Use probability moments rather than reading off a density peak
Consider a supplied position density per unit u=x/L: f(u)=(p+1)(p+2)u^p(1−u) for 0≤u≤1, with positive integer p. Integrating u^p−u^(p+1) gives 1/[(p+1)(p+2)], which proves normalization. Physical position density is f(x/L)/L, not f alone.
Learning outcome: Derive normalization and both moments for two p values. Predict the direction of the mean-mode difference before revealing the graph. Compute one interval probability independently and explain what phase information remains absent.
Starting recap
Review definite integrals, complex amplitudes, probability moments, elementary differential equations and energy-momentum units. State boundary and normalization conditions, and distinguish calibration from unused validation.
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Try
For p=2, mean(u)=3/5, mean(u²)=2/5 and variance=1/25. The mode is 2/3, farther right than the mean. Probability to the left of u=1/2 is 4(1/2)³−3(1/2)⁴=5/16. None of these numbers is a classical trajectory.
Open the experimentPredict
For p=2, which value is the mean position divided by L?
Experiment
Derive normalization and both moments for two p values. Predict the direction of the mean-mode difference before revealing the graph. Compute one interval probability independently and explain what phase information remains absent.
Integrate moments of an asymmetric density
Worked teaching model · synthetic values · Normalized position density per unit u is (p+1)(p+2)u^p(1−u),0≤u≤1, L1 nm. This is a supplied probability state, not a claim of one particular Hamiltonian or classical trajectory. Integrate moments rather than identifying mean with the density maximum.
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An asymmetric normalized density
Graph axes rescale independently; read units and values, not screen angles. 1: supplied beta-family state (solid). Joined curves show the supplied model, not additional observations.
Equivalent numerical coordinates for An asymmetric normalized density
supplied beta-family state
| u = x/L | density per unit u |
|---|---|
| 0 | 0 |
| 0.01666667 | 0.003277778 |
| 0.03333333 | 0.01288889 |
| 0.05 | 0.0285 |
| 0.06666667 | 0.04977778 |
| 0.08333333 | 0.07638889 |
| 0.1 | 0.108 |
| 0.1166667 | 0.1442778 |
| 0.1333333 | 0.1848889 |
| 0.15 | 0.2295 |
| 0.1666667 | 0.2777778 |
| 0.1833333 | 0.3293889 |
| 0.2 | 0.384 |
| 0.2166667 | 0.4412778 |
| 0.2333333 | 0.5008889 |
| 0.25 | 0.5625 |
| 0.2666667 | 0.6257778 |
| 0.2833333 | 0.6903889 |
| 0.3 | 0.756 |
| 0.3166667 | 0.8222778 |
| 0.3333333 | 0.8888889 |
| 0.35 | 0.9555 |
| 0.3666667 | 1.021778 |
| 0.3833333 | 1.087389 |
| 0.4 | 1.152 |
| 0.4166667 | 1.215278 |
| 0.4333333 | 1.276889 |
| 0.45 | 1.3365 |
| 0.4666667 | 1.393778 |
| 0.4833333 | 1.448389 |
| 0.5 | 1.5 |
| 0.5166667 | 1.548278 |
| 0.5333333 | 1.592889 |
| 0.55 | 1.6335 |
| 0.5666667 | 1.669778 |
| 0.5833333 | 1.701389 |
| 0.6 | 1.728 |
| 0.6166667 | 1.749278 |
| 0.6333333 | 1.764889 |
| 0.65 | 1.7745 |
| 0.6666667 | 1.777778 |
| 0.6833333 | 1.774389 |
| 0.7 | 1.764 |
| 0.7166667 | 1.746278 |
| 0.7333333 | 1.720889 |
| 0.75 | 1.6875 |
| 0.7666667 | 1.645778 |
| 0.7833333 | 1.595389 |
| 0.8 | 1.536 |
| 0.8166667 | 1.467278 |
| 0.8333333 | 1.388889 |
| 0.85 | 1.3005 |
| 0.8666667 | 1.201778 |
| 0.8833333 | 1.092389 |
| 0.9 | 0.972 |
| 0.9166667 | 0.8402778 |
| 0.9333333 | 0.6968889 |
| 0.95 | 0.5415 |
| 0.9666667 | 0.3737778 |
| 0.9833333 | 0.1933889 |
| 1 | 0 |
At most 82 representative computed coordinates including endpoints; the plotted curve can use a finer grid. A table of a revealed generator is not independent measurement evidence.
| Quantity | Value | Unit |
|---|---|---|
| Mean position divided by length | 0.6 | ratio |
| Second moment divided by length squared | 0.4 | ratio |
| Position variance divided by length squared | 0.04 | ratio |
| Most likely position divided by length | 0.6666667 | ratio |
| Probability left of chosen position | 0.3125 | ratio |
Expectation, density mode and interval probability answer different questions.
Integrating u^p(1−u) gives1/[(p+1)(p+2)]. The first two normalized moments are(p+1)/(p+3) and(p+1)(p+2)/[(p+3)(p+4)]. Differentiating the density places its interior mode at p/(p+1). Variance is second moment minus square of mean, not square of mode. No individual trajectory follows from these ensemble moments.
Predict before inspecting the values. Save contrasting records with assumptions and one alternative explanation. This virtual display does not certify practical measurement technique.
Expectation, density mode and interval probability answer different questions.
Integrating u^p(1−u) gives1/[(p+1)(p+2)]. The first two normalized moments are(p+1)/(p+3) and(p+1)(p+2)/[(p+3)(p+4)]. Differentiating the density places its interior mode at p/(p+1). Variance is second moment minus square of mean, not square of mode. No individual trajectory follows from these ensemble moments.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
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