Separate equilibrium from being at rest
Newton’s first law describes inertial motion: with zero net external force, velocity remains constant. Rest is one possible constant velocity, not the only one. A cart gliding at 3 m/s on an ideal frictionless horizontal track requires no forward force to maintain that velocity.
Learning outcome: Begin with equal forces and verify constant nonzero velocity. Increase only the leftward force, then only the rightward force. Predict whether the object initially speeds up or slows down and whether it reverses within 2 s. Explain the motion using signs rather than “positive force means forward motion.”
Starting recap
Review signed vectors, components, acceleration, graph slopes and system boundaries. Every force must name its agent and recipient.
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Try
With 8 N left and 8 N right, the net horizontal force is 0 and the initial+3 m/s velocity remains+3 m/s after 2 s. With 12 N left and 8 N right, a=−2 m/s² and final velocity is 3−2×2=−1 m/s. The object has reversed even though the force directions never changed.
Open the experimentPredict
Can both forces be nonzero while acceleration is zero? Can velocity be zero while acceleration is nonzero?
Experiment
Begin with equal forces and verify constant nonzero velocity. Increase only the leftward force, then only the rightward force. Predict whether the object initially speeds up or slows down and whether it reverses within 2 s. Explain the motion using signs rather than “positive force means forward motion.”
Distinguish balanced forces from rest
Worked teaching model · synthetic values · A 2 kg point object starts at +3 m/s. Two constant horizontal forces act for 2 s. Vertical forces balance and no drag is modeled. Motion continues through any zero velocity.
Reset keeps your prediction, captures and practice history.
Interaction arrows are grouped by recipient. For horizontal-only cart/block diagrams, balanced vertical interactions are omitted explicitly; this is a component diagram, not a claim that gravity vanished. For the spring case only the selected spring interaction is drawn; the opposite external holding force is tabulated but omitted from that diagram. For circular cases, the arrow is the required tension, not a claim it is available when the feasibility check fails. All arrows in one view share a scale; scale changes with controls. A zero force has no visible arrow. The force table supplies exact signs and units.
| Recipient | Interaction | Fx (N) | Fy (N) |
|---|---|---|---|
| Object | Leftward agent | -8 | 0 |
| Object | Rightward agent | 8 | 0 |
Axes rescale with settings; use values, not screen angles. In the mass-position display, the dashed vertical line marks the center-of-mass coordinate, not an extra object.
| time (s) | velocity (m/s) |
|---|---|
| 0 | 3 |
| 0.25 | 3 |
| 0.5 | 3 |
| 0.75 | 3 |
| 1 | 3 |
| 1.25 | 3 |
| 1.5 | 3 |
| 1.75 | 3 |
| 2 | 3 |
| Quantity | Value | Unit |
|---|---|---|
| Net horizontal force | 0 | N |
| Acceleration | 0 | m/s² |
| Velocity after 2 s | 3 | m/s |
Balanced forces preserve the initial +3 m/s velocity; the object need not be at rest.
The forces are on the same object and may balance, but they are not a third-law pair merely because their magnitudes can match.
Balanced forces preserve the initial +3 m/s velocity; the object need not be at rest.
The forces are on the same object and may balance, but they are not a third-law pair merely because their magnitudes can match.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
How would repeated velocity measurements distinguish equilibrium from a turning point observed in a single image?
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