components are perpendicular; neither alone is the full acceleration. A point on the axis has zero rotational linear speed despite the common angular velocity.
One rigid rotation can give different linear speeds at different radii.
v=rω, at=rα, ac=rω². Tangential and inward components are perpendicular; neither alone is the full acceleration. A point on the axis has zero rotational linear speed despite the common angular velocity.
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Why can a point have zero instantaneous speed yet nonzero tangential acceleration? What is its centripetal acceleration at that instant?
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