Test a constant-resistance claim against curved data
A resistance inferred from one voltage-current pair is not a test that resistance is constant. To test an ohmic model, collect several current and voltage pairs while controlling relevant conditions. Here the supplied graph places voltage on the vertical axis and current on the horizontal axis, so a straight-line slope has units V/A=Ω. Reversing the axes would make the slope conductance instead.
Learning outcome: Compare ohmic and nonlinear packets at zero offset. Record fitted slope, residual size and two interval slopes. Then add +0.20 V to the nonlinear packet and distinguish the shifted intercept from unchanged curvature.
Starting recap
Distinguish charge flow from energy transfer. Identify nodes, choose consistent current/voltage signs and state source and initial conditions before applying algebra.
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Try
Without measurement errors, the nonlinear model gives 1.0125 V at 0.05 A and 4.8 V at 0.20 A. The ratios V/I are 20.25 Ω and 24 Ω. A +0.10 V zero offset changes both readings but cannot remove the underlying change in interval slope.
Open the experimentPredict
Will changing the voltage offset remove the high-current curvature from the nonlinear packet?
Experiment
Compare ohmic and nonlinear packets at zero offset. Record fitted slope, residual size and two interval slopes. Then add +0.20 V to the nonlinear packet and distinguish the shifted intercept from unchanged curvature.
Challenge a resistance inference with nonlinear evidence
Worked teaching model · synthetic values · Original synthetic V(I) data at currents 0, 0.05, 0.10, 0.15 and 0.20 A. Ohmic V=20I; nonlinear V=20I+100I³, with fixed small voltage errors [0,0.01,−0.01,0.01,−0.01] V. A common voltage offset is separate from curvature. No actual bulb or material identification is implied.
Reset keeps your prediction, captures and practice history.
Circuit connections: A controlled current drives one hypothetical device; voltage is measured across that device, with a stipulated independent offset.
Axes rescale with settings; compare numerical values, not screen angles or apparent lengths. Solid/points show the selected model relationship or observations; the dashed comparison is explained below.
| Quantity | Value | Unit |
|---|---|---|
| Fitted voltage-current slope | 23.81 | Ω |
| Fitted intercept | -0.031 | V |
| Largest linear-fit residual | 0.16 | V |
| Low interval slope | 20.45 | Ω |
| High interval slope | 28.85 | Ω |
Accessible plot coordinates
| current (A) | measured voltage (V) |
|---|---|
| 0 | 0.1 |
| 0.05 | 1.1225 |
| 0.1 | 2.19 |
| 0.15 | 3.4475 |
| 0.2 | 4.89 |
| current (A) | measured voltage (V) |
|---|---|
| 0 | -0.031 |
| 0.05 | 1.1595 |
| 0.1 | 2.35 |
| 0.15 | 3.5405 |
| 0.2 | 4.731 |
An intercept can absorb a common offset, but systematic curvature challenges a constant-resistance model.
A fit returns a number even when a linear model is inappropriate. Inspect residual pattern and interval slopes. V/I, a fitted slope, and a local interval slope need not agree for a nonlinear element. The polynomial is a stipulated response, not a microscopic heating law.
An intercept can absorb a common offset, but systematic curvature challenges a constant-resistance model.
A fit returns a number even when a linear model is inappropriate. Inspect residual pattern and interval slopes. V/I, a fitted slope, and a local interval slope need not agree for a nonlinear element. The polynomial is a stipulated response, not a microscopic heating law.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
Why would a single numerical resistance or a high-quality-looking line be insufficient evidence for constant resistance?
Continue
Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
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