Learn

Learning preferences

Make learning more comfortable. Changes apply immediately.

Enlarges page content, including diagrams and their labels. You can also use your browser’s zoom.

Choose the colours that are easiest for you to distinguish. Applies to lesson diagrams and lab plots. Labels, shapes, hatching and line patterns also distinguish meanings. Source photographs and raw image brightness stay unchanged; mask-only views are available for image overlays.

ExampleComparisonSample link

Saved in this browser on this device. Preferences are separate from progress backups.

SCIENCE · INVESTIGATE AND EXPLAIN

Reject a floating prediction when required displacement is impossible

A freely floating object in vertical equilibrium has buoyancy equal to weight: ρfluidgVsub=mg. Therefore required submerged volume is m/ρfluid. For a homogeneous solid, the submerged fraction equals its average density divided by fluid density when that ratio is below one. For a hollow sealed object, use total mass and external displaced volume, not the density of its wall material alone.

Learning outcome: Compare payload4 and8 kg at fluid density1000. Record the required versus available displacement before accepting any draft. Then compare densities800 and1200 at fixed payload. Explain the special full-immersion equality case and the stability questions not answered.

Starting recap

Review density and unit conversion, perpendicular force components, static force balance, work-energy, mass conservation and projectile motion.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

A sealed box has base mass4 kg, maximum displacement0.010 m³ and horizontal area0.05 m². In waterρ1000, a4 kg payload gives total8 kg, required displacement0.008 m³ and draft0.16 m. With8 kg payload, total12 kg requires0.012 m³, exceeding capacity; at full immersion buoyancy100 N is less than weight120 N.

Open the experiment

Predict

Can a change of fluid density rescue a floating balance that failed at the same payload?

Experiment

Compare payload4 and8 kg at fluid density1000. Record the required versus available displacement before accepting any draft. Then compare densities800 and1200 at fixed payload. Explain the special full-immersion equality case and the stability questions not answered.

Test a floating equilibrium before accepting its draft

Worked teaching model · synthetic values · Original sealed rigid box base mass4 kg, external maximum displaced volume0.010 m³, horizontal area0.05 m²,height0.20 m,g10. Vertical force balance only; no flooding, stability, capsize or real vessel safety model. Required volume above capacity rejects floating equilibrium.

Reset keeps your prediction, captures and practice history.

Feasibility before draft: required displaced volume 0.008 m³ versus available0.010 m³. The vertical balance fits; rotational stability and real safety are not evaluated.

Calculated evidence ledger — synthetic teaching model
QuantityValueUnit
Total mass8kg
Required displaced volume for balance0.008m³
Maximum available displaced volume0.01m³
Maximum supportable mass in this model10kg
Floating balance feasible11 yes,0 no
Net upward force at full immersion20N
Equilibrium draft0.16m
Fraction of external volume submerged0.8ratio
Accessible plot coordinates
Primary plotted points
coordinatevalue

A vertical force-balanced displacement fits within the supplied external volume; stability is not established.

For vertical equilibrium ρfluidgVsub=mg. If the object is fully immersed first, buoyancy saturates at the full external volume. Do not hide a failed float prediction by clipping the required volume to its maximum. Neutral full immersion has no positive freeboard and is not a safety margin.

A vertical force-balanced displacement fits within the supplied external volume; stability is not established.

For vertical equilibrium ρfluidgVsub=mg. If the object is fully immersed first, buoyancy saturates at the full external volume. Do not hide a failed float prediction by clipping the required volume to its maximum. Neutral full immersion has no positive freeboard and is not a safety margin.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

1. Frame the question

A freely floating object in vertical equilibrium has buoyancy equal to weight: ρfluidgVsub=mg. Therefore required submerged volume is m/ρfluid. For a homogeneous solid, the submerged fraction equals its average density divided by fluid density when that ratio is below one. For a hollow sealed object, use total mass and external displaced volume, not the density of its wall material alone.

2. Build the mechanism

An object cannot displace more fluid than its available immersed external volume. If m/ρfluid exceeds that maximum, the assumed floating equilibrium does not exist in this model. Clipping the calculated submerged fraction to one and calling the result equilibrium hides a real force imbalance. At full immersion, buoyancy saturates while additional payload still increases weight.

For a box of constant horizontal areaA, draft is Vsub/A while the model remains geometrically valid. Adding payload deepens the draft; denser fluid reduces the required displacement. At exact full immersion with average density equal to fluid density, vertical force balance is neutral, with no positive freeboard. It does not imply a stable or safe vessel.

The numerical model checks only vertical balance. Rotational stability, load placement, wave motion, material strength, flooding and leakage require further information. A real vessel can be unsafe even when this simple force balance is possible. Do not interpret a capacity number from the fictional box as an actual loading recommendation.

3. Work an example

A sealed box has base mass4 kg, maximum displacement0.010 m³ and horizontal area0.05 m². In waterρ1000, a4 kg payload gives total8 kg, required displacement0.008 m³ and draft0.16 m. With8 kg payload, total12 kg requires0.012 m³, exceeding capacity; at full immersion buoyancy100 N is less than weight120 N.

4. Predict and investigate

Can a change of fluid density rescue a floating balance that failed at the same payload?

Compare payload4 and8 kg at fluid density1000. Record the required versus available displacement before accepting any draft. Then compare densities800 and1200 at fixed payload. Explain the special full-immersion equality case and the stability questions not answered.

5. Transfer to a new case

Try a new practice case

A floating object has mass6 kg in fluidρ1200 kg/m³. Find its required displaced volume.

This extra practice is not saved and does not award mastery. Record your first answer, explanation and whether you revealed help in the lesson notebook. Use the lesson’s saved question separately.

6. Explain the boundary

Why can a hollow metal object float even though the metal itself is denser than water?

These bounded virtual recipes and supplied observations are not independent measurements, observed laboratory work or equipment safety calculations. No lifting, pressurizing, deep-water activity or physical jet construction is requested. Practical evidence requires an appropriate supervised setting.

Sources

Original explanations, cases and numerical models. Framework checked 30 October 2026: AP Physics 1 CED, topics 8.1; 8.3. Mechanism references: OpenStax University Physics 1, fluids overview, buoyancy, and Bernoulli energy balance. No official assessment items reproduced.

Apply

A box of maximum displaced volume0.010 m³ has total mass12 kg in waterρ1000. Which is correct?

Public practice checks a specific claim. It does not establish independent mastery.

Why can a hollow metal object float even though the metal itself is denser than water?

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

Skipping retains experiments and awards no mastery.

Save a science backup or import one

Science work is stored locally in this browser, separately from mathematics and AI. It does not sync automatically. Use this science-only backup; this checkout's older all-subject export does not include science.

A legacy file is available only when the complete snapshot fits the 36 MB limit. For larger snapshots, prepare a complete file set below; never discard notebooks to make a smaller file.

Matching imported notebook drafts replace their current drafts. Omitted lessons and known first attempts remain. Export your current work first if you want to retain both drafts.

Complete file sets and course backups

A file set can hold more work than one science file. Keep its manifest and every part together. Each file is limited to 36 MB. This format needs this version of LearnAI or a compatible newer version; older versions can use only the legacy single-file backup above.

The set includes every saved science course and global continuation at this moment. Later edits need a new export. A conflicting tab exports its own visible work, which may differ from saved work in another tab.

0 file(s) selected. File order and filenames do not determine identity. Missing, changed or conflicting parts block the entire restore; no good part is applied by itself.

Science storage: loading. No account or remote computation is required.