Locate Newton’s third-law partners on different bodies
An interaction produces a pair: the force of A on B and the force of B on A. Their magnitudes are equal and their directions opposite at the same instant. The labels reverse agent and recipient. The pair is not “a force and the motion it causes”; acceleration is a response, not the partner force.
Learning outcome: Compare equal masses and a 3:1 mass ratio. List each interaction force and the acceleration of its recipient. Multiply accelerations by their masses and verify cancellation for the whole system. Explain why this is not cancellation within either individual diagram.
Starting recap
Review signed vectors, components, acceleration, graph slopes and system boundaries. Every force must name its agent and recipient.
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Try
At a selected instant two objects attract with magnitude 12 N. With masses 2 kg and 4 kg, their accelerations are +6 and−3 m/s² along the chosen axis. Their mass-weighted acceleration sum is 2×6+4×(−3)=0, consistent with zero net external horizontal force on the pair.
Open the experimentPredict
If only the right mass doubles while the stipulated interaction force is fixed, which force and which acceleration changes?
Experiment
Compare equal masses and a 3:1 mass ratio. List each interaction force and the acceleration of its recipient. Multiply accelerations by their masses and verify cancellation for the whole system. Explain why this is not cancellation within either individual diagram.
Compare mutual forces and accelerations
Worked teaching model · synthetic values · Two separated objects experience a stipulated mutual attractive interaction of magnitude 12 N at one instant; no other horizontal forces. The model does not assume that the force stays constant as separation changes.
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Interaction arrows are grouped by recipient. For horizontal-only cart/block diagrams, balanced vertical interactions are omitted explicitly; this is a component diagram, not a claim that gravity vanished. For the spring case only the selected spring interaction is drawn; the opposite external holding force is tabulated but omitted from that diagram. For circular cases, the arrow is the required tension, not a claim it is available when the feasibility check fails. All arrows in one view share a scale; scale changes with controls. A zero force has no visible arrow. The force table supplies exact signs and units.
| Recipient | Interaction | Fx (N) | Fy (N) |
|---|---|---|---|
| Left object | Right object on left | 12 | 0 |
| Right object | Left object on right | -12 | 0 |
| Quantity | Value | Unit |
|---|---|---|
| Force on left object | 12 | N |
| Force on right object | -12 | N |
| Left acceleration | 6 | m/s² |
| Right acceleration | -3 | m/s² |
| Net internal force on pair | 0 | N |
Mutual forces have equal magnitudes; accelerations can differ because masses differ.
The pair acts on different objects. Cancel the pair only when forming the combined-system external-force sum, not in either individual free-body diagram.
Mutual forces have equal magnitudes; accelerations can differ because masses differ.
The pair acts on different objects. Cancel the pair only when forming the combined-system external-force sum, not in either individual free-body diagram.
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Name the third-law partner of the track’s upward normal force on a cart. Why is the cart’s downward weight not that partner?
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