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SCIENCE · INVESTIGATE AND EXPLAIN

Enumerate allowed labels before making a degeneracy claim

For a one-electron central Coulomb problem, a principal quantum number n is a positive integer. Orbital angular label l takes values 0 through n−1. For each l, magnetic projection label m takes integer values −l through +l. A proposed label outside this set is rejected rather than rounded or clipped into a different state.

Learning outcome: Create a full label table for two shells and sum the magnetic labels rather than memorizing the total. Test an invalid l and identify which selected-state quantities must be withheld. Compare angular magnitude and projection without drawing a classical trajectory.

Starting recap

Review finite sums, exponential and logarithmic functions, radial integration measures, first-order coupled equations and mass-energy units. Keep state counts, occupations, calibration records and unused tests distinct.

All lessons are open directly. Your saved experiments remain when you leave and return.

Try

For n=3, the allowed l values 0,1,2 contribute 1+3+5=9 spatial states and 18 spin-orbitals. For l=2, the five m labels run −2 through +2, magnitude is sqrt(6)hbar and maximum absolute projection is 2hbar. The proposed pair n=2,l=2 is invalid.

Open the experiment

Predict

For n=2, which proposed orbital label is invalid?

Experiment

Create a full label table for two shells and sum the magnetic labels rather than memorizing the total. Test an invalid l and identify which selected-state quantities must be withheld. Compare angular magnitude and projection without drawing a classical trajectory.

Count labels without drawing a classical orbit

Worked teaching model · synthetic values · One-electron orbital labels have integer l from zero through n−1 and m from −l through l. Spin doubles one-electron state count. A proposed invalid l is rejected, not clipped. Degeneracy here assumes the ideal spin-independent Coulomb Hamiltonian.

Reset keeps your prediction, captures and practice history.

Allowed projections for one orbital label

Lz divided by hbarm label-222-2

Graph axes rescale independently; read units and values, not screen angles. 1: m = -2 (open-circle marked location).2: m = -1 (open-circle marked location).3: m = 0 (open-circle marked location).4: m = 1 (open-circle marked location).5: m = 2 (open-circle marked location). Joined curves show the supplied model, not additional observations.

Equivalent numerical coordinates for Allowed projections for one orbital label

m = -2

m labelLz divided by hbar
-2-2

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

m = -1

m labelLz divided by hbar
-1-1

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

m = 0

m labelLz divided by hbar
00

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

m = 1

m labelLz divided by hbar
11

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

m = 2

m labelLz divided by hbar
22

At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.

Calculated quantities under the declared measurement model
QuantityValueUnit
Proposed orbital label valid1flag
Orbital states in entire principal shell9integer
One-electron states including spin18integer
Magnetic labels for selected orbital label5integer
Orbital angular momentum magnitude divided by hbar2.44949ratio
Maximum absolute projection divided by hbar2ratio

Allowed projections count distinct eigenstates, not classical paths.

For each l=0,..., n−1 there are 2l+1 magnetic labels. Summing consecutive odd integers gives n² spatial states; two electron spin projections give2n² spin-orbitals. Orbital magnitude sqrt[l(l+1)]hbar differs from maximum projection l hbar. The ideal degeneracy and labels do not assert classical simultaneous angular components or multi-electron energy equality.

Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.

Allowed projections count distinct eigenstates, not classical paths.

For each l=0,..., n−1 there are 2l+1 magnetic labels. Summing consecutive odd integers gives n² spatial states; two electron spin projections give2n² spin-orbitals. Orbital magnitude sqrt[l(l+1)]hbar differs from maximum projection l hbar. The ideal degeneracy and labels do not assert classical simultaneous angular components or multi-electron energy equality.

Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.

Understand

Define the state and evidence

For a one-electron central Coulomb problem, a principal quantum number n is a positive integer. Orbital angular label l takes values 0 through n−1. For each l, magnetic projection label m takes integer values −l through +l. A proposed label outside this set is rejected rather than rounded or clipped into a different state.

Derive the quantitative relation

The number of spatial states in a principal shell is the sum of 2l+1 over l=0 through n−1. The odd-number sum equals n². Electron spin adds two projection labels, so there are 2n² one-electron spin-orbitals in this ideal shell. This is a state count, not a statement that all those states are occupied in a given atom.

Test a changed model or boundary

Orbital angular momentum magnitude is sqrt[l(l+1)]hbar, while an allowed z projection is m hbar. The largest absolute projection l hbar is smaller than the magnitude for nonzero l. These eigenvalue relations do not describe a tiny classical vector following a definite orbit with simultaneously specified Cartesian components.

Limit the inference

Ideal Coulomb energy depends on n, so these spatial states are degenerate before spin-dependent and other corrections. In many-electron atoms, interactions and screening alter the ordering and degeneracies. Exclusion applies to a complete one-electron state including spin, not to the orbital label l alone.

Worked original case

For n=3, the allowed l values 0,1,2 contribute 1+3+5=9 spatial states and 18 spin-orbitals. For l=2, the five m labels run −2 through +2, magnitude is sqrt(6)hbar and maximum absolute projection is 2hbar. The proposed pair n=2,l=2 is invalid.

Investigation

Create a full label table for two shells and sum the magnetic labels rather than memorizing the total. Test an invalid l and identify which selected-state quantities must be withheld. Compare angular magnitude and projection without drawing a classical trajectory.

Changed-case practice

Try the changed case before feedback

How many one-electron spin-orbitals are in the ideal n=4 shell?

This practice is public and unsaved. A matching number does not verify understanding. Retain your explanation, assumptions and changed-case evidence in the separate course workspace.

Sources and boundaries

Original derivations and virtual evidence checked 31 October 2026 against the primary explanation. All questions and numerical packets are original. Supplied theoretical distributions and synthetic records are not actual laboratory measurements. No nuclear, electrical, heating, beam or material-handling procedures are requested. Retain first reasoning, actual criterion critique, revision and a separately assigned unfamiliar task in the course evidence workspace; public keys do not authenticate mastery.

Apply

For n=2, which proposed orbital label is invalid?

Public practice checks a specific claim. It does not establish independent mastery.

Which independent calibration, state-counting or physical-domain premise is needed, and which fresh observation could challenge the inference?

Continue

Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.

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