Balance crossed-field forces without removing the fields
An electric field exerts force qE regardless of whether the particle is instantaneously moving. A magnetic field exerts q times the velocity-cross-field direction and has a speed dependence. These forces can oppose one another, but cancellation is a condition on the complete setup, not evidence that either field is absent.
Learning outcome: Capture speeds 2, 3 and 4×10⁵ m/s for positive charge, then repeat for negative charge. Retain both force components and their sum. Finally test neutral charge and explain why it defeats a charge-identification claim.
Starting recap
State coordinate axes, charge/current signs and oriented surface normals. Distinguish field from force, magnetic flux from its rate of change, and microscopic magnetic work from a full mechanical/electrical energy ledger.
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Try
With E=6.0×10⁴ N/C and B=0.20 T, selected speed is 3.0×10⁵ m/s. For q=+1.60×10⁻¹⁹ C at that speed, each opposing force has magnitude 9.6×10⁻¹⁵ N. The net force is zero, although neither individual force is zero.
Open the experimentPredict
If charge sign reverses, must selected speed reverse or change magnitude?
Experiment
Capture speeds 2, 3 and 4×10⁵ m/s for positive charge, then repeat for negative charge. Retain both force components and their sum. Finally test neutral charge and explain why it defeats a charge-identification claim.
Balance electric and magnetic forces without erasing either
Worked teaching model · synthetic values · Uniform E=6.0×10⁴ N/C along +y and B=0.20 T along +z. Charge magnitude 1.60×10⁻¹⁹ C. Ledger gives entry forces only; a nonselected particle changes velocity later, so no constant-acceleration trajectory is inferred from this entry force.
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Axes rescale with settings; compare numerical values, not screen lengths across different settings. Orbit x/y use the same spatial scale within one plot. Solid/points show the selected model relationship or observations; the dashed comparison is explained below.
| Quantity | Value | Unit |
|---|---|---|
| Electric y force | 9.6e-15 | N |
| Magnetic y force | -9.6e-15 | N |
| Net entry y force | 0 | N |
| Selected nonzero-charge speed | 300000 | m/s |
Accessible plot coordinates
| entry speed (×10⁵ m/s) | net entry y force (fN) |
|---|---|
| 1 | 6.4 |
| 1.25 | 5.6 |
| 1.5 | 4.8 |
| 1.75 | 4 |
| 2 | 3.2 |
| 2.25 | 2.4 |
| 2.5 | 1.6 |
| 2.75 | 0.8 |
| 3 | 0 |
| 3.25 | -0.8 |
| 3.5 | -1.6 |
| 3.75 | -2.4 |
| 4 | -3.2 |
| 4.25 | -4 |
| 4.5 | -4.8 |
| 4.75 | -5.6 |
| 5 | -6.4 |
At v=E/B, electric and magnetic forces cancel for either nonzero charge sign.
Cancellation does not mean either field or either force vanishes. Reversing charge reverses both forces, preserving the selected speed. Away from selection this is an instantaneous entry-force analysis, not a computed trajectory or a particle-species identification.
At v=E/B, electric and magnetic forces cancel for either nonzero charge sign.
Cancellation does not mean either field or either force vanishes. Reversing charge reverses both forces, preserving the selected speed. Away from selection this is an instantaneous entry-force analysis, not a computed trajectory or a particle-species identification.
Captures preserve recipes and replay their calculated results. They are synthetic model evidence, not physical measurements.
Understand
Apply
Public practice checks a specific claim. It does not establish independent mastery.
Why cannot one use the plotted off-selection entry force as an exact constant force for a full trajectory?
Continue
Completion requires a saved prediction, at least one capture and a reflection. Presence checks do not grade your reasoning.
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