Connect torque-time evidence to angular-momentum change
External torque transfers angular momentum to or from a chosen system. For a constant torque, angular impulse is τΔt. For a variable pulse it is the signed torque-time area. The angular impulse equals ΔL, with units N m s, equivalent to kg m²/s. This equality is different from the torque-angle work relation.
Learning outcome: Compare pulses (4 N m,1 s) and (2 N m,2 s), then reverse their signs. Reconstruct final angular momentum before checking. Sketch a separate L-time line rising from −2 to +2 over 2 s and then flat: its first average torque is +2 N m and its later torque is zero.
Starting recap
Review axis-specific inertia, force application locations, torque-angle versus torque-time area, energy conservation and system boundaries.
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A triangular external torque pulse peaks at +4 N m and lasts 1 s. Its angular impulse is ½×4×1=2 N m s. A rotor with I=2 kg m² starts at +1 rad/s, so initial L=2 and final L=4 kg m²/s, giving final ω=2 rad/s. A rectangular pulse with the same peak and duration would deliver twice the impulse.
Open the experimentPredict
If peak torque doubles and duration halves, which quantity stays fixed: angular impulse, peak angular acceleration or elapsed time?
Experiment
Compare pulses (4 N m,1 s) and (2 N m,2 s), then reverse their signs. Reconstruct final angular momentum before checking. Sketch a separate L-time line rising from −2 to +2 over 2 s and then flat: its first average torque is +2 N m and its later torque is zero.
Change angular momentum with a triangular torque pulse
Worked teaching model · synthetic values · A rigid rotor with fixed inertia2 kg m² starts at+1 rad/s. External torque rises linearly to its signed peak at half duration and returns to zero. No changing inertia or bearing torque is omitted from the stipulated net pulse.
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| Quantity | Value | Unit |
|---|---|---|
| Signed angular impulse | 2 | N m s |
| Initial angular momentum | 2 | kg m²/s |
| Final angular momentum | 4 | kg m²/s |
| Final angular velocity | 2 | rad/s |
| Average external torque | 2 | N m |
Accessible plot coordinates
| time (s) | net external torque (N m) |
|---|---|
| 0 | 0 |
| 0.5 | 4 |
| 1 | 0 |
Torque-time area gives angular-momentum change, not rotational work.
ΔL=∫τdt is evaluated as triangle area here, without calculus. The slope of an angular-momentum-time graph gives net external torque. Constant inertia converts ΔL into IΔω; changing inertia requires separate endpoint accounting.
Torque-time area gives angular-momentum change, not rotational work.
ΔL=∫τdt is evaluated as triangle area here, without calculus. The slope of an angular-momentum-time graph gives net external torque. Constant inertia converts ΔL into IΔω; changing inertia requires separate endpoint accounting.
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What would you measure to distinguish a small external angular impulse from an error in the inferred inertia?
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