Derive velocity addition from transformed differentials
Velocity is a ratio of spatial and time increments in one frame. A transformation must change both increments before the ratio is taken. Frame S′ moves at +β relative to S, and a particle has primed speed u′. The inverse Lorentz map gives dt=γ(dt′+βdx′) and dx=γ(dx′+βdt′).
Learning outcome: Transform the explicit differential pair, calculate the ratio, reverse it and check the interval. Compare counter-moving and light cases before treating a sum as a massive-frame speed.
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At β=0.6 and u′=0.5, dt=1.625 and dx=1.375, so u=11/13≈0.846154 rather than 1.1. Both coordinate-increment intervals are 0.75, and the inverse formula recovers u′=0.5.
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What goes wrong if space is transformed but the original time increment is retained?
Experiment
Transform the explicit differential pair, calculate the ratio, reverse it and check the interval. Compare counter-moving and light cases before treating a sum as a massive-frame speed.
Divide transformed coordinate differentials
Worked teaching model · synthetic values · Original one-dimensional boost with S′ moving+β relative to S, c=1. Unit coordinate increment dt′=1 and dx′=u′. Values u′=±1 are light signals, not massive-frame speeds. No Galilean time assumption.
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Velocity is a ratio of two transformed differentials; retaining the old time increment gives the wrong composition.
Original one-dimensional boost with S′ moving+β relative to S, c=1. Unit coordinate increment dt′=1 and dx′=u′. Values u′=±1 are light signals, not massive-frame speeds. No Galilean time assumption.
| Quantity | Value | Unit |
|---|---|---|
| Transformed coordinate time increment | 1.625000 | reference time |
| Transformed spatial increment | 1.375000 | reference length |
| Composed velocity | 0.8461538 | c |
| Galilean comparison | 1.100000 | c |
| Recovered primed velocity | 0.5000000 | c |
| Increment invariant | 0.7500000 | reference length squared |
| Original increment invariant | 0.7500000 | reference length squared |
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Velocity is a ratio of two transformed differentials; retaining the old time increment gives the wrong composition.
Original one-dimensional boost with S′ moving+β relative to S, c=1. Unit coordinate increment dt′=1 and dx′=u′. Values u′=±1 are light signals, not massive-frame speeds. No Galilean time assumption.
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At β=0.6, use u′=−0.5 and then u′=−1.
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