Connect local height energy to inverse-square gravity
Potential energy belongs to a system of interacting objects and its configuration, not to an isolated object without its interaction partner. For two nonoverlapping spherical masses, U=−GMm/r when zero is chosen at infinite separation. Finite-separation values are negative because positive work is needed to separate the attractive pair to infinity quasistatically.
Learning outcome: At initial radius ratio 1, compare outward increments 0.1,0.5 and 1 body radius. Compute exact and local-constant-field energy changes and their discrepancy. Repeat from initial radius ratio 3 and explain why the same absolute increment is a smaller relative change there.
Starting recap
Review signed force components, graph areas, speed squared and system boundaries. Distinguish an interaction force from an energy store or transfer.
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The hypothetical body has R=10 m and GM=1000 m³/s²; the test mass is 2 kg. Moving from 10 to 11 m changes U from−200 to−181.818 J, an increase 18.182 J. Initial g=10 m/s² gives local m g Δr=20 J, about 10% high. These rounded parameters describe an invented teaching body, not Earth.
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When an attractive pair moves farther apart, does negative potential energy become more negative or less negative?
Experiment
At initial radius ratio 1, compare outward increments 0.1,0.5 and 1 body radius. Compute exact and local-constant-field energy changes and their discrepancy. Repeat from initial radius ratio 3 and explain why the same absolute increment is a smaller relative change there.
Compare inverse-square and local gravitational energy
Worked teaching model · synthetic values · Hypothetical spherical body radius R=10 m and GM=1000 m³/s²; test mass 2 kg. U=−GMm/r uses zero at infinity. Both endpoints are outside the body; compare exact ΔU with m g_initial Δr. Fixed central body, no rotation or atmosphere.
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Axes rescale with settings; compare numerical values, not screen angles or apparent lengths. Solid/points show the selected model relationship or observations; the dashed comparison is explained below.
| Quantity | Value | Unit |
|---|---|---|
| Initial potential energy | -200 | J |
| Final potential energy | -181.81818 | J |
| Exact potential-energy increase | 18.18182 | J |
| Work done by gravity | -18.18182 | J |
| Local constant-field approximation | 20 | J |
| Approximation excess / exact increase | 0.1 | ratio |
Accessible plot coordinates
| position (m) | energy (J) |
|---|---|
| 10 | -200 |
| 12 | -166.66667 |
| 14 | -142.85714 |
| 16 | -125 |
| 18 | -111.11111 |
| 20 | -100 |
| 22 | -90.90909 |
| 24 | -83.33333 |
| 26 | -76.92308 |
| 28 | -71.42857 |
| 30 | -66.66667 |
| 32 | -62.5 |
| 34 | -58.82353 |
| 36 | -55.55556 |
| 38 | -52.63158 |
| 40 | -50 |
| 42 | -47.61905 |
| 44 | -45.45455 |
| 46 | -43.47826 |
| 48 | -41.66667 |
| 50 | -40 |
Moving outward makes gravitational potential energy less negative; gravity does negative work.
ΔU=GMm(1/ri−1/rf). The local m g_initial Δr approximation overestimates this outward increase because the field weakens with radius. It improves when Δr is small relative to ri.
Moving outward makes gravitational potential energy less negative; gravity does negative work.
ΔU=GMm(1/ri−1/rf). The local m g_initial Δr approximation overestimates this outward increase because the field weakens with radius. It improves when Δr is small relative to ri.
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How would a third interacting body change the potential-energy ledger? List the distinct pairs before writing their terms.
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