Reserve fresh temperatures after equal-budget heat-capacity calibration
For a quantum oscillator with levels En=(n+1/2)hbar omega, the geometric partition sum gives mean energy U=hbar omega[1/2+1/(exp(Theta/T)−1)], where Theta=hbar omega/kB. Differentiate at fixed oscillator frequency to obtain C/kB=F(Theta/T), with F(x)=x²exp(x)/(exp(x)−1)². The temperature-independent zero-point energy contributes no heat capacity.
Learning outcome: Derive the energy and heat-capacity law from the geometric sum. Fit both amplitudes at the same temperature, retain two frozen predictions and propagate the direct calibration ratio. Then propose a temperature-dependent gain alternative and the independent measurement needed to test it.
Starting recap
Review finite sums, exponential and logarithmic functions, radial integration measures, first-order coupled equations and mass-energy units. Keep state counts, occupations, calibration records and unused tests distinct.
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Try
Take Theta=300 K and generating amplitude2. The200 K indication is2F(1.5). The quantum fitted amplitude is that reading divided byF(1.5), then predicts2F(3) at100 K and2F(.75) at400 K. The classical family predicts the same calibrated200 K indication at both new temperatures. Both used exactly one calibration datum.
Open the experimentPredict
Why does zero-point energy make no contribution to this heat capacity?
Experiment
Derive the energy and heat-capacity law from the geometric sum. Fit both amplitudes at the same temperature, retain two frozen predictions and propagate the direct calibration ratio. Then propose a temperature-dependent gain alternative and the independent measurement needed to test it.
Give classical and quantum families equal calibration budgets
Worked teaching model · synthetic values · Synthetic heat-capacity response y=A F(Theta/T), F(x)=x² exp(x)/(exp(x)−1)² for independent identical quantum oscillators. Theta is independently supplied, A unknown to analyst. Quantum and classical constant-response families each fit only amplitude at 200 K; 100 and400 K are fresh. A temperature-dependent response gain remains an alternative; no real crystal or unique phonon spectrum is inferred.
Reset keeps your prediction, captures and practice history.
One calibration amplitude per hypothesis
Graph axes rescale independently; read units and values, not screen angles. 1: quantum frozen curve (solid).2: classical frozen constant (dashed).3: fresh low-temperature record (open-circle marked location).4: fresh high-temperature record (open-circle marked location). Joined curves show the supplied model, not additional observations.
Equivalent numerical coordinates for One calibration amplitude per hypothesis
quantum frozen curve
| temperature (K) | heat-capacity response |
|---|---|
| 100 | 0.9925381 |
| 105 | 1.055426 |
| 110 | 1.113765 |
| 115 | 1.167794 |
| 120 | 1.21778 |
| 125 | 1.264004 |
| 130 | 1.306746 |
| 135 | 1.346278 |
| 140 | 1.382859 |
| 145 | 1.416732 |
| 150 | 1.448123 |
| 155 | 1.477241 |
| 160 | 1.504276 |
| 165 | 1.529405 |
| 170 | 1.552788 |
| 175 | 1.574569 |
| 180 | 1.594882 |
| 185 | 1.613846 |
| 190 | 1.631572 |
| 195 | 1.648159 |
| 200 | 1.663697 |
| 205 | 1.678269 |
| 210 | 1.691949 |
| 215 | 1.704806 |
| 220 | 1.716902 |
| 225 | 1.728292 |
| 230 | 1.73903 |
| 235 | 1.749163 |
| 240 | 1.758733 |
| 245 | 1.76778 |
| 250 | 1.77634 |
| 255 | 1.784447 |
| 260 | 1.792132 |
| 265 | 1.799422 |
| 270 | 1.806344 |
| 275 | 1.81292 |
| 280 | 1.819174 |
| 285 | 1.825126 |
| 290 | 1.830794 |
| 295 | 1.836196 |
| 300 | 1.841347 |
| 305 | 1.846264 |
| 310 | 1.850959 |
| 315 | 1.855445 |
| 320 | 1.859735 |
| 325 | 1.86384 |
| 330 | 1.867769 |
| 335 | 1.871534 |
| 340 | 1.875141 |
| 345 | 1.878601 |
| 350 | 1.881921 |
| 355 | 1.885109 |
| 360 | 1.88817 |
| 365 | 1.891112 |
| 370 | 1.893941 |
| 375 | 1.896662 |
| 380 | 1.899281 |
| 385 | 1.901802 |
| 390 | 1.904231 |
| 395 | 1.906572 |
| 400 | 1.908829 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
classical frozen constant
| temperature (K) | heat-capacity response |
|---|---|
| 100 | 1.663697 |
| 105 | 1.663697 |
| 110 | 1.663697 |
| 115 | 1.663697 |
| 120 | 1.663697 |
| 125 | 1.663697 |
| 130 | 1.663697 |
| 135 | 1.663697 |
| 140 | 1.663697 |
| 145 | 1.663697 |
| 150 | 1.663697 |
| 155 | 1.663697 |
| 160 | 1.663697 |
| 165 | 1.663697 |
| 170 | 1.663697 |
| 175 | 1.663697 |
| 180 | 1.663697 |
| 185 | 1.663697 |
| 190 | 1.663697 |
| 195 | 1.663697 |
| 200 | 1.663697 |
| 205 | 1.663697 |
| 210 | 1.663697 |
| 215 | 1.663697 |
| 220 | 1.663697 |
| 225 | 1.663697 |
| 230 | 1.663697 |
| 235 | 1.663697 |
| 240 | 1.663697 |
| 245 | 1.663697 |
| 250 | 1.663697 |
| 255 | 1.663697 |
| 260 | 1.663697 |
| 265 | 1.663697 |
| 270 | 1.663697 |
| 275 | 1.663697 |
| 280 | 1.663697 |
| 285 | 1.663697 |
| 290 | 1.663697 |
| 295 | 1.663697 |
| 300 | 1.663697 |
| 305 | 1.663697 |
| 310 | 1.663697 |
| 315 | 1.663697 |
| 320 | 1.663697 |
| 325 | 1.663697 |
| 330 | 1.663697 |
| 335 | 1.663697 |
| 340 | 1.663697 |
| 345 | 1.663697 |
| 350 | 1.663697 |
| 355 | 1.663697 |
| 360 | 1.663697 |
| 365 | 1.663697 |
| 370 | 1.663697 |
| 375 | 1.663697 |
| 380 | 1.663697 |
| 385 | 1.663697 |
| 390 | 1.663697 |
| 395 | 1.663697 |
| 400 | 1.663697 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
fresh low-temperature record
| temperature (K) | heat-capacity response |
|---|---|
| 100 | 0.9925381 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
fresh high-temperature record
| temperature (K) | heat-capacity response |
|---|---|
| 400 | 1.908829 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
| Quantity | Value | Unit |
|---|---|---|
| Single calibration indication at 200 K | 1.663697 | response units |
| Quantum frozen prediction at 100 K | 0.9925381 | response units |
| Classical frozen prediction at 100 K | 1.663697 | response units |
| Fresh indication at 100 K | 0.9925381 | response units |
| Quantum frozen prediction at 400 K | 1.908829 | response units |
| Classical frozen prediction at 400 K | 1.663697 | response units |
| Fresh indication at 400 K | 1.908829 | response units |
| Quantum100 prediction calibration bound | 0.005965858 | response units |
| Classical prediction calibration bound | 0.01 | response units |
A quantized oscillator suppresses low-temperature heat capacity; equal fitting budgets make the unused temperatures meaningful tests.
For levels En=(n+1/2)hbar omega, sum the geometric partition series to obtain U=hbar omega[1/2+1/(exp(Theta/T)−1)]. Differentiation gives C/kB=(Theta/T)²exp(Theta/T)/(exp(Theta/T)−1)². Temperature-independent zero-point energy contributes no heat capacity. With independently fixed Theta, each family fits one scale at 200 K. Multiply the calibration hard error by the direct positive prediction ratio, then add fresh error separately. A freely varying temperature-dependent gain could mimic the curve and requires independent calibration.
Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.
A quantized oscillator suppresses low-temperature heat capacity; equal fitting budgets make the unused temperatures meaningful tests.
For levels En=(n+1/2)hbar omega, sum the geometric partition series to obtain U=hbar omega[1/2+1/(exp(Theta/T)−1)]. Differentiation gives C/kB=(Theta/T)²exp(Theta/T)/(exp(Theta/T)−1)². Temperature-independent zero-point energy contributes no heat capacity. With independently fixed Theta, each family fits one scale at 200 K. Multiply the calibration hard error by the direct positive prediction ratio, then add fresh error separately. A freely varying temperature-dependent gain could mimic the curve and requires independent calibration.
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