Draw forces on one object without double counting
A free-body diagram isolates one object or an explicitly stated system. Each arrow names an interaction acting on that object: Earth on cart, track on cart, or string on cart. Forces the cart exerts on something else belong on a different diagram. Velocity and acceleration can be shown nearby but are not additional force arrows.
Learning outcome: Compare pull angles 0°,30° and 60° at 20 N. Draw the three actual interaction arrows before using the ledger, then resolve components in equations. Check the vertical sum and the horizontal sum separately. Predict what would break if an unbounded pull lifted the cart off the track.
Starting recap
Review signed vectors, components, acceleration, graph slopes and system boundaries. Every force must name its agent and recipient.
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For m=4 kg, g=10 m/s² and a 20 N pull at 30°, the horizontal pull is 20 cos 30°≈17.32 N and the upward part is 10 N. Vertical balance gives N=40−10=30 N. Horizontal acceleration is 17.32/4≈4.33 m/s². Do not add a separate “net force” arrow to these interactions.
Open the experimentPredict
At fixed pull magnitude, does a steeper upward angle increase or decrease horizontal acceleration and normal force?
Experiment
Compare pull angles 0°,30° and 60° at 20 N. Draw the three actual interaction arrows before using the ledger, then resolve components in equations. Check the vertical sum and the horizontal sum separately. Predict what would break if an unbounded pull lifted the cart off the track.
Resolve an angled pull on a supported cart
Worked teaching model · synthetic values · A 4 kg cart on a horizontal frictionless track; g=10 m/s². No vertical acceleration while normal force is positive. Pull has horizontal and upward components. All supported settings maintain contact.
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Interaction arrows are grouped by recipient. For horizontal-only cart/block diagrams, balanced vertical interactions are omitted explicitly; this is a component diagram, not a claim that gravity vanished. For the spring case only the selected spring interaction is drawn; the opposite external holding force is tabulated but omitted from that diagram. For circular cases, the arrow is the required tension, not a claim it is available when the feasibility check fails. All arrows in one view share a scale; scale changes with controls. A zero force has no visible arrow. The force table supplies exact signs and units.
| Recipient | Interaction | Fx (N) | Fy (N) |
|---|---|---|---|
| Cart | Earth on cart: weight | 0 | -40 |
| Cart | Track on cart: normal | 0 | 30 |
| Cart | Pulling agent on cart | 17.32051 | 10 |
| Quantity | Value | Unit |
|---|---|---|
| Horizontal pull component | 17.32051 | N |
| Upward pull component | 10 | N |
| Normal force | 30 | N |
| Horizontal acceleration | 4.33013 | m/s² |
The normal force is not automatically equal to weight: the upward pull supports part of the load.
Vertical balance gives N+F sinθ−mg=0; horizontal dynamics gives F cosθ=ma. Draw the actual pull once, not both the pull and its components as additional forces.
The normal force is not automatically equal to weight: the upward pull supports part of the load.
Vertical balance gives N+F sinθ−mg=0; horizontal dynamics gives F cosθ=ma. Draw the actual pull once, not both the pull and its components as additional forces.
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Public practice checks a specific claim. It does not establish independent mastery.
For a frictionless inclined plane with angle 30°, derive acceleration from mg sinθ=ma. Explain why changing mass does not change this ideal acceleration.
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