Keep momentum while accounting for collision energy change
An inelastic collision reduces the system’s translational kinetic-energy subtotal while converting energy to other forms. A perfectly inelastic collision is the sticking case: both objects share one final velocity. Total momentum can still be conserved when external impulse is negligible. Total energy is not destroyed.
Learning outcome: Find mass choices giving a small or zero final velocity. Reconstruct initial and final momenta and energies separately. Compare the same masses with the elastic model; identify which conserved quantity is common to both and which distinguishes them.
Starting recap
Review signed velocity components, force-time areas, kinetic energy and system boundaries. Keep momentum vectors distinct from scalar energy.
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Try
With masses 2 and 3 kg approaching at+4 and−1 m/s, shared final velocity is(8−3)/5=1 m/s. Initial kinetic energy 17.5 J becomes final translational energy 2.5 J. The 15 J decrease equals½×(6/5)×5² and is accounted as other internal energy in the combined-system model.
Open the experimentPredict
Can the stuck pair be at rest even though both incoming objects had nonzero kinetic energy?
Experiment
Find mass choices giving a small or zero final velocity. Reconstruct initial and final momenta and energies separately. Compare the same masses with the elastic model; identify which conserved quantity is common to both and which distinguishes them.
Keep momentum while tracking kinetic-energy loss
Worked teaching model · synthetic values · Two approaching point objects start at +4 and −1 m/s and stick. External impulse is negligible. Lost translational kinetic energy becomes unpartitioned internal energy; no temperature or deformation mechanism is inferred.
Reset keeps your prediction, captures and practice history.
| Quantity | Value | Unit |
|---|---|---|
| Shared final velocity | 1 | m/s |
| Initial system momentum | 5 | kg m/s |
| Final system momentum | 5 | kg m/s |
| Initial kinetic energy | 17.5 | J |
| Final kinetic energy | 2.5 | J |
| Kinetic-energy decrease | 15 | J |
Accessible plot coordinates
| time (s) | net force (N) |
|---|
Sticking conserves isolated-system momentum, not the translational kinetic-energy subtotal.
v=(m1u1+m2u2)/(m1+m2). Energy decrease is ½[m1m2/(m1+m2)](u1−u2)². It becomes other internal energy; the model does not assign a temperature or claim energy destruction.
Sticking conserves isolated-system momentum, not the translational kinetic-energy subtotal.
v=(m1u1+m2u2)/(m1+m2). Energy decrease is ½[m1m2/(m1+m2)](u1−u2)². It becomes other internal energy; the model does not assign a temperature or claim energy destruction.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
Why does observing that the objects separate after contact fail to prove the collision was elastic?
Continue
Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
Skipping retains experiments and awards no mastery.
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