Distinguish a transient peak from a regulated steady state
Negative feedback occurs when a response contributes to reducing its own upstream drive or production. A delayed inhibitor can allow an initial rise before suppressing further accumulation. Positive feedback instead reinforces a change and can help create switch-like transitions; neither label alone predicts an entire time course without the network and rates.
Learning outcome: Compare g=0 and g=2 at input 3. Retain peak and late response separately. Solve the steady equation before reading the final ledger, then explain one alternative mechanism that could generate a qualitatively similar decline.
Starting recap
Separate receptor binding, downstream response and checkpoint passage. Declare DNA-counting boundaries, population age assumptions and the evidence needed to distinguish mechanisms.
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Try
For S=3 and g=2, the steady equation is 2x²+x−3=0. Its nonnegative solution is x=1, compared with x=3 without feedback. A declining trajectory toward one is therefore regulation, not return to the zero baseline.
Open the experimentPredict
Does a falling response after an initial peak establish perfect adaptation if the input remains on?
Experiment
Compare g=0 and g=2 at input 3. Retain peak and late response separately. Solve the steady equation before reading the final ledger, then explain one alternative mechanism that could generate a qualitatively similar decline.
Compare transient response and regulated steady state
Worked teaching model · synthetic values · Supplied dimensionless model dx/dt=S/(1+g y)−x, dy/dt=0.3(x−y), starting x=y=0. Explicit Euler step 0.02 to time 20. Negative feedback limits response but does not produce perfect adaptation to baseline. Not fitted cellular kinetics.
Reset keeps your prediction, captures and practice history.
Feedback changes both the transient and the sustained response.
The delayed inhibitor reduces gain, but nonzero input still gives a nonzero steady response. A returning trace does not by itself establish perfect adaptation or identify a molecular inhibitor.
Solid: Selected feedback. Dashed: No feedback. Axes rescale to the current range; use labeled values rather than comparing graph heights across settings.
| Model time | Selected feedback (Response x) | No feedback (Response x) |
|---|---|---|
| 0 | 0.000000 | 0.000000 |
| 0.5 | 1.120721 | 1.180408 |
| 1 | 1.559596 | 1.896362 |
| 1.5 | 1.630102 | 2.330610 |
| 2 | 1.555884 | 2.593994 |
| 2.5 | 1.442322 | 2.753745 |
| 3 | 1.332174 | 2.850639 |
| 3.5 | 1.239905 | 2.909408 |
| 4 | 1.168026 | 2.945053 |
| 4.5 | 1.114470 | 2.966673 |
| 5 | 1.075825 | 2.979786 |
| 5.5 | 1.048666 | 2.987740 |
| 6 | 1.030041 | 2.992564 |
| 6.5 | 1.017587 | 2.995490 |
| 7 | 1.009492 | 2.997264 |
| 7.5 | 1.004409 | 2.998341 |
| 8 | 1.001360 | 2.998994 |
| 8.5 | 0.9996480 | 2.999390 |
| 9 | 0.9987894 | 2.999630 |
| 9.5 | 0.9984536 | 2.999775 |
| 10 | 0.9984208 | 2.999864 |
| 10.5 | 0.9985487 | 2.999917 |
| 11 | 0.9987486 | 2.999950 |
| 11.5 | 0.9989677 | 2.999970 |
| 12 | 0.9991765 | 2.999982 |
| 12.5 | 0.9993609 | 2.999989 |
| 13 | 0.9995156 | 2.999993 |
| 13.5 | 0.9996407 | 2.999996 |
| 14 | 0.9997388 | 2.999998 |
| 14.5 | 0.9998138 | 2.999998 |
| 15 | 0.9998700 | 2.999999 |
| 15.5 | 0.9999112 | 2.999999 |
| 16 | 0.9999408 | 3.000000 |
| 16.5 | 0.9999617 | 3.000000 |
| 17 | 0.9999760 | 3.000000 |
| 17.5 | 0.9999857 | 3.000000 |
| 18 | 0.9999921 | 3.000000 |
| 18.5 | 0.9999961 | 3.000000 |
| 19 | 0.9999986 | 3.000000 |
| 19.5 | 1.000000 | 3.000000 |
| 20 | 1.000001 | 3.000000 |
| Quantity | Value | Unit |
|---|---|---|
| Exact sustained-input steady response | 1 | relative units |
| No-feedback steady response | 3 | relative units |
| Response at displayed time 20 | 1.000001 | relative units |
| Peak sampled response | 1.630102 | relative units |
Retain prior predictions, settings and quantities in the notebook. These are original supplied/calculated comparisons, not physical specimen observations or laboratory participation.
Feedback changes both the transient and the sustained response.
The delayed inhibitor reduces gain, but nonzero input still gives a nonzero steady response. A returning trace does not by itself establish perfect adaptation or identify a molecular inhibitor.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
A supplied feedback model has steady equation 3x²+x−4=0. Find its nonnegative steady response, and compare with the no-feedback response at input 4.
Continue
Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
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